TSTP Solution File: SYO078^5 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO078^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:26 EDT 2023

% Result   : Theorem 3.40s 3.56s
% Output   : Proof 3.40s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.12  % Problem    : SYO078^5 : TPTP v8.1.2. Released v4.0.0.
% 0.11/0.13  % Command    : duper %s
% 0.13/0.34  % Computer : n017.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 300
% 0.13/0.34  % DateTime   : Sat Aug 26 07:12:55 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.40/3.56  SZS status Theorem for theBenchmark.p
% 3.40/3.56  SZS output start Proof for theBenchmark.p
% 3.40/3.56  Clause #0 (by assumption #[]): Eq (Not (Or (Or (Iff cP cQ) (Iff cQ cR)) (Iff cP cR))) True
% 3.40/3.56  Clause #1 (by clausification #[0]): Eq (Or (Or (Iff cP cQ) (Iff cQ cR)) (Iff cP cR)) False
% 3.40/3.56  Clause #2 (by clausification #[1]): Eq (Iff cP cR) False
% 3.40/3.56  Clause #3 (by clausification #[1]): Eq (Or (Iff cP cQ) (Iff cQ cR)) False
% 3.40/3.56  Clause #4 (by clausification #[2]): Or (Eq cP False) (Eq cR False)
% 3.40/3.56  Clause #5 (by clausification #[2]): Or (Eq cP True) (Eq cR True)
% 3.40/3.56  Clause #6 (by clausification #[3]): Eq (Iff cQ cR) False
% 3.40/3.56  Clause #7 (by clausification #[3]): Eq (Iff cP cQ) False
% 3.40/3.56  Clause #8 (by clausification #[6]): Or (Eq cQ False) (Eq cR False)
% 3.40/3.56  Clause #9 (by clausification #[6]): Or (Eq cQ True) (Eq cR True)
% 3.40/3.56  Clause #10 (by clausification #[7]): Or (Eq cP False) (Eq cQ False)
% 3.40/3.56  Clause #11 (by clausification #[7]): Or (Eq cP True) (Eq cQ True)
% 3.40/3.56  Clause #12 (by superposition #[11, 4]): Or (Eq cQ True) (Or (Eq True False) (Eq cR False))
% 3.40/3.56  Clause #15 (by clausification #[12]): Or (Eq cQ True) (Eq cR False)
% 3.40/3.56  Clause #17 (by superposition #[15, 9]): Or (Eq cQ True) (Or (Eq cQ True) (Eq False True))
% 3.40/3.56  Clause #18 (by clausification #[17]): Or (Eq cQ True) (Eq cQ True)
% 3.40/3.56  Clause #19 (by eliminate duplicate literals #[18]): Eq cQ True
% 3.40/3.56  Clause #20 (by backward demodulation #[19, 8]): Or (Eq True False) (Eq cR False)
% 3.40/3.56  Clause #22 (by backward demodulation #[19, 10]): Or (Eq cP False) (Eq True False)
% 3.40/3.56  Clause #27 (by clausification #[22]): Eq cP False
% 3.40/3.56  Clause #29 (by backward demodulation #[27, 5]): Or (Eq False True) (Eq cR True)
% 3.40/3.56  Clause #30 (by clausification #[29]): Eq cR True
% 3.40/3.56  Clause #31 (by clausification #[20]): Eq cR False
% 3.40/3.56  Clause #32 (by superposition #[31, 30]): Eq False True
% 3.40/3.56  Clause #33 (by clausification #[32]): False
% 3.40/3.56  SZS output end Proof for theBenchmark.p
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