TSTP Solution File: SYO691-1.000 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYO691-1.000 : TPTP v8.1.0. Released v7.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n026.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:26:34 EDT 2022

% Result   : Unsatisfiable 1.97s 2.15s
% Output   : Refutation 1.97s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    5
%            Number of leaves      :    7
% Syntax   : Number of clauses     :   14 (  10 unt;   0 nHn;   4 RR)
%            Number of literals    :   19 (   0 equ;   6 neg)
%            Maximal clause size   :    3 (   1 avg)
%            Maximal term depth    :    5 (   2 avg)
%            Number of predicates  :    4 (   3 usr;   1 prp; 0-3 aty)
%            Number of functors    :    4 (   4 usr;   2 con; 0-2 aty)
%            Number of variables   :   41 (   0 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ~ se_q(succ(succ(succ(zero))),A,A),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(2,axiom,
    ( ~ top(A,B)
    | step(A,B) ),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(3,axiom,
    ( ~ step(A,B)
    | step(f(A,C),f(B,C)) ),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(4,axiom,
    ( ~ step(A,B)
    | step(f(C,A),f(C,B)) ),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(5,axiom,
    ( ~ se_q(A,B,C)
    | ~ step(C,D)
    | se_q(succ(A),B,D) ),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(6,axiom,
    top(f(f(A,B),f(C,a)),f(f(C,f(B,a)),A)),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(7,axiom,
    se_q(zero,A,A),
    file('SYO691-1.000.p',unknown),
    [] ).

cnf(8,plain,
    step(f(f(A,B),f(C,a)),f(f(C,f(B,a)),A)),
    inference(hyper,[status(thm)],[6,2]),
    [iquote('hyper,6,2')] ).

cnf(9,plain,
    se_q(succ(zero),f(f(A,B),f(C,a)),f(f(C,f(B,a)),A)),
    inference(hyper,[status(thm)],[8,5,7]),
    [iquote('hyper,8,5,7')] ).

cnf(10,plain,
    step(f(A,f(f(B,C),f(D,a))),f(A,f(f(D,f(C,a)),B))),
    inference(hyper,[status(thm)],[8,4]),
    [iquote('hyper,8,4')] ).

cnf(11,plain,
    step(f(f(f(A,B),f(C,a)),D),f(f(f(C,f(B,a)),A),D)),
    inference(hyper,[status(thm)],[8,3]),
    [iquote('hyper,8,3')] ).

cnf(17,plain,
    se_q(succ(succ(zero)),f(f(A,B),f(f(C,D),a)),f(f(f(B,f(D,a)),C),A)),
    inference(hyper,[status(thm)],[11,5,9]),
    [iquote('hyper,11,5,9')] ).

cnf(30,plain,
    se_q(succ(succ(succ(zero))),f(f(f(f(A,B),f(C,a)),D),f(f(E,F),a)),f(f(f(D,f(F,a)),E),f(f(C,f(B,a)),A))),
    inference(hyper,[status(thm)],[17,5,10]),
    [iquote('hyper,17,5,10')] ).

