TSTP Solution File: SYO551^1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYO551^1 : TPTP v8.1.2. Released v5.2.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:23:00 EDT 2023
% Result : Theorem 3.26s 3.57s
% Output : Proof 3.26s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13 % Problem : SYO551^1 : TPTP v8.1.2. Released v5.2.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.36 % Computer : n029.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 300
% 0.14/0.36 % DateTime : Sat Aug 26 07:31:54 EDT 2023
% 0.14/0.36 % CPUTime :
% 3.26/3.57 SZS status Theorem for theBenchmark.p
% 3.26/3.57 SZS output start Proof for theBenchmark.p
% 3.26/3.57 Clause #0 (by assumption #[]): Eq (Not (Exists fun F => ∀ (X : Iota → Iota), Eq (F X) X)) True
% 3.26/3.57 Clause #1 (by clausification #[0]): Eq (Exists fun F => ∀ (X : Iota → Iota), Eq (F X) X) False
% 3.26/3.57 Clause #2 (by clausification #[1]): ∀ (a : (Iota → Iota) → Iota → Iota), Eq (∀ (X : Iota → Iota), Eq (a X) X) False
% 3.26/3.57 Clause #3 (by clausification #[2]): ∀ (a : (Iota → Iota) → Iota → Iota) (a_1 : Iota → Iota), Eq (Not (Eq (a (skS.0 0 a a_1)) (skS.0 0 a a_1))) True
% 3.26/3.57 Clause #4 (by clausification #[3]): ∀ (a : (Iota → Iota) → Iota → Iota) (a_1 : Iota → Iota), Eq (Eq (a (skS.0 0 a a_1)) (skS.0 0 a a_1)) False
% 3.26/3.57 Clause #5 (by clausification #[4]): ∀ (a : (Iota → Iota) → Iota → Iota) (a_1 : Iota → Iota), Ne (a (skS.0 0 a a_1)) (skS.0 0 a a_1)
% 3.26/3.57 Clause #6 (by equality resolution #[5]): False
% 3.26/3.57 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------