%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYO125^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n009.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:35 EDT 2023

% Result   : Theorem 3.34s 3.50s
% Output   : Proof 3.34s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.08/0.14  % Problem    : SYO125^5 : TPTP v8.1.2. Released v4.0.0.
% 0.08/0.15  % Command    : duper %s
% 0.15/0.37  % Computer : n009.cluster.edu
% 0.15/0.37  % Model    : x86_64 x86_64
% 0.15/0.37  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.37  % Memory   : 8042.1875MB
% 0.15/0.37  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.15/0.37  % CPULimit   : 300
% 0.15/0.37  % WCLimit    : 300
% 0.15/0.37  % DateTime   : Sat Aug 26 01:32:36 EDT 2023
% 0.15/0.37  % CPUTime    : 
% 3.34/3.50  SZS status Theorem for theBenchmark.p
% 3.34/3.50  SZS output start Proof for theBenchmark.p
% 3.34/3.50  Clause #0 (by assumption #[]): Eq (Not (And (Iff cP cQ) (Iff cQ cR) → Iff cP cR)) True
% 3.34/3.50  Clause #1 (by clausification #[0]): Eq (And (Iff cP cQ) (Iff cQ cR) → Iff cP cR) False
% 3.34/3.50  Clause #2 (by clausification #[1]): Eq (And (Iff cP cQ) (Iff cQ cR)) True
% 3.34/3.50  Clause #3 (by clausification #[1]): Eq (Iff cP cR) False
% 3.34/3.50  Clause #4 (by clausification #[2]): Eq (Iff cQ cR) True
% 3.34/3.50  Clause #5 (by clausification #[2]): Eq (Iff cP cQ) True
% 3.34/3.50  Clause #6 (by clausification #[4]): Or (Eq cQ True) (Eq cR False)
% 3.34/3.50  Clause #7 (by clausification #[4]): Or (Eq cQ False) (Eq cR True)
% 3.34/3.50  Clause #8 (by clausification #[5]): Or (Eq cP True) (Eq cQ False)
% 3.34/3.50  Clause #9 (by clausification #[5]): Or (Eq cP False) (Eq cQ True)
% 3.34/3.50  Clause #10 (by clausification #[3]): Or (Eq cP False) (Eq cR False)
% 3.34/3.50  Clause #11 (by clausification #[3]): Or (Eq cP True) (Eq cR True)
% 3.34/3.50  Clause #12 (by superposition #[11, 6]): Or (Eq cP True) (Or (Eq cQ True) (Eq True False))
% 3.34/3.50  Clause #13 (by clausification #[12]): Or (Eq cP True) (Eq cQ True)
% 3.34/3.50  Clause #14 (by superposition #[13, 9]): Or (Eq cQ True) (Or (Eq True False) (Eq cQ True))
% 3.34/3.50  Clause #16 (by clausification #[14]): Or (Eq cQ True) (Eq cQ True)
% 3.34/3.50  Clause #17 (by eliminate duplicate literals #[16]): Eq cQ True
% 3.34/3.50  Clause #19 (by backward demodulation #[17, 7]): Or (Eq True False) (Eq cR True)
% 3.34/3.50  Clause #20 (by backward demodulation #[17, 8]): Or (Eq cP True) (Eq True False)
% 3.34/3.50  Clause #23 (by clausification #[20]): Eq cP True
% 3.34/3.50  Clause #24 (by backward demodulation #[23, 10]): Or (Eq True False) (Eq cR False)
% 3.34/3.50  Clause #26 (by clausification #[24]): Eq cR False
% 3.34/3.50  Clause #27 (by clausification #[19]): Eq cR True
% 3.34/3.50  Clause #28 (by superposition #[27, 26]): Eq True False
% 3.34/3.50  Clause #29 (by clausification #[28]): False
% 3.34/3.50  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------