TSTP Solution File: SYO131^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SYO131^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Tue Mar 29 00:50:42 EDT 2022

% Result   : Theorem 0.48s 0.66s
% Output   : Proof 0.48s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem    : SYO131^5 : TPTP v7.5.0. Released v4.0.0.
% 0.07/0.12  % Command    : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.13/0.33  % Computer   : n015.cluster.edu
% 0.13/0.33  % Model      : x86_64 x86_64
% 0.13/0.33  % CPUModel   : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % RAMPerCPU  : 8042.1875MB
% 0.13/0.33  % OS         : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit   : 300
% 0.13/0.33  % DateTime   : Fri Mar 11 16:04:03 EST 2022
% 0.13/0.33  % CPUTime    : 
% 0.13/0.34  ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.13/0.34  Python 2.7.5
% 0.48/0.66  Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.48/0.66  FOF formula (<kernel.Constant object at 0x24cd2d8>, <kernel.DependentProduct object at 0x24cd908>) of role type named f
% 0.48/0.66  Using role type
% 0.48/0.66  Declaring f:(fofType->fofType)
% 0.48/0.66  FOF formula (<kernel.Constant object at 0x24d1ea8>, <kernel.DependentProduct object at 0x24cd908>) of role type named cR
% 0.48/0.66  Using role type
% 0.48/0.66  Declaring cR:(fofType->(fofType->Prop))
% 0.48/0.66  FOF formula (<kernel.Constant object at 0x24cd518>, <kernel.Single object at 0x24cdab8>) of role type named a
% 0.48/0.66  Using role type
% 0.48/0.66  Declaring a:fofType
% 0.48/0.66  FOF formula (<kernel.Constant object at 0x24cddd0>, <kernel.DependentProduct object at 0x24aad88>) of role type named g
% 0.48/0.66  Using role type
% 0.48/0.66  Declaring g:(fofType->fofType)
% 0.48/0.66  FOF formula (((cR (g (f a))) (f (g (f a))))->((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))) of role conjecture named cEXAMPLE1
% 0.48/0.66  Conjecture to prove = (((cR (g (f a))) (f (g (f a))))->((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))):Prop
% 0.48/0.66  We need to prove ['(((cR (g (f a))) (f (g (f a))))->((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))))']
% 0.48/0.66  Parameter fofType:Type.
% 0.48/0.66  Parameter f:(fofType->fofType).
% 0.48/0.66  Parameter cR:(fofType->(fofType->Prop)).
% 0.48/0.66  Parameter a:fofType.
% 0.48/0.66  Parameter g:(fofType->fofType).
% 0.48/0.66  Trying to prove (((cR (g (f a))) (f (g (f a))))->((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))))
% 0.48/0.66  Found x:((cR (g (f a))) (f (g (f a))))
% 0.48/0.66  Found x as proof of ((cR (g (f a))) (f (g (f a))))
% 0.48/0.66  Found (ex_intro000 x) as proof of ((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))
% 0.48/0.66  Found ((ex_intro00 (g (f a))) x) as proof of ((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))
% 0.48/0.66  Found (((ex_intro0 (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x) as proof of ((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))
% 0.48/0.66  Found ((((ex_intro fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x) as proof of ((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))
% 0.48/0.66  Found (fun (x:((cR (g (f a))) (f (g (f a)))))=> ((((ex_intro fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x)) as proof of ((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx))))
% 0.48/0.66  Found (fun (x:((cR (g (f a))) (f (g (f a)))))=> ((((ex_intro fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x)) as proof of (((cR (g (f a))) (f (g (f a))))->((ex fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))))
% 0.48/0.66  Got proof (fun (x:((cR (g (f a))) (f (g (f a)))))=> ((((ex_intro fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x))
% 0.48/0.66  Time elapsed = 0.052021s
% 0.48/0.66  node=7 cost=314.000000 depth=6
% 0.48/0.66  ::::::::::::::::::::::
% 0.48/0.66  % SZS status Theorem for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.48/0.66  % SZS output start Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.48/0.66  (fun (x:((cR (g (f a))) (f (g (f a)))))=> ((((ex_intro fofType) (fun (Xx:fofType)=> ((cR Xx) (f Xx)))) (g (f a))) x))
% 0.48/0.66  % SZS output end Proof for /export/starexec/sandbox2/benchmark/theBenchmark.p
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