TSTP Solution File: SYO098^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SYO098^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 04:21:30 EDT 2023
% Result : Theorem 3.63s 3.85s
% Output : Proof 3.63s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SYO098^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.17/0.34 % Computer : n016.cluster.edu
% 0.17/0.34 % Model : x86_64 x86_64
% 0.17/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.17/0.34 % Memory : 8042.1875MB
% 0.17/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.17/0.34 % CPULimit : 300
% 0.17/0.34 % WCLimit : 300
% 0.17/0.34 % DateTime : Sat Aug 26 03:26:56 EDT 2023
% 0.17/0.35 % CPUTime :
% 3.63/3.85 SZS status Theorem for theBenchmark.p
% 3.63/3.85 SZS output start Proof for theBenchmark.p
% 3.63/3.85 Clause #0 (by assumption #[]): Eq
% 3.63/3.85 (Not
% 3.63/3.85 ((∀ (W : Iota), Not (cR W W)) → Exists fun X => Exists fun Y => And (Not (cR X Y)) (cQ Y X → ∀ (Z : Iota), cQ Z Z)))
% 3.63/3.85 True
% 3.63/3.85 Clause #1 (by clausification #[0]): Eq ((∀ (W : Iota), Not (cR W W)) → Exists fun X => Exists fun Y => And (Not (cR X Y)) (cQ Y X → ∀ (Z : Iota), cQ Z Z))
% 3.63/3.85 False
% 3.63/3.85 Clause #2 (by clausification #[1]): Eq (∀ (W : Iota), Not (cR W W)) True
% 3.63/3.85 Clause #3 (by clausification #[1]): Eq (Exists fun X => Exists fun Y => And (Not (cR X Y)) (cQ Y X → ∀ (Z : Iota), cQ Z Z)) False
% 3.63/3.85 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (Not (cR a a)) True
% 3.63/3.85 Clause #5 (by clausification #[4]): ∀ (a : Iota), Eq (cR a a) False
% 3.63/3.85 Clause #6 (by clausification #[3]): ∀ (a : Iota), Eq (Exists fun Y => And (Not (cR a Y)) (cQ Y a → ∀ (Z : Iota), cQ Z Z)) False
% 3.63/3.85 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (And (Not (cR a a_1)) (cQ a_1 a → ∀ (Z : Iota), cQ Z Z)) False
% 3.63/3.85 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (Not (cR a a_1)) False) (Eq (cQ a_1 a → ∀ (Z : Iota), cQ Z Z) False)
% 3.63/3.85 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq (cQ a a_1 → ∀ (Z : Iota), cQ Z Z) False) (Eq (cR a_1 a) True)
% 3.63/3.85 Clause #10 (by clausification #[9]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) True) (Eq (cQ a_1 a) True)
% 3.63/3.85 Clause #11 (by clausification #[9]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) True) (Eq (∀ (Z : Iota), cQ Z Z) False)
% 3.63/3.85 Clause #12 (by clausification #[11]): ∀ (a a_1 a_2 : Iota), Or (Eq (cR a a_1) True) (Eq (Not (cQ (skS.0 0 a_2) (skS.0 0 a_2))) True)
% 3.63/3.85 Clause #13 (by clausification #[12]): ∀ (a a_1 a_2 : Iota), Or (Eq (cR a a_1) True) (Eq (cQ (skS.0 0 a_2) (skS.0 0 a_2)) False)
% 3.63/3.85 Clause #14 (by superposition #[13, 10]): ∀ (a a_1 a_2 : Iota), Or (Eq (cR a a_1) True) (Or (Eq (cR (skS.0 0 a_2) (skS.0 0 a_2)) True) (Eq False True))
% 3.63/3.85 Clause #15 (by clausification #[14]): ∀ (a a_1 a_2 : Iota), Or (Eq (cR a a_1) True) (Eq (cR (skS.0 0 a_2) (skS.0 0 a_2)) True)
% 3.63/3.85 Clause #17 (by superposition #[15, 5]): ∀ (a a_1 : Iota), Or (Eq (cR a a_1) True) (Eq True False)
% 3.63/3.85 Clause #19 (by clausification #[17]): ∀ (a a_1 : Iota), Eq (cR a a_1) True
% 3.63/3.85 Clause #21 (by superposition #[19, 5]): Eq True False
% 3.63/3.85 Clause #23 (by clausification #[21]): False
% 3.63/3.85 SZS output end Proof for theBenchmark.p
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