TSTP Solution File: SYO285^5 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SYO285^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n003.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:51:04 EDT 2022
% Result : Theorem 0.46s 0.63s
% Output : Proof 0.46s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11 % Problem : SYO285^5 : TPTP v7.5.0. Released v4.0.0.
% 0.11/0.11 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.32 % Computer : n003.cluster.edu
% 0.12/0.32 % Model : x86_64 x86_64
% 0.12/0.32 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32 % RAMPerCPU : 8042.1875MB
% 0.12/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32 % CPULimit : 300
% 0.12/0.32 % DateTime : Sat Mar 12 00:45:26 EST 2022
% 0.12/0.32 % CPUTime :
% 0.12/0.33 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.34 Python 2.7.5
% 0.46/0.63 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.46/0.63 FOF formula (<kernel.Constant object at 0xc13c68>, <kernel.Constant object at 0xc13758>) of role type named y
% 0.46/0.63 Using role type
% 0.46/0.63 Declaring y:fofType
% 0.46/0.63 FOF formula (<kernel.Constant object at 0xc17d88>, <kernel.DependentProduct object at 0xc13cf8>) of role type named cQ
% 0.46/0.63 Using role type
% 0.46/0.63 Declaring cQ:(fofType->Prop)
% 0.46/0.63 FOF formula (<kernel.Constant object at 0xc13c68>, <kernel.DependentProduct object at 0xc13488>) of role type named cR
% 0.46/0.63 Using role type
% 0.46/0.63 Declaring cR:(fofType->Prop)
% 0.46/0.63 FOF formula ((forall (Xp:(fofType->Prop)), (Xp y))->((and (forall (Xx:fofType), (cR Xx))) (cQ y))) of role conjecture named cTEST2
% 0.46/0.63 Conjecture to prove = ((forall (Xp:(fofType->Prop)), (Xp y))->((and (forall (Xx:fofType), (cR Xx))) (cQ y))):Prop
% 0.46/0.63 We need to prove ['((forall (Xp:(fofType->Prop)), (Xp y))->((and (forall (Xx:fofType), (cR Xx))) (cQ y)))']
% 0.46/0.63 Parameter fofType:Type.
% 0.46/0.63 Parameter y:fofType.
% 0.46/0.63 Parameter cQ:(fofType->Prop).
% 0.46/0.63 Parameter cR:(fofType->Prop).
% 0.46/0.63 Trying to prove ((forall (Xp:(fofType->Prop)), (Xp y))->((and (forall (Xx:fofType), (cR Xx))) (cQ y)))
% 0.46/0.63 Found x0:=(x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0)))):((and (forall (Xx:fofType), (cR Xx))) (cQ y))
% 0.46/0.63 Found (x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0)))) as proof of ((and (forall (Xx:fofType), (cR Xx))) (cQ y))
% 0.46/0.63 Found (fun (x:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0))))) as proof of ((and (forall (Xx:fofType), (cR Xx))) (cQ y))
% 0.46/0.63 Found (fun (x:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0))))) as proof of ((forall (Xp:(fofType->Prop)), (Xp y))->((and (forall (Xx:fofType), (cR Xx))) (cQ y)))
% 0.46/0.63 Got proof (fun (x:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0)))))
% 0.46/0.63 Time elapsed = 0.026367s
% 0.46/0.63 node=2 cost=-94.000000 depth=2
% 0.46/0.63 ::::::::::::::::::::::
% 0.46/0.63 % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.46/0.63 % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.46/0.63 (fun (x:(forall (Xp:(fofType->Prop)), (Xp y)))=> (x (fun (x0:fofType)=> ((and (forall (Xx:fofType), (cR Xx))) (cQ x0)))))
% 0.46/0.63 % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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