0.12/0.12 % Problem : theBenchmark.p : TPTP v0.0.0. Released v0.0.0. 0.12/0.13 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s 0.13/0.34 % Computer : n002.cluster.edu 0.13/0.34 % Model : x86_64 x86_64 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz 0.13/0.34 % Memory : 8042.1875MB 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 0.13/0.34 % CPULimit : 1200 0.13/0.34 % WCLimit : 120 0.13/0.34 % DateTime : Tue Jul 13 11:56:48 EDT 2021 0.13/0.34 % CPUTime : 0.20/0.37 # No SInE strategy applied 0.20/0.37 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_S04AN 0.20/0.37 # and selection function SelectComplexExceptUniqMaxHorn. 0.20/0.37 # 0.20/0.37 # Presaturation interreduction done 0.20/0.37 # Number of axioms: 2 Number of unprocessed: 2 0.20/0.37 # Tableaux proof search. 0.20/0.37 # APR header successfully linked. 0.20/0.37 # Hello from C++ 0.48/0.63 # The folding up rule is enabled... 0.48/0.63 # Local unification is enabled... 0.48/0.63 # Any saturation attempts will use folding labels... 0.48/0.63 # 2 beginning clauses after preprocessing and clausification 0.48/0.63 # Creating start rules for all 1 conjectures. 0.48/0.63 # There are 1 start rule candidates: 0.48/0.63 # Found 2 unit axioms. 0.48/0.63 # 1 start rule tableaux created. 0.48/0.63 # 0 extension rule candidate clauses 0.48/0.63 # 2 unit axiom clauses 0.48/0.63 0.48/0.63 # Requested 8, 32 cores available to the main process. 0.48/0.63 # There are not enough tableaux to fork, creating more from the initial 1 0.48/0.63 # Creating equality axioms 0.48/0.63 # Ran out of tableaux, making start rules for all clauses 0.48/0.65 # There were 1 total branch saturation attempts. 0.48/0.65 # There were 0 of these attempts blocked. 0.48/0.65 # There were 0 deferred branch saturation attempts. 0.48/0.65 # There were 0 free duplicated saturations. 0.48/0.65 # There were 1 total successful branch saturations. 0.48/0.65 # There were 0 successful branch saturations in interreduction. 0.48/0.65 # There were 0 successful branch saturations on the branch. 0.48/0.65 # There were 1 successful branch saturations after the branch. 0.48/0.65 # SZS status Unsatisfiable for /export/starexec/sandbox2/benchmark/theBenchmark.p 0.48/0.65 # SZS output start for /export/starexec/sandbox2/benchmark/theBenchmark.p 0.48/0.65 # Begin clausification derivation 0.48/0.65 0.48/0.65 # End clausification derivation 0.48/0.65 # Begin listing active clauses obtained from FOF to CNF conversion 0.48/0.65 cnf(i_0_4, plain, (double_divide(double_divide(X1,inverse(double_divide(X2,X3))),double_divide(inverse(X2),inverse(double_divide(X4,double_divide(X1,X4)))))=X3)). 0.48/0.65 cnf(i_0_6, negated_conjecture, (inverse(double_divide(inverse(double_divide(c3,b3)),a3))!=inverse(double_divide(c3,inverse(double_divide(b3,a3)))))). 0.48/0.65 cnf(i_0_8, plain, (X5=X5)). 0.48/0.65 # End listing active clauses. There is an equivalent clause to each of these in the clausification! 0.48/0.65 # Begin printing tableau 0.48/0.65 # Found 5 steps 0.48/0.65 cnf(i_0_4, plain, (double_divide(double_divide(X13,inverse(double_divide(X14,double_divide(c3,inverse(double_divide(b3,a3)))))),double_divide(inverse(X14),inverse(double_divide(X15,double_divide(X13,X15)))))=double_divide(c3,inverse(double_divide(b3,a3)))), inference(start_rule)). 0.48/0.65 cnf(i_0_14, plain, (double_divide(double_divide(X13,inverse(double_divide(X14,double_divide(c3,inverse(double_divide(b3,a3)))))),double_divide(inverse(X14),inverse(double_divide(X15,double_divide(X13,X15)))))=double_divide(c3,inverse(double_divide(b3,a3)))), inference(extension_rule, [i_0_13])). 0.48/0.65 cnf(i_0_27, plain, (inverse(double_divide(double_divide(X13,inverse(double_divide(X14,double_divide(c3,inverse(double_divide(b3,a3)))))),double_divide(inverse(X14),inverse(double_divide(X15,double_divide(X13,X15))))))=inverse(double_divide(c3,inverse(double_divide(b3,a3))))), inference(extension_rule, [i_0_11])). 0.48/0.65 cnf(i_0_33, plain, (inverse(double_divide(inverse(double_divide(c3,b3)),a3))=inverse(double_divide(c3,inverse(double_divide(b3,a3))))), inference(closure_rule, [i_0_6])). 0.48/0.65 cnf(i_0_34, plain, (inverse(double_divide(inverse(double_divide(c3,b3)),a3))!=inverse(double_divide(double_divide(X13,inverse(double_divide(X14,double_divide(c3,inverse(double_divide(b3,a3)))))),double_divide(inverse(X14),inverse(double_divide(X15,double_divide(X13,X15))))))), inference(etableau_closure_rule, [i_0_34, ...])). 0.48/0.65 # End printing tableau 0.48/0.65 # SZS output end 0.48/0.65 # Branches closed with saturation will be marked with an "s" 0.48/0.65 # Returning from population with 7 new_tableaux and 0 remaining starting tableaux. 0.48/0.65 # We now have 7 tableaux to operate on 0.48/0.65 # Found closed tableau during pool population. 0.48/0.65 # Proof search is over... 0.48/0.65 # Freeing feature tree 0.48/0.66 EOF