cnf(31,plain,
    $false,
    inference(binary,[status(thm)],[30,1]),
    [iquote('binary,30.1,1.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SYO691-1.000 : TPTP v8.1.0. Released v7.3.0.
% 0.04/0.13  % Command  : otter-tptp-script %s
% 0.13/0.34  % Computer : n026.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 300
% 0.13/0.34  % DateTime : Wed Jul 27 10:22:09 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 1.97/2.15  ----- Otter 3.3f, August 2004 -----
% 1.97/2.15  The process was started by sandbox on n026.cluster.edu,
% 1.97/2.15  Wed Jul 27 10:22:09 2022
% 1.97/2.15  The command was "./otter".  The process ID is 26738.
% 1.97/2.15  
% 1.97/2.15  set(prolog_style_variables).
% 1.97/2.15  set(auto).
% 1.97/2.15     dependent: set(auto1).
% 1.97/2.15     dependent: set(process_input).
% 1.97/2.15     dependent: clear(print_kept).
% 1.97/2.15     dependent: clear(print_new_demod).
% 1.97/2.15     dependent: clear(print_back_demod).
% 1.97/2.15     dependent: clear(print_back_sub).
% 1.97/2.15     dependent: set(control_memory).
% 1.97/2.15     dependent: assign(max_mem, 12000).
% 1.97/2.15     dependent: assign(pick_given_ratio, 4).
% 1.97/2.15     dependent: assign(stats_level, 1).
% 1.97/2.15     dependent: assign(max_seconds, 10800).
% 1.97/2.15  clear(print_given).
% 1.97/2.15  
% 1.97/2.15  list(usable).
% 1.97/2.15  0 [] top(f(f(Z,Y),f(X,a)),f(f(X,f(Y,a)),Z)).
% 1.97/2.15  0 [] -se_q(succ(succ(succ(zero))),X,X).
% 1.97/2.15  0 [] -top(X,Y)|step(X,Y).
% 1.97/2.15  0 [] -step(X,Y)|step(f(X,Z),f(Y,Z)).
% 1.97/2.15  0 [] -step(Y,Z)|step(f(X,Y),f(X,Z)).
% 1.97/2.15  0 [] se_q(zero,X,X).
% 1.97/2.15  0 [] -se_q(N,X,Y)| -step(Y,Z)|se_q(succ(N),X,Z).
% 1.97/2.15  end_of_list.
% 1.97/2.15  
% 1.97/2.15  SCAN INPUT: prop=0, horn=1, equality=0, symmetry=0, max_lits=3.
% 1.97/2.15  
% 1.97/2.15  This is a Horn set without equality.  The strategy will
% 1.97/2.15  be hyperresolution, with satellites in sos and nuclei
% 1.97/2.15  in usable.
% 1.97/2.15  
% 1.97/2.15     dependent: set(hyper_res).
% 1.97/2.15     dependent: clear(order_hyper).
% 1.97/2.15  
% 1.97/2.15  ------------> process usable:
% 1.97/2.15  ** KEPT (pick-wt=7): 1 [] -se_q(succ(succ(succ(zero))),A,A).
% 1.97/2.15  ** KEPT (pick-wt=6): 2 [] -top(A,B)|step(A,B).
% 1.97/2.15  ** KEPT (pick-wt=10): 3 [] -step(A,B)|step(f(A,C),f(B,C)).
% 1.97/2.15  ** KEPT (pick-wt=10): 4 [] -step(A,B)|step(f(C,A),f(C,B)).
% 1.97/2.15  ** KEPT (pick-wt=12): 5 [] -se_q(A,B,C)| -step(C,D)|se_q(succ(A),B,D).
% 1.97/2.15  
% 1.97/2.15  ------------> process sos:
% 1.97/2.15  ** KEPT (pick-wt=15): 6 [] top(f(f(A,B),f(C,a)),f(f(C,f(B,a)),A)).
% 1.97/2.15  ** KEPT (pick-wt=4): 7 [] se_q(zero,A,A).
% 1.97/2.15  
% 1.97/2.15  ======= end of input processing =======
% 1.97/2.15  
% 1.97/2.15  =========== start of search ===========
% 1.97/2.15  
% 1.97/2.15  -------- PROOF -------- 
% 1.97/2.15  
% 1.97/2.15  ----> UNIT CONFLICT at   0.00 sec ----> 31 [binary,30.1,1.1] $F.
% 1.97/2.15  
% 1.97/2.15  Length of proof is 6.  Level of proof is 4.
% 1.97/2.15  
% 1.97/2.15  ---------------- PROOF ----------------
% 1.97/2.15  % SZS status Unsatisfiable
% 1.97/2.15  % SZS output start Refutation
% See solution above
% 1.97/2.15  ------------ end of proof -------------
% 1.97/2.15  
% 1.97/2.15  
% 1.97/2.15  Search stopped by max_proofs option.
% 1.97/2.15  
% 1.97/2.15  
% 1.97/2.15  Search stopped by max_proofs option.
% 1.97/2.15  
% 1.97/2.15  ============ end of search ============
% 1.97/2.15  
% 1.97/2.15  -------------- statistics -------------
% 1.97/2.15  clauses given                 10
% 1.97/2.15  clauses generated             24
% 1.97/2.15  clauses kept                  30
% 1.97/2.15  clauses forward subsumed       1
% 1.97/2.15  clauses back subsumed          0
% 1.97/2.15  Kbytes malloced              976
% 1.97/2.15  
% 1.97/2.15  ----------- times (seconds) -----------
% 1.97/2.15  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.97/2.15  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.97/2.15  wall-clock time        2             (0 hr, 0 min, 2 sec)
% 1.97/2.15  
% 1.97/2.15  That finishes the proof of the theorem.
% 1.97/2.15  
% 1.97/2.15  Process 26738 finished Wed Jul 27 10:22:11 2022
% 1.97/2.15  Otter interrupted
% 1.97/2.15  PROOF FOUND
%------------------------------------------------------------------------------