TSTP Solution File: SYO272^5 by cocATP---0.2.0
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- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO272^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n004.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:51:03 EDT 2022
% Result : Unknown 0.68s 0.83s
% Output : None
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.11 % Problem : SYO272^5 : TPTP v7.5.0. Released v4.0.0.
% 0.03/0.11 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.11/0.32 % Computer : n004.cluster.edu
% 0.11/0.32 % Model : x86_64 x86_64
% 0.11/0.32 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.11/0.32 % RAMPerCPU : 8042.1875MB
% 0.11/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.11/0.32 % CPULimit : 300
% 0.11/0.32 % DateTime : Fri Mar 11 23:53:25 EST 2022
% 0.11/0.32 % CPUTime :
% 0.11/0.33 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.11/0.33 Python 2.7.5
% 0.61/0.83 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.61/0.83 FOF formula (<kernel.Constant object at 0x2178050>, <kernel.DependentProduct object at 0x2151d40>) of role type named cHALF
% 0.61/0.83 Using role type
% 0.61/0.83 Declaring cHALF:(fofType->(fofType->Prop))
% 0.61/0.83 FOF formula (<kernel.Constant object at 0x2b9de6cbd518>, <kernel.DependentProduct object at 0x21515f0>) of role type named cDOUBLE
% 0.61/0.83 Using role type
% 0.61/0.83 Declaring cDOUBLE:(fofType->(fofType->Prop))
% 0.61/0.83 FOF formula (<kernel.Constant object at 0x21783b0>, <kernel.DependentProduct object at 0x2151998>) of role type named cS
% 0.61/0.83 Using role type
% 0.61/0.83 Declaring cS:(fofType->fofType)
% 0.61/0.83 FOF formula (<kernel.Constant object at 0x2178290>, <kernel.Single object at 0x2178098>) of role type named c0
% 0.61/0.83 Using role type
% 0.61/0.83 Declaring c0:fofType
% 0.61/0.83 FOF formula (((and ((and ((and (forall (Xu:fofType) (Xv:fofType), ((iff ((cDOUBLE Xu) Xv)) (forall (Q:(fofType->(fofType->Prop))), (((and ((Q c0) c0)) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))))) ((cHALF c0) c0))) ((cHALF (cS c0)) c0))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu)))) of role conjecture named cTHM301A
% 0.61/0.83 Conjecture to prove = (((and ((and ((and (forall (Xu:fofType) (Xv:fofType), ((iff ((cDOUBLE Xu) Xv)) (forall (Q:(fofType->(fofType->Prop))), (((and ((Q c0) c0)) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))))) ((cHALF c0) c0))) ((cHALF (cS c0)) c0))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu)))):Prop
% 0.61/0.83 We need to prove ['(((and ((and ((and (forall (Xu:fofType) (Xv:fofType), ((iff ((cDOUBLE Xu) Xv)) (forall (Q:(fofType->(fofType->Prop))), (((and ((Q c0) c0)) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))))) ((cHALF c0) c0))) ((cHALF (cS c0)) c0))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu))))']
% 0.61/0.83 Parameter fofType:Type.
% 0.61/0.83 Parameter cHALF:(fofType->(fofType->Prop)).
% 0.61/0.83 Parameter cDOUBLE:(fofType->(fofType->Prop)).
% 0.61/0.83 Parameter cS:(fofType->fofType).
% 0.61/0.83 Parameter c0:fofType.
% 0.61/0.83 Trying to prove (((and ((and ((and (forall (Xu:fofType) (Xv:fofType), ((iff ((cDOUBLE Xu) Xv)) (forall (Q:(fofType->(fofType->Prop))), (((and ((Q c0) c0)) (forall (Xx:fofType) (Xy:fofType), (((Q Xx) Xy)->((Q (cS Xx)) (cS (cS Xy))))))->((Q Xu) Xv)))))) ((cHALF c0) c0))) ((cHALF (cS c0)) c0))) (forall (Xx:fofType) (Xy:fofType), (((cHALF Xx) Xy)->((cHALF (cS (cS Xx))) (cS Xy)))))->(forall (Xu:fofType) (Xv:fofType), (((cDOUBLE Xu) Xv)->((cHALF Xv) Xu))))
% 0.61/0.83 % SZS status GaveUp for /export/starexec/sandbox2/benchmark/theBenchmark.p
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