TSTP Solution File: SYO552^1 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO552^1 : TPTP v8.1.2. Released v5.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n019.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:23:01 EDT 2023
% Result : Theorem 3.35s 3.74s
% Output : Proof 3.35s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO552^1 : TPTP v8.1.2. Released v5.2.0.
% 0.00/0.14 % Command : duper %s
% 0.13/0.35 % Computer : n019.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sat Aug 26 06:35:58 EDT 2023
% 0.13/0.35 % CPUTime :
% 3.35/3.74 SZS status Theorem for theBenchmark.p
% 3.35/3.74 SZS output start Proof for theBenchmark.p
% 3.35/3.74 Clause #0 (by assumption #[]): Eq (Not (Exists fun F => ∀ (X Y : Iota), Eq (F X Y) X)) True
% 3.35/3.74 Clause #1 (by clausification #[0]): Eq (Exists fun F => ∀ (X Y : Iota), Eq (F X Y) X) False
% 3.35/3.74 Clause #2 (by clausification #[1]): ∀ (a : Iota → Iota → Iota), Eq (∀ (X Y : Iota), Eq (a X Y) X) False
% 3.35/3.74 Clause #3 (by clausification #[2]): ∀ (a : Iota → Iota → Iota) (a_1 : Iota), Eq (Not (∀ (Y : Iota), Eq (a (skS.0 0 a a_1) Y) (skS.0 0 a a_1))) True
% 3.35/3.74 Clause #4 (by clausification #[3]): ∀ (a : Iota → Iota → Iota) (a_1 : Iota), Eq (∀ (Y : Iota), Eq (a (skS.0 0 a a_1) Y) (skS.0 0 a a_1)) False
% 3.35/3.74 Clause #5 (by clausification #[4]): ∀ (a : Iota → Iota → Iota) (a_1 a_2 : Iota), Eq (Not (Eq (a (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)) (skS.0 0 a a_1))) True
% 3.35/3.74 Clause #6 (by clausification #[5]): ∀ (a : Iota → Iota → Iota) (a_1 a_2 : Iota), Eq (Eq (a (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)) (skS.0 0 a a_1)) False
% 3.35/3.74 Clause #7 (by clausification #[6]): ∀ (a : Iota → Iota → Iota) (a_1 a_2 : Iota), Ne (a (skS.0 0 a a_1) (skS.0 1 a a_1 a_2)) (skS.0 0 a a_1)
% 3.35/3.74 Clause #8 (by equality resolution #[7]): False
% 3.35/3.74 SZS output end Proof for theBenchmark.p
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