TSTP Solution File: SYO512^1 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : SYO512^1 : TPTP v7.5.0. Released v4.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n013.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:59 EDT 2022

% Result   : Theorem 0.47s 0.68s
% Output   : Proof 0.47s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem    : SYO512^1 : TPTP v7.5.0. Released v4.1.0.
% 0.07/0.12  % Command    : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.13/0.33  % Computer   : n013.cluster.edu
% 0.13/0.33  % Model      : x86_64 x86_64
% 0.13/0.33  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % RAMPerCPU  : 8042.1875MB
% 0.13/0.33  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % DateTime   : Sun Mar 13 13:27:37 EDT 2022
% 0.13/0.33  % CPUTime    : 
% 0.13/0.34  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.13/0.34  Python 2.7.5
% 0.47/0.68  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.47/0.68  FOF formula (<kernel.Constant object at 0x13311b8>, <kernel.DependentProduct object at 0x130a5f0>) of role type named eps
% 0.47/0.68  Using role type
% 0.47/0.68  Declaring eps:((fofType->Prop)->fofType)
% 0.47/0.68  FOF formula (forall (P:(fofType->Prop)), (((ex fofType) (fun (X:fofType)=> (P X)))->(P (eps P)))) of role axiom named epschoice
% 0.47/0.68  A new axiom: (forall (P:(fofType->Prop)), (((ex fofType) (fun (X:fofType)=> (P X)))->(P (eps P))))
% 0.47/0.68  FOF formula (<kernel.Constant object at 0x1327c68>, <kernel.DependentProduct object at 0x130a950>) of role type named r
% 0.47/0.68  Using role type
% 0.47/0.68  Declaring r:(fofType->(fofType->Prop))
% 0.47/0.68  FOF formula (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((r X) Y)))) of role axiom named rtotal
% 0.47/0.68  A new axiom: (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((r X) Y))))
% 0.47/0.68  FOF formula (forall (X:fofType), ((r X) (eps (r X)))) of role conjecture named claim
% 0.47/0.68  Conjecture to prove = (forall (X:fofType), ((r X) (eps (r X)))):Prop
% 0.47/0.68  Parameter fofType_DUMMY:fofType.
% 0.47/0.68  We need to prove ['(forall (X:fofType), ((r X) (eps (r X))))']
% 0.47/0.68  Parameter fofType:Type.
% 0.47/0.68  Parameter eps:((fofType->Prop)->fofType).
% 0.47/0.68  Axiom epschoice:(forall (P:(fofType->Prop)), (((ex fofType) (fun (X:fofType)=> (P X)))->(P (eps P)))).
% 0.47/0.68  Parameter r:(fofType->(fofType->Prop)).
% 0.47/0.68  Axiom rtotal:(forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((r X) Y)))).
% 0.47/0.68  Trying to prove (forall (X:fofType), ((r X) (eps (r X))))
% 0.47/0.68  Found rtotal0:=(rtotal X):((ex fofType) (fun (Y:fofType)=> ((r X) Y)))
% 0.47/0.68  Found (rtotal X) as proof of ((ex fofType) (fun (X0:fofType)=> ((r X) X0)))
% 0.47/0.68  Found (rtotal X) as proof of ((ex fofType) (fun (X0:fofType)=> ((r X) X0)))
% 0.47/0.68  Found (epschoice0 (rtotal X)) as proof of ((r X) (eps (r X)))
% 0.47/0.68  Found ((epschoice (r X)) (rtotal X)) as proof of ((r X) (eps (r X)))
% 0.47/0.68  Found (fun (X:fofType)=> ((epschoice (r X)) (rtotal X))) as proof of ((r X) (eps (r X)))
% 0.47/0.68  Found (fun (X:fofType)=> ((epschoice (r X)) (rtotal X))) as proof of (forall (X:fofType), ((r X) (eps (r X))))
% 0.47/0.68  Got proof (fun (X:fofType)=> ((epschoice (r X)) (rtotal X)))
% 0.47/0.68  Time elapsed = 0.048334s
% 0.47/0.68  node=16 cost=-56.000000 depth=5
% 0.47/0.68  ::::::::::::::::::::::
% 0.47/0.68  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.47/0.68  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.47/0.68  (fun (X:fofType)=> ((epschoice (r X)) (rtotal X)))
% 0.47/0.68  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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