TSTP Solution File: SYO132^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO132^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n031.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:36 EDT 2023

% Result   : Theorem 3.48s 3.71s
% Output   : Proof 3.48s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12  % Problem    : SYO132^5 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n031.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 01:07:22 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.48/3.71  SZS status Theorem for theBenchmark.p
% 3.48/3.71  SZS output start Proof for theBenchmark.p
% 3.48/3.71  Clause #0 (by assumption #[]): Eq (Not (And (And (cP cS) (cT cX)) (Eq cS cT) → And (cP cT) (cS cX))) True
% 3.48/3.71  Clause #1 (by clausification #[0]): Eq (And (And (cP cS) (cT cX)) (Eq cS cT) → And (cP cT) (cS cX)) False
% 3.48/3.71  Clause #2 (by clausification #[1]): Eq (And (And (cP cS) (cT cX)) (Eq cS cT)) True
% 3.48/3.71  Clause #3 (by clausification #[1]): Eq (And (cP cT) (cS cX)) False
% 3.48/3.71  Clause #4 (by clausification #[2]): Eq (Eq cS cT) True
% 3.48/3.71  Clause #5 (by clausification #[2]): Eq (And (cP cS) (cT cX)) True
% 3.48/3.71  Clause #6 (by clausification #[4]): Eq cS cT
% 3.48/3.71  Clause #7 (by argument congruence #[6]): ∀ (a : Iota), Eq (cS a) (cT a)
% 3.48/3.71  Clause #10 (by clausification #[5]): Eq (cT cX) True
% 3.48/3.71  Clause #11 (by clausification #[5]): Eq (cP cS) True
% 3.48/3.71  Clause #12 (by forward demodulation #[11, 6]): Eq (cP cT) True
% 3.48/3.71  Clause #13 (by clausification #[3]): Or (Eq (cP cT) False) (Eq (cS cX) False)
% 3.48/3.71  Clause #14 (by forward demodulation #[13, 7]): Or (Eq (cP cT) False) (Eq (cT cX) False)
% 3.48/3.71  Clause #15 (by forward demodulation #[14, 10]): Or (Eq (cP cT) False) (Eq True False)
% 3.48/3.71  Clause #16 (by clausification #[15]): Eq (cP cT) False
% 3.48/3.71  Clause #17 (by superposition #[16, 12]): Eq False True
% 3.48/3.71  Clause #19 (by clausification #[17]): False
% 3.48/3.71  SZS output end Proof for theBenchmark.p
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