TSTP Solution File: SYO121^5 by cocATP---0.2.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : cocATP---0.2.0
% Problem : SYO121^5 : TPTP v7.5.0. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:41 EDT 2022
% Result : Unknown 0.48s 0.64s
% Output : None
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----No solution output by system
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.11 % Problem : SYO121^5 : TPTP v7.5.0. Released v4.0.0.
% 0.10/0.12 % Command : python CASC.py /export/starexec/sandbox2/benchmark/theBenchmark.p
% 0.12/0.32 % Computer : n029.cluster.edu
% 0.12/0.32 % Model : x86_64 x86_64
% 0.12/0.32 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.32 % RAMPerCPU : 8042.1875MB
% 0.12/0.32 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Fri Mar 11 15:44:45 EST 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.33 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.34 Python 2.7.5
% 0.48/0.64 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox2/benchmark/', '/export/starexec/sandbox2/benchmark/']
% 0.48/0.64 FOF formula (<kernel.Constant object at 0x22a53f8>, <kernel.DependentProduct object at 0x22a5b48>) of role type named cQ
% 0.48/0.64 Using role type
% 0.48/0.64 Declaring cQ:(fofType->(fofType->(fofType->Prop)))
% 0.48/0.64 FOF formula ((ex fofType) (fun (E:fofType)=> (forall (K:fofType), (((cQ K) E) K)))) of role conjecture named cTHM27
% 0.48/0.64 Conjecture to prove = ((ex fofType) (fun (E:fofType)=> (forall (K:fofType), (((cQ K) E) K)))):Prop
% 0.48/0.64 Parameter fofType_DUMMY:fofType.
% 0.48/0.64 We need to prove ['((ex fofType) (fun (E:fofType)=> (forall (K:fofType), (((cQ K) E) K))))']
% 0.48/0.64 Parameter fofType:Type.
% 0.48/0.64 Parameter cQ:(fofType->(fofType->(fofType->Prop))).
% 0.48/0.64 Trying to prove ((ex fofType) (fun (E:fofType)=> (forall (K:fofType), (((cQ K) E) K))))
% 0.48/0.64 % SZS status GaveUp for /export/starexec/sandbox2/benchmark/theBenchmark.p
%------------------------------------------------------------------------------