0.07/0.12 % Problem : theBenchmark.p : TPTP v0.0.0. Released v0.0.0. 0.07/0.13 % Command : etableau --auto --tsmdo --quicksat=10000 --tableau=1 --tableau-saturation=1 -s -p --tableau-cores=8 --cpu-limit=%d %s 0.13/0.34 % Computer : n002.cluster.edu 0.13/0.34 % Model : x86_64 x86_64 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz 0.13/0.34 % Memory : 8042.1875MB 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64 0.13/0.34 % CPULimit : 1200 0.13/0.34 % WCLimit : 120 0.13/0.34 % DateTime : Tue Jul 13 14:43:33 EDT 2021 0.13/0.34 % CPUTime : 0.13/0.37 # No SInE strategy applied 0.13/0.37 # Auto-Mode selected heuristic G_E___208_C18_F1_SE_CS_SP_PS_S5PRR_RG_S04AN 0.13/0.37 # and selection function SelectComplexExceptUniqMaxHorn. 0.13/0.37 # 0.13/0.37 # Presaturation interreduction done 0.13/0.37 # Number of axioms: 6 Number of unprocessed: 6 0.13/0.37 # Tableaux proof search. 0.13/0.37 # APR header successfully linked. 0.13/0.37 # Hello from C++ 0.13/0.37 # The folding up rule is enabled... 0.13/0.37 # Local unification is enabled... 0.13/0.37 # Any saturation attempts will use folding labels... 0.13/0.37 # 6 beginning clauses after preprocessing and clausification 0.13/0.37 # Creating start rules for all 1 conjectures. 0.13/0.37 # There are 1 start rule candidates: 0.13/0.37 # Found 5 unit axioms. 0.13/0.37 # 1 start rule tableaux created. 0.13/0.37 # 1 extension rule candidate clauses 0.13/0.37 # 5 unit axiom clauses 0.13/0.37 0.13/0.37 # Requested 8, 32 cores available to the main process. 0.13/0.37 # There are not enough tableaux to fork, creating more from the initial 1 0.13/0.37 # Creating equality axioms 0.13/0.37 # Ran out of tableaux, making start rules for all clauses 0.13/0.37 # Returning from population with 13 new_tableaux and 0 remaining starting tableaux. 0.13/0.37 # We now have 13 tableaux to operate on 41.90/5.68 # There were 1 total branch saturation attempts. 41.90/5.68 # There were 0 of these attempts blocked. 41.90/5.68 # There were 0 deferred branch saturation attempts. 41.90/5.68 # There were 0 free duplicated saturations. 41.90/5.68 # There were 1 total successful branch saturations. 41.90/5.68 # There were 0 successful branch saturations in interreduction. 41.90/5.68 # There were 0 successful branch saturations on the branch. 41.90/5.68 # There were 1 successful branch saturations after the branch. 41.90/5.68 # SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p 41.90/5.68 # SZS output start for /export/starexec/sandbox/benchmark/theBenchmark.p 41.90/5.68 # Begin clausification derivation 41.90/5.68 41.90/5.68 # End clausification derivation 41.90/5.68 # Begin listing active clauses obtained from FOF to CNF conversion 41.90/5.68 cnf(i_0_4, plain, (ld(X1,mult(X1,X2))=X2)). 41.90/5.68 cnf(i_0_5, plain, (mult(X1,ld(X1,X2))=X2)). 41.90/5.68 cnf(i_0_2, plain, (mult(rd(X1,X2),X2)=X1)). 41.90/5.68 cnf(i_0_6, plain, (rd(mult(X1,X2),X2)=X1)). 41.90/5.68 cnf(i_0_1, plain, (mult(mult(mult(X1,X2),X3),X2)=mult(X1,mult(X2,mult(X3,X2))))). 41.90/5.68 cnf(i_0_3, negated_conjecture, (mult(esk1_0,ld(esk2_0,esk2_0))!=esk1_0|mult(ld(esk2_0,esk2_0),esk1_0)!=esk1_0)). 41.90/5.68 cnf(i_0_13, plain, (X19=X19)). 41.90/5.68 # End listing active clauses. There is an equivalent clause to each of these in the clausification! 