TSTP Solution File: SYO390^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO390^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n023.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:22:21 EDT 2023

% Result   : Theorem 3.58s 3.77s
% Output   : Proof 3.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SYO390^5 : TPTP v8.1.2. Released v4.0.0.
% 0.11/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n023.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 04:37:11 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.58/3.77  SZS status Theorem for theBenchmark.p
% 3.58/3.77  SZS output start Proof for theBenchmark.p
% 3.58/3.77  Clause #0 (by assumption #[]): Eq (Not (∀ (Xp Xq : Prop), Iff Xp Xq → Eq Xp Xq)) True
% 3.58/3.77  Clause #1 (by clausification #[0]): Eq (∀ (Xp Xq : Prop), Iff Xp Xq → Eq Xp Xq) False
% 3.58/3.77  Clause #2 (by clausification #[1]): ∀ (a : Prop), Eq (Not (∀ (Xq : Prop), Iff (skS.0 0 a) Xq → Eq (skS.0 0 a) Xq)) True
% 3.58/3.77  Clause #3 (by clausification #[2]): ∀ (a : Prop), Eq (∀ (Xq : Prop), Iff (skS.0 0 a) Xq → Eq (skS.0 0 a) Xq) False
% 3.58/3.77  Clause #4 (by clausification #[3]): ∀ (a a_1 : Prop), Eq (Not (Iff (skS.0 0 a) (skS.0 1 a a_1) → Eq (skS.0 0 a) (skS.0 1 a a_1))) True
% 3.58/3.77  Clause #5 (by clausification #[4]): ∀ (a a_1 : Prop), Eq (Iff (skS.0 0 a) (skS.0 1 a a_1) → Eq (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.58/3.77  Clause #6 (by clausification #[5]): ∀ (a a_1 : Prop), Eq (Iff (skS.0 0 a) (skS.0 1 a a_1)) True
% 3.58/3.77  Clause #7 (by clausification #[5]): ∀ (a a_1 : Prop), Eq (Eq (skS.0 0 a) (skS.0 1 a a_1)) False
% 3.58/3.77  Clause #8 (by clausification #[6]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 a) True) (Eq (skS.0 1 a a_1) False)
% 3.58/3.77  Clause #9 (by clausification #[6]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 a) False) (Eq (skS.0 1 a a_1) True)
% 3.58/3.77  Clause #10 (by identity loobHoist #[8]): ∀ (a a_1 : Prop), Or (Eq (skS.0 1 a a_1) False) (Or (Eq (skS.0 0 True) True) (Eq a False))
% 3.58/3.77  Clause #12 (by identity loobHoist #[10]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq (skS.0 1 a True) False) (Eq a_1 False)))
% 3.58/3.77  Clause #14 (by identity loobHoist #[12]): ∀ (a a_1 : Prop),
% 3.58/3.77    Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq a_1 False) (Or (Eq (skS.0 1 True True) False) (Eq a False))))
% 3.58/3.77  Clause #16 (by eliminate duplicate literals #[14]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) False)))
% 3.58/3.77  Clause #17 (by falseElim #[16]): ∀ (a : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Eq (skS.0 1 True True) False))
% 3.58/3.77  Clause #18 (by identity loobHoist #[9]): ∀ (a a_1 : Prop), Or (Eq (skS.0 1 a a_1) True) (Or (Eq (skS.0 0 True) False) (Eq a False))
% 3.58/3.77  Clause #20 (by identity loobHoist #[18]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq (skS.0 1 a True) True) (Eq a_1 False)))
% 3.58/3.77  Clause #22 (by identity loobHoist #[20]): ∀ (a a_1 : Prop),
% 3.58/3.77    Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq a_1 False) (Or (Eq (skS.0 1 True True) True) (Eq a False))))
% 3.58/3.77  Clause #24 (by eliminate duplicate literals #[22]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) True)))
% 3.58/3.77  Clause #25 (by clausification #[7]): ∀ (a a_1 : Prop), Ne (skS.0 0 a) (skS.0 1 a a_1)
