%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYO368^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n012.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:22:16 EDT 2023

% Result   : Theorem 3.32s 3.56s
% Output   : Proof 3.32s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO368^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14  % Command    : duper %s
% 0.13/0.35  % Computer : n012.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 04:51:10 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.32/3.56  SZS status Theorem for theBenchmark.p
% 3.32/3.56  SZS output start Proof for theBenchmark.p
% 3.32/3.56  Clause #0 (by assumption #[]): Eq (Not (And (Iff a b) (cP a) → cP b)) True
% 3.32/3.56  Clause #1 (by clausification #[0]): Eq (And (Iff a b) (cP a) → cP b) False
% 3.32/3.56  Clause #2 (by clausification #[1]): Eq (And (Iff a b) (cP a)) True
% 3.32/3.56  Clause #3 (by clausification #[1]): Eq (cP b) False
% 3.32/3.56  Clause #4 (by clausification #[2]): Eq (cP a) True
% 3.32/3.56  Clause #5 (by clausification #[2]): Eq (Iff a b) True
% 3.32/3.56  Clause #6 (by identity loobHoist #[4]): Or (Eq (cP True) True) (Eq a False)
% 3.32/3.56  Clause #7 (by identity boolHoist #[4]): Or (Eq (cP False) True) (Eq a True)
% 3.32/3.56  Clause #8 (by identity loobHoist #[3]): Or (Eq (cP True) False) (Eq b False)
% 3.32/3.56  Clause #9 (by identity boolHoist #[3]): Or (Eq (cP False) False) (Eq b True)
% 3.32/3.56  Clause #10 (by clausification #[5]): Or (Eq a True) (Eq b False)
% 3.32/3.56  Clause #11 (by clausification #[5]): Or (Eq a False) (Eq b True)
% 3.32/3.56  Clause #12 (by superposition #[9, 7]): Or (Eq b True) (Or (Eq False True) (Eq a True))
% 3.32/3.56  Clause #13 (by clausification #[12]): Or (Eq b True) (Eq a True)
% 3.32/3.56  Clause #14 (by superposition #[13, 10]): Or (Eq a True) (Or (Eq a True) (Eq True False))
% 3.32/3.56  Clause #15 (by clausification #[14]): Or (Eq a True) (Eq a True)
% 3.32/3.56  Clause #16 (by eliminate duplicate literals #[15]): Eq a True
% 3.32/3.56  Clause #17 (by backward demodulation #[16, 6]): Or (Eq (cP True) True) (Eq True False)
% 3.32/3.56  Clause #19 (by backward demodulation #[16, 11]): Or (Eq True False) (Eq b True)
% 3.32/3.56  Clause #22 (by clausification #[19]): Eq b True
% 3.32/3.56  Clause #23 (by backward demodulation #[22, 8]): Or (Eq (cP True) False) (Eq True False)
% 3.32/3.56  Clause #25 (by clausification #[17]): Eq (cP True) True
% 3.32/3.56  Clause #26 (by clausification #[23]): Eq (cP True) False
% 3.32/3.56  Clause #27 (by superposition #[26, 25]): Eq False True
% 3.32/3.56  Clause #28 (by clausification #[27]): False
% 3.32/3.56  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------