TSTP Solution File: SYO080^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO080^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n007.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:26 EDT 2023

% Result   : Theorem 3.38s 3.63s
% Output   : Proof 3.38s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.10/0.12  % Problem    : SYO080^5 : TPTP v8.1.2. Released v4.0.0.
% 0.10/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n007.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 05:14:26 EDT 2023
% 0.13/0.34  % CPUTime    : 
% 3.38/3.63  SZS status Theorem for theBenchmark.p
% 3.38/3.63  SZS output start Proof for theBenchmark.p
% 3.38/3.63  Clause #0 (by assumption #[]): Eq (Not (((((cA → cB) → cA) → cA) → cB) → cB)) True
% 3.38/3.63  Clause #1 (by clausification #[0]): Eq (((((cA → cB) → cA) → cA) → cB) → cB) False
% 3.38/3.63  Clause #2 (by clausification #[1]): Eq ((((cA → cB) → cA) → cA) → cB) True
% 3.38/3.63  Clause #3 (by clausification #[1]): Eq cB False
% 3.38/3.63  Clause #4 (by clausification #[2]): Or (Eq (((cA → cB) → cA) → cA) False) (Eq cB True)
% 3.38/3.63  Clause #5 (by clausification #[4]): Or (Eq cB True) (Eq ((cA → cB) → cA) True)
% 3.38/3.63  Clause #6 (by clausification #[4]): Or (Eq cB True) (Eq cA False)
% 3.38/3.63  Clause #7 (by clausification #[5]): Or (Eq cB True) (Or (Eq (cA → cB) False) (Eq cA True))
% 3.38/3.63  Clause #8 (by clausification #[7]): Or (Eq cB True) (Or (Eq cA True) (Eq cA True))
% 3.38/3.63  Clause #10 (by eliminate duplicate literals #[8]): Or (Eq cB True) (Eq cA True)
% 3.38/3.63  Clause #11 (by superposition #[3, 10]): Or (Eq cA True) (Eq True False)
% 3.38/3.63  Clause #12 (by clausification #[11]): Eq cA True
% 3.38/3.63  Clause #14 (by backward demodulation #[12, 6]): Or (Eq cB True) (Eq True False)
% 3.38/3.63  Clause #15 (by clausification #[14]): Eq cB True
% 3.38/3.63  Clause #16 (by superposition #[15, 3]): Eq True False
% 3.38/3.63  Clause #17 (by clausification #[16]): False
% 3.38/3.63  SZS output end Proof for theBenchmark.p
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