TSTP Solution File: SYO371^5 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : SYO371^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:16 EDT 2022

% Result   : Theorem 0.14s 0.54s
% Output   : Proof 0.14s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.09  % Problem    : SYO371^5 : TPTP v7.5.0. Released v4.0.0.
% 0.00/0.09  % Command    : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.10/0.28  % Computer   : n032.cluster.edu
% 0.10/0.28  % Model      : x86_64 x86_64
% 0.10/0.28  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.10/0.28  % RAMPerCPU  : 8042.1875MB
% 0.10/0.28  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.10/0.28  % CPULimit   : 300
% 0.10/0.28  % DateTime   : Sat Mar 12 08:14:32 EST 2022
% 0.10/0.28  % CPUTime    : 
% 0.13/0.28  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.13/0.29  Python 2.7.5
% 0.14/0.54  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.14/0.54  FOF formula (<kernel.Constant object at 0x163f950>, <kernel.Sort object at 0x2aad6a2dc5a8>) of role type named cQ
% 0.14/0.54  Using role type
% 0.14/0.54  Declaring cQ:Prop
% 0.14/0.54  FOF formula (<kernel.Constant object at 0x163fef0>, <kernel.Sort object at 0x2aad6a2dc5a8>) of role type named cP
% 0.14/0.54  Using role type
% 0.14/0.54  Declaring cP:Prop
% 0.14/0.54  FOF formula ((forall (R:(Prop->Prop)), ((R cP)->(R cQ)))->((iff cP) cQ)) of role conjecture named cEXT_O_LEIB
% 0.14/0.54  Conjecture to prove = ((forall (R:(Prop->Prop)), ((R cP)->(R cQ)))->((iff cP) cQ)):Prop
% 0.14/0.54  We need to prove ['((forall (R:(Prop->Prop)), ((R cP)->(R cQ)))->((iff cP) cQ))']
% 0.14/0.54  Parameter cQ:Prop.
% 0.14/0.54  Parameter cP:Prop.
% 0.14/0.54  Trying to prove ((forall (R:(Prop->Prop)), ((R cP)->(R cQ)))->((iff cP) cQ))
% 0.14/0.54  Found iff_refl0:=(iff_refl cP):((iff cP) cP)
% 0.14/0.54  Found (iff_refl cP) as proof of ((iff cP) cP)
% 0.14/0.54  Found (iff_refl cP) as proof of ((iff cP) cP)
% 0.14/0.54  Found (x0 (iff_refl cP)) as proof of ((iff cP) cQ)
% 0.14/0.54  Found ((x (iff cP)) (iff_refl cP)) as proof of ((iff cP) cQ)
% 0.14/0.54  Found (fun (x:(forall (R:(Prop->Prop)), ((R cP)->(R cQ))))=> ((x (iff cP)) (iff_refl cP))) as proof of ((iff cP) cQ)
% 0.14/0.54  Found (fun (x:(forall (R:(Prop->Prop)), ((R cP)->(R cQ))))=> ((x (iff cP)) (iff_refl cP))) as proof of ((forall (R:(Prop->Prop)), ((R cP)->(R cQ)))->((iff cP) cQ))
% 0.14/0.54  Got proof (fun (x:(forall (R:(Prop->Prop)), ((R cP)->(R cQ))))=> ((x (iff cP)) (iff_refl cP)))
% 0.14/0.54  Time elapsed = 0.034970s
% 0.14/0.54  node=8 cost=-61.000000 depth=5
% 0.14/0.54  ::::::::::::::::::::::
% 0.14/0.54  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.14/0.54  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.14/0.54  (fun (x:(forall (R:(Prop->Prop)), ((R cP)->(R cQ))))=> ((x (iff cP)) (iff_refl cP)))
% 0.14/0.54  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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