0.00/0.04 % Problem : theBenchmark.p : TPTP v0.0.0. Released v0.0.0. 0.00/0.04 % Command : twee %s --tstp --casc --quiet --conditional-encoding if --smaller --drop-non-horn 0.03/0.24 % Computer : n187.star.cs.uiowa.edu 0.03/0.24 % Model : x86_64 x86_64 0.03/0.24 % CPU : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz 0.03/0.24 % Memory : 32218.625MB 0.03/0.24 % OS : Linux 3.10.0-693.2.2.el7.x86_64 0.03/0.24 % CPULimit : 300 0.03/0.24 % DateTime : Sat Jul 14 04:26:40 CDT 2018 0.03/0.24 % CPUTime : 95.72/95.92 % SZS status Theorem 95.72/95.92 95.72/95.92 % SZS output start Proof 95.72/95.92 Take the following subset of the input axioms: 95.72/95.93 fof(ax2_4304, axiom, 95.72/95.93 genls(c_tptpcol_16_130924, c_tptpcol_15_130923)). 95.72/95.93 fof(query172, conjecture, 95.72/95.93 genls(c_tptpcol_16_130924, c_tptpcol_15_130923) 95.72/95.93 <= mtvisible(f_contentmtofcdafromeventfn(f_urlreferentfn(f_urlfn(s_http_wwwarthritis_symptomcoma_cbursitishtm)), 95.72/95.93 c_translation_0_885))). 95.72/95.93 95.72/95.93 Now clausify the problem and encode Horn clauses using encoding 3 of 95.72/95.93 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf. 95.72/95.93 We repeatedly replace C & s=t => u=v by the two clauses: 95.72/95.93 $$fresh(y, y, x1...xn) = u 95.72/95.93 C => $$fresh(s, t, x1...xn) = v 95.72/95.93 where $$fresh is a fresh function symbol and x1..xn are the free 95.72/95.93 variables of u and v. 95.72/95.93 A predicate p(X) is encoded as p(X)=$$true (this is sound, because the 95.72/95.93 input problem has no model of domain size 1). 95.72/95.93 95.72/95.93 The encoding turns the above axioms into the following unit equations and goals: 95.72/95.93 95.72/95.93 Axiom 6613 (ax2_4304): genls(c_tptpcol_16_130924, c_tptpcol_15_130923) = $$true2. 95.72/95.93 95.72/95.93 Goal 1 (query172_1): genls(c_tptpcol_16_130924, c_tptpcol_15_130923) = $$true2. 95.72/95.93 Proof: 95.72/95.93 genls(c_tptpcol_16_130924, c_tptpcol_15_130923) 95.72/95.93 = { by axiom 6613 (ax2_4304) } 95.72/95.93 $$true2 95.72/95.93 % SZS output end Proof 95.72/95.93 95.72/95.93 RESULT: Theorem (the conjecture is true). 95.92/96.14 EOF