TSTP Solution File: SYO350^5 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SYO350^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:51:13 EDT 2022
% Result : Theorem 0.61s 0.80s
% Output : Proof 0.61s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : SYO350^5 : TPTP v7.5.0. Released v4.0.0.
% 0.06/0.13 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.33 % Computer : n028.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % RAMPerCPU : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Sat Mar 12 06:17:04 EST 2022
% 0.12/0.34 % CPUTime :
% 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.35 Python 2.7.5
% 0.61/0.80 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.61/0.80 FOF formula (<kernel.Constant object at 0x1e05518>, <kernel.DependentProduct object at 0x2b13d835dcb0>) of role type named g
% 0.61/0.80 Using role type
% 0.61/0.80 Declaring g:(fofType->fofType)
% 0.61/0.80 FOF formula (<kernel.Constant object at 0x1e09e60>, <kernel.DependentProduct object at 0x1e053f8>) of role type named p
% 0.61/0.80 Using role type
% 0.61/0.80 Declaring p:((fofType->fofType)->Prop)
% 0.61/0.80 FOF formula (<kernel.Constant object at 0x1e05518>, <kernel.DependentProduct object at 0x2b13d835d908>) of role type named f
% 0.61/0.80 Using role type
% 0.61/0.80 Declaring f:(fofType->fofType)
% 0.61/0.80 FOF formula ((forall (X:fofType), (((eq fofType) (f X)) (g X)))->((p f)->(p g))) of role conjecture named cE1FUNC
% 0.61/0.80 Conjecture to prove = ((forall (X:fofType), (((eq fofType) (f X)) (g X)))->((p f)->(p g))):Prop
% 0.61/0.80 Parameter fofType_DUMMY:fofType.
% 0.61/0.80 We need to prove ['((forall (X:fofType), (((eq fofType) (f X)) (g X)))->((p f)->(p g)))']
% 0.61/0.80 Parameter fofType:Type.
% 0.61/0.80 Parameter g:(fofType->fofType).
% 0.61/0.80 Parameter p:((fofType->fofType)->Prop).
% 0.61/0.80 Parameter f:(fofType->fofType).
% 0.61/0.80 Trying to prove ((forall (X:fofType), (((eq fofType) (f X)) (g X)))->((p f)->(p g)))
% 0.61/0.80 Found functional_extensionality000000:=(functional_extensionality00000 p):((p f)->(p g))
% 0.61/0.80 Found (functional_extensionality00000 p) as proof of ((p f)->(p g))
% 0.61/0.80 Found ((functional_extensionality0000 x) p) as proof of ((p f)->(p g))
% 0.61/0.80 Found (((functional_extensionality000 g) x) p) as proof of ((p f)->(p g))
% 0.61/0.80 Found ((((functional_extensionality00 f) g) x) p) as proof of ((p f)->(p g))
% 0.61/0.80 Found (((((functional_extensionality0 fofType) f) g) x) p) as proof of ((p f)->(p g))
% 0.61/0.80 Found ((((((functional_extensionality fofType) fofType) f) g) x) p) as proof of ((p f)->(p g))
% 0.61/0.80 Found (fun (x:(forall (X:fofType), (((eq fofType) (f X)) (g X))))=> ((((((functional_extensionality fofType) fofType) f) g) x) p)) as proof of ((p f)->(p g))
% 0.61/0.80 Found (fun (x:(forall (X:fofType), (((eq fofType) (f X)) (g X))))=> ((((((functional_extensionality fofType) fofType) f) g) x) p)) as proof of ((forall (X:fofType), (((eq fofType) (f X)) (g X)))->((p f)->(p g)))
% 0.61/0.80 Got proof (fun (x:(forall (X:fofType), (((eq fofType) (f X)) (g X))))=> ((((((functional_extensionality fofType) fofType) f) g) x) p))
% 0.61/0.80 Time elapsed = 0.163856s
% 0.61/0.80 node=36 cost=62.000000 depth=7
% 0.61/0.80 ::::::::::::::::::::::
% 0.61/0.80 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.61/0.80 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.61/0.80 (fun (x:(forall (X:fofType), (((eq fofType) (f X)) (g X))))=> ((((((functional_extensionality fofType) fofType) f) g) x) p))
% 0.61/0.80 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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