TSTP Solution File: SYO353^5 by cocATP---0.2.0

View Problem - Process Solution

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% File     : cocATP---0.2.0
% Problem  : SYO353^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n032.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:51:14 EDT 2022

% Result   : Theorem 0.35s 0.51s
% Output   : Proof 0.35s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.08  % Problem    : SYO353^5 : TPTP v7.5.0. Released v4.0.0.
% 0.00/0.08  % Command    : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.08/0.27  % Computer   : n032.cluster.edu
% 0.08/0.27  % Model      : x86_64 x86_64
% 0.08/0.27  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.08/0.27  % RAMPerCPU  : 8042.1875MB
% 0.08/0.27  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.08/0.27  % CPULimit   : 300
% 0.08/0.27  % DateTime   : Sat Mar 12 06:19:47 EST 2022
% 0.08/0.27  % CPUTime    : 
% 0.08/0.28  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.08/0.28  Python 2.7.5
% 0.35/0.51  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.35/0.51  FOF formula (<kernel.Constant object at 0xc42e60>, <kernel.Type object at 0xc42ea8>) of role type named a_type
% 0.35/0.51  Using role type
% 0.35/0.51  Declaring a:Type
% 0.35/0.51  FOF formula (<kernel.Constant object at 0xc42d40>, <kernel.Constant object at 0xc42c68>) of role type named v
% 0.35/0.51  Using role type
% 0.35/0.51  Declaring v:a
% 0.35/0.51  FOF formula (<kernel.Constant object at 0xc4b5a8>, <kernel.Constant object at 0xc42c68>) of role type named u
% 0.35/0.51  Using role type
% 0.35/0.51  Declaring u:a
% 0.35/0.51  FOF formula ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))) of role conjecture named cE1LEIBEQ1_pme
% 0.35/0.51  Conjecture to prove = ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))):Prop
% 0.35/0.51  We need to prove ['((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))))']
% 0.35/0.51  Parameter a:Type.
% 0.35/0.51  Parameter v:a.
% 0.35/0.51  Parameter u:a.
% 0.35/0.51  Trying to prove ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))))
% 0.35/0.51  Found x000:=(x00 u):((Q u) u)
% 0.35/0.51  Found (x00 u) as proof of ((Q u) u)
% 0.35/0.51  Found (fun (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of ((Q u) u)
% 0.35/0.51  Found (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of ((forall (Z:a), ((Q Z) Z))->((Q u) u))
% 0.35/0.51  Found (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) u)))
% 0.35/0.51  Found (x0 (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))
% 0.35/0.51  Found ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))
% 0.35/0.51  Found (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) as proof of (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v)))
% 0.35/0.51  Found (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u)))) as proof of ((forall (Xq:(a->Prop)), ((Xq u)->(Xq v)))->(forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) v))))
% 0.35/0.51  Got proof (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))))
% 0.35/0.51  Time elapsed = 0.046443s
% 0.35/0.51  node=17 cost=-48.000000 depth=7
% 0.35/0.51  ::::::::::::::::::::::
% 0.35/0.51  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.35/0.51  % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.35/0.51  (fun (x:(forall (Xq:(a->Prop)), ((Xq u)->(Xq v))))=> ((x (fun (x1:a)=> (forall (Q:(a->(a->Prop))), ((forall (Z:a), ((Q Z) Z))->((Q u) x1))))) (fun (Q:(a->(a->Prop))) (x00:(forall (Z:a), ((Q Z) Z)))=> (x00 u))))
% 0.35/0.51  % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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