TSTP Solution File: SYO258^5 by cocATP---0.2.0
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%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO258^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:51:01 EDT 2022
% Result : Unknown 1.07s 1.25s
% Output : None
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11 % Problem : SYO258^5 : TPTP v7.5.0. Released v4.0.0.
% 0.07/0.12 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.32 % Computer : n008.cluster.edu
% 0.12/0.32 % Model : x86_64 x86_64
% 0.12/0.32 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32 % RAMPerCPU : 8042.1875MB
% 0.12/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.32 % CPULimit : 300
% 0.12/0.32 % DateTime : Fri Mar 11 22:24:02 EST 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.33 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.34 Python 2.7.5
% 1.07/1.23 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 1.07/1.23 FOF formula (<kernel.Constant object at 0x9a1fc8>, <kernel.Constant object at 0x9a1170>) of role type named a
% 1.07/1.23 Using role type
% 1.07/1.23 Declaring a:fofType
% 1.07/1.23 FOF formula (<kernel.Constant object at 0x9a24d0>, <kernel.DependentProduct object at 0x9a15f0>) of role type named cQ
% 1.07/1.23 Using role type
% 1.07/1.23 Declaring cQ:(fofType->((fofType->Prop)->Prop))
% 1.07/1.23 FOF formula (<kernel.Constant object at 0x9a11b8>, <kernel.DependentProduct object at 0x9a1440>) of role type named cP
% 1.07/1.23 Using role type
% 1.07/1.23 Declaring cP:(fofType->(fofType->Prop))
% 1.07/1.23 FOF formula (<kernel.Constant object at 0x9a1fc8>, <kernel.Single object at 0x9a1050>) of role type named b
% 1.07/1.23 Using role type
% 1.07/1.23 Declaring b:fofType
% 1.07/1.23 FOF formula (((and ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E)))->((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> (forall (Xg:fofType), ((A Xg)->((and ((ex fofType) (fun (Xx:fofType)=> ((and ((cP Xg) Xx)) ((cQ Xx) A))))) (A a))))))) of role conjecture named cBLEDSOE_FENG_6
% 1.07/1.23 Conjecture to prove = (((and ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E)))->((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> (forall (Xg:fofType), ((A Xg)->((and ((ex fofType) (fun (Xx:fofType)=> ((and ((cP Xg) Xx)) ((cQ Xx) A))))) (A a))))))):Prop
% 1.07/1.23 We need to prove ['(((and ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E)))->((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> (forall (Xg:fofType), ((A Xg)->((and ((ex fofType) (fun (Xx:fofType)=> ((and ((cP Xg) Xx)) ((cQ Xx) A))))) (A a)))))))']
% 1.07/1.23 Parameter fofType:Type.
% 1.07/1.23 Parameter a:fofType.
% 1.07/1.23 Parameter cQ:(fofType->((fofType->Prop)->Prop)).
% 1.07/1.23 Parameter cP:(fofType->(fofType->Prop)).
% 1.07/1.23 Parameter b:fofType.
% 1.07/1.23 Trying to prove (((and ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E)))->((ex (fofType->Prop)) (fun (A:(fofType->Prop))=> (forall (Xg:fofType), ((A Xg)->((and ((ex fofType) (fun (Xx:fofType)=> ((and ((cP Xg) Xx)) ((cQ Xx) A))))) (A a)))))))
% 1.07/1.23 Found x00:(x0 Xg)
% 1.07/1.23 Instantiate: x0:=(cP Xg):(fofType->Prop);x1:=Xg:fofType
% 1.07/1.23 Found x00 as proof of ((cP Xg) x1)
% 1.07/1.23 Found x00:(x2 Xg)
% 1.07/1.23 Instantiate: x2:=(cP Xg):(fofType->Prop);x3:=Xg:fofType
% 1.07/1.23 Found x00 as proof of ((cP Xg) x3)
% 1.07/1.23 Found x10:=(x1 x2):((cQ b) x2)
% 1.07/1.23 Found (x1 x2) as proof of ((cQ x3) x2)
% 1.07/1.23 Found (x1 x2) as proof of ((cQ x3) x2)
% 1.07/1.23 Found (x1 x2) as proof of ((cQ x3) x2)
% 1.07/1.23 Found x00:(x0 Xg)
% 1.07/1.23 Instantiate: x3:=Xg:fofType;x0:=(cP Xg):(fofType->Prop)
% 1.07/1.23 Found x00 as proof of ((cP Xg) x3)
% 1.07/1.23 Found x20:=(x2 x0):((cQ b) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found x00:(x0 Xg)
% 1.07/1.23 Instantiate: x3:=Xg:fofType;x0:=(cP Xg):(fofType->Prop)
% 1.07/1.23 Found x00 as proof of ((cP Xg) x3)
% 1.07/1.23 Found x20:=(x2 x0):((cQ b) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found (x2 x0) as proof of ((cQ x3) x0)
% 1.07/1.23 Found x00:(x0 Xg)
% 1.07/1.23 Instantiate: x0:=(cP Xg):(fofType->Prop);x1:=Xg:fofType
% 1.07/1.23 Found x00 as proof of ((cP Xg) x1)
% 1.07/1.23 Found x30:=(x3 x0):((cQ b) x0)
% 1.07/1.23 Found (x3 x0) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (x3 x0) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (x3 x0) as proof of ((cQ x1) x0)
% 1.07/1.23 Found x30:=(x3 x0):((cQ b) x0)
% 1.07/1.23 Found (x3 x0) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (x3 x0) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (fun (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0)) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0)) as proof of ((forall (E:(fofType->Prop)), ((cQ b) E))->((cQ x1) x0))
% 1.07/1.23 Found (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0)) as proof of (((cP a) b)->((forall (E:(fofType->Prop)), ((cQ b) E))->((cQ x1) x0)))
% 1.07/1.23 Found (and_rect00 (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0))) as proof of ((cQ x1) x0)
% 1.07/1.23 Found ((and_rect0 ((cQ x1) x0)) (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0))) as proof of ((cQ x1) x0)
% 1.07/1.23 Found (((fun (P:Type) (x2:(((cP a) b)->((forall (E:(fofType->Prop)), ((cQ b) E))->P)))=> (((((and_rect ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E))) P) x2) x)) ((cQ x1) x0)) (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0))) as proof of ((cQ x1) x0)
% 1.07/1.25 Found (((fun (P:Type) (x2:(((cP a) b)->((forall (E:(fofType->Prop)), ((cQ b) E))->P)))=> (((((and_rect ((cP a) b)) (forall (E:(fofType->Prop)), ((cQ b) E))) P) x2) x)) ((cQ x1) x0)) (fun (x2:((cP a) b)) (x3:(forall (E:(fofType->Prop)), ((cQ b) E)))=> (x3 x0))) as proof of ((cQ x1) x0)
% 1.07/1.25 % SZS status GaveUp for /export/starexec/sandbox2/benchmark/theBenchmark.p
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