TSTP Solution File: SYO253^5 by Satallax---3.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Satallax---3.5
% Problem  : SYO253^5 : TPTP v8.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 19:31:06 EDT 2022

% Result   : Theorem 0.19s 0.36s
% Output   : Proof 0.19s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SYO253^5 : TPTP v8.1.0. Released v4.0.0.
% 0.04/0.13  % Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
% 0.13/0.34  % Computer : n008.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Sat Jul  9 02:52:23 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.19/0.36  % SZS status Theorem
% 0.19/0.36  % Mode: mode213
% 0.19/0.36  % Inferences: 11
% 0.19/0.36  % SZS output start Proof
% 0.19/0.36  thf(ty_p, type, p : $o).
% 0.19/0.36  thf(sP1,plain,sP1 <=> p,introduced(definition,[new_symbols(definition,[sP1])])).
% 0.19/0.36  thf(sP2,plain,sP2 <=> ((~(sP1)) => (~(sP1))),introduced(definition,[new_symbols(definition,[sP2])])).
% 0.19/0.36  thf(sP3,plain,sP3 <=> ((~((sP1 => sP1))) = sP2),introduced(definition,[new_symbols(definition,[sP3])])).
% 0.19/0.36  thf(sP4,plain,sP4 <=> (sP1 => sP1),introduced(definition,[new_symbols(definition,[sP4])])).
% 0.19/0.36  thf(cTHM124,conjecture,(~((![X1:$o>$o]:((X1 @ (~(sP4))) => (X1 @ sP2)))))).
% 0.19/0.36  thf(h0,negated_conjecture,(![X1:$o>$o]:((X1 @ (~(sP4))) => (X1 @ sP2))),inference(assume_negation,[status(cth)],[cTHM124])).
% 0.19/0.36  thf(1,plain,(sP2 | sP1),inference(prop_rule,[status(thm)],[])).
% 0.19/0.36  thf(2,plain,(sP2 | ~(sP1)),inference(prop_rule,[status(thm)],[])).
% 0.19/0.36  thf(3,plain,(sP4 | ~(sP1)),inference(prop_rule,[status(thm)],[])).
% 0.19/0.36  thf(4,plain,(sP4 | sP1),inference(prop_rule,[status(thm)],[])).
% 0.19/0.36  thf(5,plain,((~(sP3) | ~(sP4)) | ~(sP2)),inference(prop_rule,[status(thm)],[])).
% 0.19/0.36  thf(6,plain,sP3,inference(normalize,[status(thm)],[h0]).
% 0.19/0.36  thf(7,plain,$false,inference(prop_unsat,[status(thm),assumptions([h0])],[1,2,3,4,5,6])).
% 0.19/0.36  thf(0,theorem,(~((![X1:$o>$o]:((X1 @ (~(sP4))) => (X1 @ sP2))))),inference(contra,[status(thm),contra(discharge,[h0])],[7,h0])).
% 0.19/0.36  % SZS output end Proof
%------------------------------------------------------------------------------