% 3.58/3.77  Clause #26 (by clausification #[25]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 a) False) (Eq (skS.0 1 a a_1) False)
% 3.58/3.77  Clause #27 (by clausification #[25]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 a) True) (Eq (skS.0 1 a a_1) True)
% 3.58/3.77  Clause #28 (by identity loobHoist #[26]): ∀ (a a_1 : Prop), Or (Eq (skS.0 1 a a_1) False) (Or (Eq (skS.0 0 True) False) (Eq a False))
% 3.58/3.77  Clause #30 (by identity loobHoist #[28]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq (skS.0 1 a True) False) (Eq a_1 False)))
% 3.58/3.77  Clause #32 (by identity loobHoist #[30]): ∀ (a a_1 : Prop),
% 3.58/3.77    Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq a_1 False) (Or (Eq (skS.0 1 True True) False) (Eq a False))))
% 3.58/3.77  Clause #34 (by eliminate duplicate literals #[32]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) False) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) False)))
% 3.58/3.77  Clause #35 (by identity loobHoist #[27]): ∀ (a a_1 : Prop), Or (Eq (skS.0 1 a a_1) True) (Or (Eq (skS.0 0 True) True) (Eq a False))
% 3.58/3.77  Clause #37 (by identity loobHoist #[35]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq (skS.0 1 a True) True) (Eq a_1 False)))
% 3.58/3.77  Clause #39 (by identity loobHoist #[37]): ∀ (a a_1 : Prop),
% 3.58/3.77    Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq a_1 False) (Or (Eq (skS.0 1 True True) True) (Eq a False))))
% 3.58/3.77  Clause #41 (by eliminate duplicate literals #[39]): ∀ (a a_1 : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) True)))
% 3.58/3.78  Clause #42 (by falseElim #[41]): ∀ (a : Prop), Or (Eq (skS.0 0 True) True) (Or (Eq a False) (Eq (skS.0 1 True True) True))
% 3.58/3.78  Clause #43 (by falseElim #[17]): Or (Eq (skS.0 0 True) True) (Eq (skS.0 1 True True) False)
% 3.58/3.78  Clause #48 (by falseElim #[42]): Or (Eq (skS.0 0 True) True) (Eq (skS.0 1 True True) True)
% 3.58/3.78  Clause #49 (by superposition #[48, 43]): Or (Eq (skS.0 0 True) True) (Or (Eq (skS.0 0 True) True) (Eq True False))
% 3.58/3.78  Clause #50 (by clausification #[49]): Or (Eq (skS.0 0 True) True) (Eq (skS.0 0 True) True)
% 3.58/3.78  Clause #51 (by eliminate duplicate literals #[50]): Eq (skS.0 0 True) True
% 3.58/3.78  Clause #52 (by backward demodulation #[51, 24]): ∀ (a a_1 : Prop), Or (Eq True False) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) True)))
% 3.58/3.78  Clause #53 (by backward demodulation #[51, 34]): ∀ (a a_1 : Prop), Or (Eq True False) (Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) False)))
% 3.58/3.78  Clause #57 (by clausification #[53]): ∀ (a a_1 : Prop), Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) False))
% 3.58/3.78  Clause #59 (by falseElim #[57]): ∀ (a : Prop), Or (Eq a False) (Eq (skS.0 1 True True) False)
% 3.58/3.78  Clause #61 (by falseElim #[59]): Eq (skS.0 1 True True) False
% 3.58/3.78  Clause #62 (by clausification #[52]): ∀ (a a_1 : Prop), Or (Eq a False) (Or (Eq a_1 False) (Eq (skS.0 1 True True) True))
% 3.58/3.78  Clause #64 (by falseElim #[62]): ∀ (a : Prop), Or (Eq a False) (Eq (skS.0 1 True True) True)
% 3.58/3.78  Clause #66 (by falseElim #[64]): Eq (skS.0 1 True True) True
% 3.58/3.78  Clause #67 (by superposition #[66, 61]): Eq True False
% 3.58/3.78  Clause #68 (by clausification #[67]): False
% 3.58/3.78  SZS output end Proof for theBenchmark.p
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