TSTP Solution File: SYO554^1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO554^1 : TPTP v8.1.2. Released v5.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n017.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:23:01 EDT 2023
% Result : Unsatisfiable 3.44s 3.68s
% Output : Proof 3.44s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.12 % Problem : SYO554^1 : TPTP v8.1.2. Released v5.2.0.
% 0.08/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n017.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 07:10:25 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.44/3.68 SZS status Theorem for theBenchmark.p
% 3.44/3.68 SZS output start Proof for theBenchmark.p
% 3.44/3.68 Clause #0 (by assumption #[]): Eq (Or (p s) (p t)) True
% 3.44/3.68 Clause #1 (by assumption #[]): Eq (Or (Not (p u)) (Not (p t))) True
% 3.44/3.68 Clause #2 (by assumption #[]): Eq (Eq s t) True
% 3.44/3.68 Clause #3 (by assumption #[]): Eq (Eq t u) True
% 3.44/3.68 Clause #4 (by clausification #[3]): Eq t u
% 3.44/3.68 Clause #5 (by clausification #[2]): Eq s t
% 3.44/3.68 Clause #6 (by clausification #[0]): Or (Eq (p s) True) (Eq (p t) True)
% 3.44/3.68 Clause #7 (by forward demodulation #[6, 5]): Or (Eq (p t) True) (Eq (p t) True)
% 3.44/3.68 Clause #8 (by eliminate duplicate literals #[7]): Eq (p t) True
% 3.44/3.68 Clause #9 (by clausification #[1]): Or (Eq (Not (p u)) True) (Eq (Not (p t)) True)
% 3.44/3.68 Clause #10 (by clausification #[9]): Or (Eq (Not (p t)) True) (Eq (p u) False)
% 3.44/3.68 Clause #11 (by clausification #[10]): Or (Eq (p u) False) (Eq (p t) False)
% 3.44/3.68 Clause #12 (by forward demodulation #[11, 4]): Or (Eq (p t) False) (Eq (p t) False)
% 3.44/3.68 Clause #13 (by eliminate duplicate literals #[12]): Eq (p t) False
% 3.44/3.68 Clause #14 (by superposition #[13, 8]): Eq False True
% 3.44/3.68 Clause #15 (by clausification #[14]): False
% 3.44/3.68 SZS output end Proof for theBenchmark.p
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