TSTP Solution File: SYO270^5 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYO270^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:22:01 EDT 2023
% Result : Theorem 3.66s 3.83s
% Output : Proof 3.66s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO270^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.35 % Computer : n026.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Sat Aug 26 03:57:48 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.66/3.83 SZS status Theorem for theBenchmark.p
% 3.66/3.83 SZS output start Proof for theBenchmark.p
% 3.66/3.83 Clause #0 (by assumption #[]): Eq
% 3.66/3.83 (Not
% 3.66/3.83 (Exists fun Xx => Exists fun Xf => ∀ (Xy : Iota), And (∀ (Xz : Iota), cP Xz (Xf Xx)) (cP Xx Xy) → cP Xy (g (h Xy))))
% 3.66/3.83 True
% 3.66/3.83 Clause #1 (by clausification #[0]): Eq (Exists fun Xx => Exists fun Xf => ∀ (Xy : Iota), And (∀ (Xz : Iota), cP Xz (Xf Xx)) (cP Xx Xy) → cP Xy (g (h Xy)))
% 3.66/3.83 False
% 3.66/3.83 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (Exists fun Xf => ∀ (Xy : Iota), And (∀ (Xz : Iota), cP Xz (Xf a)) (cP a Xy) → cP Xy (g (h Xy))) False
% 3.66/3.83 Clause #3 (by clausification #[2]): ∀ (a : Iota → Iota) (a_1 : Iota),
% 3.66/3.83 Eq (∀ (Xy : Iota), And (∀ (Xz : Iota), cP Xz (a a_1)) (cP a_1 Xy) → cP Xy (g (h Xy))) False
% 3.66/3.83 Clause #4 (by clausification #[3]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota),
% 3.66/3.83 Eq
% 3.66/3.83 (Not
% 3.66/3.83 (And (∀ (Xz : Iota), cP Xz (a a_1)) (cP a_1 (skS.0 0 a a_1 a_2)) →
% 3.66/3.83 cP (skS.0 0 a a_1 a_2) (g (h (skS.0 0 a a_1 a_2)))))
% 3.66/3.83 True
% 3.66/3.83 Clause #5 (by clausification #[4]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota),
% 3.66/3.83 Eq
% 3.66/3.83 (And (∀ (Xz : Iota), cP Xz (a a_1)) (cP a_1 (skS.0 0 a a_1 a_2)) →
% 3.66/3.83 cP (skS.0 0 a a_1 a_2) (g (h (skS.0 0 a a_1 a_2))))
% 3.66/3.83 False
% 3.66/3.83 Clause #6 (by clausification #[5]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Eq (And (∀ (Xz : Iota), cP Xz (a a_1)) (cP a_1 (skS.0 0 a a_1 a_2))) True
% 3.66/3.83 Clause #7 (by clausification #[5]): ∀ (a : Iota → Iota) (a_1 a_2 : Iota), Eq (cP (skS.0 0 a a_1 a_2) (g (h (skS.0 0 a a_1 a_2)))) False
% 3.66/3.83 Clause #9 (by clausification #[6]): ∀ (a : Iota → Iota) (a_1 : Iota), Eq (∀ (Xz : Iota), cP Xz (a a_1)) True
% 3.66/3.83 Clause #10 (by clausification #[9]): ∀ (a : Iota) (a_1 : Iota → Iota) (a_2 : Iota), Eq (cP a (a_1 a_2)) True
% 3.66/3.83 Clause #25 (by superposition #[7, 10]): Eq True False
% 3.66/3.83 Clause #27 (by clausification #[25]): False
% 3.66/3.83 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------