0.00/0.04	% Problem    : theBenchmark.p : TPTP v0.0.0. Released v0.0.0.
0.00/0.04	% Command    : twee %s --tstp --casc --quiet --conditional-encoding if --smaller --drop-non-horn
0.03/0.24	% Computer   : n024.star.cs.uiowa.edu
0.03/0.24	% Model      : x86_64 x86_64
0.03/0.24	% CPU        : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
0.03/0.24	% Memory     : 32218.625MB
0.03/0.24	% OS         : Linux 3.10.0-693.2.2.el7.x86_64
0.03/0.24	% CPULimit   : 300
0.03/0.24	% DateTime   : Sat Jul 14 04:32:55 CDT 2018
0.03/0.24	% CPUTime    : 
94.85/95.12	% SZS status Theorem
94.85/95.12	
94.85/95.12	% SZS output start Proof
94.85/95.12	Take the following subset of the input axioms:
94.85/95.13	  fof(ax2_1215, axiom,
94.85/95.13	      genls(c_tptpcol_16_30972, c_tptpcol_15_30970)).
94.85/95.13	  fof(query143, conjecture,
94.85/95.13	      mtvisible(c_tptp_member2862_mt)
94.85/95.13	        => genls(c_tptpcol_16_30972, c_tptpcol_15_30970)).
94.85/95.13	
94.85/95.13	Now clausify the problem and encode Horn clauses using encoding 3 of
94.85/95.13	http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
94.85/95.13	We repeatedly replace C & s=t => u=v by the two clauses:
94.85/95.13	  $$fresh(y, y, x1...xn) = u
94.85/95.13	  C => $$fresh(s, t, x1...xn) = v
94.85/95.13	where $$fresh is a fresh function symbol and x1..xn are the free
94.85/95.13	variables of u and v.
94.85/95.13	A predicate p(X) is encoded as p(X)=$$true (this is sound, because the
94.85/95.13	input problem has no model of domain size 1).
94.85/95.13	
94.85/95.13	The encoding turns the above axioms into the following unit equations and goals:
94.85/95.13	
94.85/95.13	Axiom 7558 (ax2_1215): genls(c_tptpcol_16_30972, c_tptpcol_15_30970) = $$true2.
94.85/95.13	
94.85/95.13	Goal 1 (query143_1): genls(c_tptpcol_16_30972, c_tptpcol_15_30970) = $$true2.
94.85/95.13	Proof:
94.85/95.13	  genls(c_tptpcol_16_30972, c_tptpcol_15_30970)
94.85/95.13	= { by axiom 7558 (ax2_1215) }
94.85/95.13	  $$true2
94.85/95.13	% SZS output end Proof
94.85/95.13	
94.85/95.13	RESULT: Theorem (the conjecture is true).
95.13/95.33	EOF