TSTP Solution File: SYO123^5 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SYO123^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:41 EDT 2022
% Result : Theorem 0.45s 0.68s
% Output : Proof 0.45s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.15 % Problem : SYO123^5 : TPTP v7.5.0. Released v4.0.0.
% 0.07/0.16 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.37 % Computer : n029.cluster.edu
% 0.12/0.37 % Model : x86_64 x86_64
% 0.12/0.37 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.37 % RAMPerCPU : 8042.1875MB
% 0.12/0.37 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.37 % CPULimit : 300
% 0.12/0.37 % DateTime : Fri Mar 11 15:50:15 EST 2022
% 0.12/0.37 % CPUTime :
% 0.12/0.38 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.39 Python 2.7.5
% 0.45/0.68 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.45/0.68 FOF formula (<kernel.Constant object at 0x1d6e758>, <kernel.Constant object at 0x1d6ed40>) of role type named b
% 0.45/0.68 Using role type
% 0.45/0.68 Declaring b:fofType
% 0.45/0.68 FOF formula (<kernel.Constant object at 0x1d72e18>, <kernel.DependentProduct object at 0x1d6e878>) of role type named cP
% 0.45/0.68 Using role type
% 0.45/0.68 Declaring cP:(fofType->Prop)
% 0.45/0.68 FOF formula (<kernel.Constant object at 0x1d6e758>, <kernel.Single object at 0x1d6e098>) of role type named a
% 0.45/0.68 Using role type
% 0.45/0.68 Declaring a:fofType
% 0.45/0.68 FOF formula ((forall (Xx:fofType), (cP Xx))->((and (cP a)) (cP b))) of role conjecture named cALLCONJ2
% 0.45/0.68 Conjecture to prove = ((forall (Xx:fofType), (cP Xx))->((and (cP a)) (cP b))):Prop
% 0.45/0.68 We need to prove ['((forall (Xx:fofType), (cP Xx))->((and (cP a)) (cP b)))']
% 0.45/0.68 Parameter fofType:Type.
% 0.45/0.68 Parameter b:fofType.
% 0.45/0.68 Parameter cP:(fofType->Prop).
% 0.45/0.68 Parameter a:fofType.
% 0.45/0.68 Trying to prove ((forall (Xx:fofType), (cP Xx))->((and (cP a)) (cP b)))
% 0.45/0.68 Found x0:=(x a):(cP a)
% 0.45/0.68 Found (x a) as proof of (cP a)
% 0.45/0.68 Found (x a) as proof of (cP a)
% 0.45/0.68 Found x0:=(x b):(cP b)
% 0.45/0.68 Found (x b) as proof of (cP b)
% 0.45/0.68 Found (x b) as proof of (cP b)
% 0.45/0.68 Found ((conj00 (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.45/0.68 Found (((conj0 (cP b)) (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.45/0.68 Found ((((conj (cP a)) (cP b)) (x a)) (x b)) as proof of ((and (cP a)) (cP b))
% 0.45/0.68 Found (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj (cP a)) (cP b)) (x a)) (x b))) as proof of ((and (cP a)) (cP b))
% 0.45/0.68 Found (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj (cP a)) (cP b)) (x a)) (x b))) as proof of ((forall (Xx:fofType), (cP Xx))->((and (cP a)) (cP b)))
% 0.45/0.68 Got proof (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj (cP a)) (cP b)) (x a)) (x b)))
% 0.45/0.68 Time elapsed = 0.030470s
% 0.45/0.68 node=8 cost=13.000000 depth=6
% 0.45/0.68 ::::::::::::::::::::::
% 0.45/0.68 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.45/0.68 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.45/0.68 (fun (x:(forall (Xx:fofType), (cP Xx)))=> ((((conj (cP a)) (cP b)) (x a)) (x b)))
% 0.45/0.68 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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