TSTP Solution File: SYO132^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO132^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n031.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:21:36 EDT 2023
% Result : Theorem 3.48s 3.71s
% Output : Proof 3.48s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : SYO132^5 : TPTP v8.1.2. Released v4.0.0.
% 0.12/0.13 % Command : duper %s
% 0.13/0.34 % Computer : n031.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Sat Aug 26 01:07:22 EDT 2023
% 0.13/0.34 % CPUTime :
% 3.48/3.71 SZS status Theorem for theBenchmark.p
% 3.48/3.71 SZS output start Proof for theBenchmark.p
% 3.48/3.71 Clause #0 (by assumption #[]): Eq (Not (And (And (cP cS) (cT cX)) (Eq cS cT) → And (cP cT) (cS cX))) True
% 3.48/3.71 Clause #1 (by clausification #[0]): Eq (And (And (cP cS) (cT cX)) (Eq cS cT) → And (cP cT) (cS cX)) False
% 3.48/3.71 Clause #2 (by clausification #[1]): Eq (And (And (cP cS) (cT cX)) (Eq cS cT)) True
% 3.48/3.71 Clause #3 (by clausification #[1]): Eq (And (cP cT) (cS cX)) False
% 3.48/3.71 Clause #4 (by clausification #[2]): Eq (Eq cS cT) True
% 3.48/3.71 Clause #5 (by clausification #[2]): Eq (And (cP cS) (cT cX)) True
% 3.48/3.71 Clause #6 (by clausification #[4]): Eq cS cT
% 3.48/3.71 Clause #7 (by argument congruence #[6]): ∀ (a : Iota), Eq (cS a) (cT a)
% 3.48/3.71 Clause #10 (by clausification #[5]): Eq (cT cX) True
% 3.48/3.71 Clause #11 (by clausification #[5]): Eq (cP cS) True
% 3.48/3.71 Clause #12 (by forward demodulation #[11, 6]): Eq (cP cT) True
% 3.48/3.71 Clause #13 (by clausification #[3]): Or (Eq (cP cT) False) (Eq (cS cX) False)
% 3.48/3.71 Clause #14 (by forward demodulation #[13, 7]): Or (Eq (cP cT) False) (Eq (cT cX) False)
% 3.48/3.71 Clause #15 (by forward demodulation #[14, 10]): Or (Eq (cP cT) False) (Eq True False)
% 3.48/3.71 Clause #16 (by clausification #[15]): Eq (cP cT) False
% 3.48/3.71 Clause #17 (by superposition #[16, 12]): Eq False True
% 3.48/3.71 Clause #19 (by clausification #[17]): False
% 3.48/3.71 SZS output end Proof for theBenchmark.p
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