41.90/5.68 # Begin printing tableau 41.90/5.68 # Found 6 steps 41.90/5.68 cnf(i_0_4, plain, (ld(X7,mult(X7,X4))=X4), inference(start_rule)). 41.90/5.68 cnf(i_0_20, plain, (ld(X7,mult(X7,X4))=X4), inference(extension_rule, [i_0_17])). 41.90/5.68 cnf(i_0_39, plain, (ld(X1,mult(X1,X6))!=X6), inference(closure_rule, [i_0_4])). 41.90/5.68 cnf(i_0_37, plain, (mult(ld(X7,mult(X7,X4)),ld(X1,mult(X1,X6)))=mult(X4,X6)), inference(extension_rule, [i_0_16])). 41.90/5.68 cnf(i_0_54, plain, (mult(X4,X6)!=ld(X1,mult(X1,mult(X4,X6)))), inference(closure_rule, [i_0_4])). 41.90/5.68 cnf(i_0_52, plain, (mult(ld(X7,mult(X7,X4)),ld(X1,mult(X1,X6)))=ld(X1,mult(X1,mult(X4,X6)))), inference(etableau_closure_rule, [i_0_52, ...])). 41.90/5.68 # End printing tableau 41.90/5.68 # SZS output end 41.90/5.68 # Branches closed with saturation will be marked with an "s" 41.90/5.69 # There were 1 total branch saturation attempts. 41.90/5.69 # There were 0 of these attempts blocked. 41.90/5.69 # There were 0 deferred branch saturation attempts. 41.90/5.69 # There were 0 free duplicated saturations. 41.90/5.69 # There were 1 total successful branch saturations. 41.90/5.69 # There were 0 successful branch saturations in interreduction. 41.90/5.69 # There were 0 successful branch saturations on the branch. 41.90/5.69 # There were 1 successful branch saturations after the branch. 41.90/5.69 # SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p 41.90/5.69 # SZS output start for /export/starexec/sandbox/benchmark/theBenchmark.p 41.90/5.69 # Begin clausification derivation 41.90/5.69 41.90/5.69 # End clausification derivation 41.90/5.69 # Begin listing active clauses obtained from FOF to CNF conversion 41.90/5.69 cnf(i_0_4, plain, (ld(X1,mult(X1,X2))=X2)). 41.90/5.69 cnf(i_0_5, plain, (mult(X1,ld(X1,X2))=X2)). 41.90/5.69 cnf(i_0_2, plain, (mult(rd(X1,X2),X2)=X1)). 41.90/5.69 cnf(i_0_6, plain, (rd(mult(X1,X2),X2)=X1)). 41.90/5.69 cnf(i_0_1, plain, (mult(mult(mult(X1,X2),X3),X2)=mult(X1,mult(X2,mult(X3,X2))))). 41.90/5.69 cnf(i_0_3, negated_conjecture, (mult(esk1_0,ld(esk2_0,esk2_0))!=esk1_0|mult(ld(esk2_0,esk2_0),esk1_0)!=esk1_0)). 41.90/5.69 cnf(i_0_13, plain, (X19=X19)). 41.90/5.69 # End listing active clauses. There is an equivalent clause to each of these in the clausification! 41.90/5.69 # Begin printing tableau 41.90/5.69 # Found 6 steps 41.90/5.69 cnf(i_0_4, plain, (ld(X9,mult(X9,X6))=X6), inference(start_rule)). 41.90/5.69 cnf(i_0_20, plain, (ld(X9,mult(X9,X6))=X6), inference(extension_rule, [i_0_17])). 41.90/5.69 cnf(i_0_38, plain, (ld(X1,mult(X1,X4))!=X4), inference(closure_rule, [i_0_4])). 41.90/5.69 cnf(i_0_37, plain, (mult(ld(X1,mult(X1,X4)),ld(X9,mult(X9,X6)))=mult(X4,X6)), inference(extension_rule, [i_0_16])). 41.90/5.69 cnf(i_0_54, plain, (mult(X4,X6)!=ld(X1,mult(X1,mult(X4,X6)))), inference(closure_rule, [i_0_4])). 41.90/5.69 cnf(i_0_52, plain, (mult(ld(X1,mult(X1,X4)),ld(X9,mult(X9,X6)))=ld(X1,mult(X1,mult(X4,X6)))), inference(etableau_closure_rule, [i_0_52, ...])). 41.90/5.69 # End printing tableau 41.90/5.69 # SZS output end 41.90/5.69 # Branches closed with saturation will be marked with an "s" 41.90/5.70 # Child (15698) has found a proof. 41.90/5.70 41.90/5.70 # Proof search is over... 41.90/5.70 # Freeing feature tree 41.90/5.74 EOF