TSTP Solution File: SYO147^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO147^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:21:39 EDT 2023
% Result : Theorem 3.42s 3.63s
% Output : Proof 3.42s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.13 % Problem : SYO147^5 : TPTP v8.1.2. Released v4.0.0.
% 0.14/0.15 % Command : duper %s
% 0.14/0.36 % Computer : n031.cluster.edu
% 0.14/0.36 % Model : x86_64 x86_64
% 0.14/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.36 % Memory : 8042.1875MB
% 0.14/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.36 % CPULimit : 300
% 0.14/0.36 % WCLimit : 300
% 0.14/0.36 % DateTime : Sat Aug 26 03:47:07 EDT 2023
% 0.14/0.36 % CPUTime :
% 3.42/3.63 SZS status Theorem for theBenchmark.p
% 3.42/3.63 SZS output start Proof for theBenchmark.p
% 3.42/3.63 Clause #0 (by assumption #[]): Eq (Not (Exists fun Xy => ∀ (Xx : Iota), And (And (cP1 Xx) (cP1 Xy → cP2 Xx)) (cP2 Xy → cP3 Xx) → cP3 Xy)) True
% 3.42/3.63 Clause #1 (by clausification #[0]): Eq (Exists fun Xy => ∀ (Xx : Iota), And (And (cP1 Xx) (cP1 Xy → cP2 Xx)) (cP2 Xy → cP3 Xx) → cP3 Xy) False
% 3.42/3.63 Clause #2 (by clausification #[1]): ∀ (a : Iota), Eq (∀ (Xx : Iota), And (And (cP1 Xx) (cP1 a → cP2 Xx)) (cP2 a → cP3 Xx) → cP3 a) False
% 3.42/3.63 Clause #3 (by clausification #[2]): ∀ (a a_1 : Iota),
% 3.42/3.63 Eq (Not (And (And (cP1 (skS.0 0 a a_1)) (cP1 a → cP2 (skS.0 0 a a_1))) (cP2 a → cP3 (skS.0 0 a a_1)) → cP3 a)) True
% 3.42/3.63 Clause #4 (by clausification #[3]): ∀ (a a_1 : Iota),
% 3.42/3.63 Eq (And (And (cP1 (skS.0 0 a a_1)) (cP1 a → cP2 (skS.0 0 a a_1))) (cP2 a → cP3 (skS.0 0 a a_1)) → cP3 a) False
% 3.42/3.63 Clause #5 (by clausification #[4]): ∀ (a a_1 : Iota), Eq (And (And (cP1 (skS.0 0 a a_1)) (cP1 a → cP2 (skS.0 0 a a_1))) (cP2 a → cP3 (skS.0 0 a a_1))) True
% 3.42/3.63 Clause #6 (by clausification #[4]): ∀ (a : Iota), Eq (cP3 a) False
% 3.42/3.63 Clause #7 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (cP2 a → cP3 (skS.0 0 a a_1)) True
% 3.42/3.63 Clause #8 (by clausification #[5]): ∀ (a a_1 : Iota), Eq (And (cP1 (skS.0 0 a a_1)) (cP1 a → cP2 (skS.0 0 a a_1))) True
% 3.42/3.63 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (cP2 a) False) (Eq (cP3 (skS.0 0 a a_1)) True)
% 3.42/3.63 Clause #10 (by clausification #[8]): ∀ (a a_1 : Iota), Eq (cP1 a → cP2 (skS.0 0 a a_1)) True
% 3.42/3.63 Clause #11 (by clausification #[8]): ∀ (a a_1 : Iota), Eq (cP1 (skS.0 0 a a_1)) True
% 3.42/3.63 Clause #12 (by clausification #[10]): ∀ (a a_1 : Iota), Or (Eq (cP1 a) False) (Eq (cP2 (skS.0 0 a a_1)) True)
% 3.42/3.63 Clause #13 (by superposition #[11, 12]): ∀ (a a_1 a_2 : Iota), Or (Eq (cP2 (skS.0 0 (skS.0 0 a a_1) a_2)) True) (Eq False True)
% 3.42/3.63 Clause #14 (by clausification #[13]): ∀ (a a_1 a_2 : Iota), Eq (cP2 (skS.0 0 (skS.0 0 a a_1) a_2)) True
% 3.42/3.63 Clause #15 (by superposition #[14, 9]): ∀ (a a_1 a_2 a_3 : Iota), Or (Eq True False) (Eq (cP3 (skS.0 0 (skS.0 0 (skS.0 0 a a_1) a_2) a_3)) True)
% 3.42/3.63 Clause #16 (by clausification #[15]): ∀ (a a_1 a_2 a_3 : Iota), Eq (cP3 (skS.0 0 (skS.0 0 (skS.0 0 a a_1) a_2) a_3)) True
% 3.42/3.63 Clause #17 (by superposition #[16, 6]): Eq True False
% 3.42/3.63 Clause #18 (by clausification #[17]): False
% 3.42/3.63 SZS output end Proof for theBenchmark.p
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