TSTP Solution File: SYO135^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO135^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:21:37 EDT 2023
% Result : Theorem 3.34s 3.56s
% Output : Proof 3.34s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO135^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.14 % Command : duper %s
% 0.14/0.34 % Computer : n008.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Sat Aug 26 06:26:17 EDT 2023
% 0.14/0.34 % CPUTime :
% 3.34/3.56 SZS status Theorem for theBenchmark.p
% 3.34/3.56 SZS output start Proof for theBenchmark.p
% 3.34/3.56 Clause #0 (by assumption #[]): Eq (Not (Or (∀ (Xx0 : Iota), cP Xx0) (cQ x) → Or (And (cP a) (cP b)) (cQ x))) True
% 3.34/3.56 Clause #1 (by clausification #[0]): Eq (Or (∀ (Xx0 : Iota), cP Xx0) (cQ x) → Or (And (cP a) (cP b)) (cQ x)) False
% 3.34/3.56 Clause #2 (by clausification #[1]): Eq (Or (∀ (Xx0 : Iota), cP Xx0) (cQ x)) True
% 3.34/3.56 Clause #3 (by clausification #[1]): Eq (Or (And (cP a) (cP b)) (cQ x)) False
% 3.34/3.56 Clause #4 (by clausification #[2]): Or (Eq (∀ (Xx0 : Iota), cP Xx0) True) (Eq (cQ x) True)
% 3.34/3.56 Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (cQ x) True) (Eq (cP a) True)
% 3.34/3.56 Clause #6 (by clausification #[3]): Eq (cQ x) False
% 3.34/3.56 Clause #7 (by clausification #[3]): Eq (And (cP a) (cP b)) False
% 3.34/3.56 Clause #8 (by superposition #[6, 5]): ∀ (a : Iota), Or (Eq False True) (Eq (cP a) True)
% 3.34/3.56 Clause #9 (by clausification #[8]): ∀ (a : Iota), Eq (cP a) True
% 3.34/3.56 Clause #10 (by clausification #[7]): Or (Eq (cP a) False) (Eq (cP b) False)
% 3.34/3.56 Clause #11 (by forward demodulation #[10, 9]): Or (Eq True False) (Eq (cP b) False)
% 3.34/3.56 Clause #12 (by clausification #[11]): Eq (cP b) False
% 3.34/3.56 Clause #13 (by superposition #[12, 9]): Eq False True
% 3.34/3.56 Clause #14 (by clausification #[13]): False
% 3.34/3.56 SZS output end Proof for theBenchmark.p
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