%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYO346^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n021.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:22:12 EDT 2023

% Result   : Theorem 5.69s 5.88s
% Output   : Proof 5.69s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem    : SYO346^5 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.14/0.35  % Computer : n021.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri Aug 25 23:45:41 EDT 2023
% 0.14/0.35  % CPUTime    : 
% 5.69/5.88  SZS status Theorem for theBenchmark.p
% 5.69/5.88  SZS output start Proof for theBenchmark.p
% 5.69/5.88  Clause #0 (by assumption #[]): Eq (Not (Or (Or (Ne cA cB) (Not (cP cA))) (cP cB))) True
% 5.69/5.88  Clause #1 (by clausification #[0]): Eq (Or (Or (Ne cA cB) (Not (cP cA))) (cP cB)) False
% 5.69/5.88  Clause #2 (by clausification #[1]): Eq (cP cB) False
% 5.69/5.88  Clause #3 (by clausification #[1]): Eq (Or (Ne cA cB) (Not (cP cA))) False
% 5.69/5.88  Clause #4 (by identity loobHoist #[2]): Or (Eq (cP True) False) (Eq cB False)
% 5.69/5.88  Clause #5 (by identity boolHoist #[2]): Or (Eq (cP False) False) (Eq cB True)
% 5.69/5.88  Clause #6 (by clausification #[3]): Eq (Not (cP cA)) False
% 5.69/5.88  Clause #7 (by clausification #[3]): Eq (Ne cA cB) False
% 5.69/5.88  Clause #8 (by clausification #[6]): Eq (cP cA) True
% 5.69/5.88  Clause #9 (by identity loobHoist #[8]): Or (Eq (cP True) True) (Eq cA False)
% 5.69/5.88  Clause #10 (by identity boolHoist #[8]): Or (Eq (cP False) True) (Eq cA True)
% 5.69/5.88  Clause #11 (by superposition #[10, 5]): Or (Eq cA True) (Or (Eq True False) (Eq cB True))
% 5.69/5.88  Clause #12 (by clausification #[7]): Eq cA cB
% 5.69/5.88  Clause #13 (by backward demodulation #[12, 4]): Or (Eq (cP True) False) (Eq cA False)
% 5.69/5.88  Clause #17 (by clausification #[11]): Or (Eq cA True) (Eq cB True)
% 5.69/5.88  Clause #18 (by superposition #[17, 12]): Or (Eq cA True) (Eq cA True)
% 5.69/5.88  Clause #19 (by eliminate duplicate literals #[18]): Eq cA True
% 5.69/5.88  Clause #20 (by backward demodulation #[19, 9]): Or (Eq (cP True) True) (Eq True False)
% 5.69/5.88  Clause #27 (by forward demodulation #[13, 19]): Or (Eq (cP True) False) (Eq True False)
% 5.69/5.88  Clause #28 (by clausification #[27]): Eq (cP True) False
% 5.69/5.88  Clause #30 (by clausification #[20]): Eq (cP True) True
% 5.69/5.88  Clause #31 (by superposition #[30, 28]): Eq True False
% 5.69/5.88  Clause #32 (by clausification #[31]): False
% 5.69/5.88  SZS output end Proof for theBenchmark.p
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