TSTP Solution File: SYO012^1 by Duper---1.0

View Problem - Process Solution

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% File     : Duper---1.0
% Problem  : SYO012^1 : TPTP v8.1.2. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 04:21:06 EDT 2023

% Result   : Theorem 3.58s 3.76s
% Output   : Proof 3.58s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem    : SYO012^1 : TPTP v8.1.2. Released v3.7.0.
% 0.00/0.13  % Command    : duper %s
% 0.13/0.35  % Computer : n003.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit   : 300
% 0.13/0.35  % WCLimit    : 300
% 0.13/0.35  % DateTime   : Sat Aug 26 00:31:38 EDT 2023
% 0.13/0.35  % CPUTime    : 
% 3.58/3.76  SZS status Theorem for theBenchmark.p
% 3.58/3.76  SZS output start Proof for theBenchmark.p
% 3.58/3.76  Clause #0 (by assumption #[]): Eq (Not (p (And a b) → p (And b a))) True
% 3.58/3.76  Clause #1 (by clausification #[0]): Eq (p (And a b) → p (And b a)) False
% 3.58/3.76  Clause #2 (by clausification #[1]): Eq (p (And a b)) True
% 3.58/3.76  Clause #3 (by clausification #[1]): Eq (p (And b a)) False
% 3.58/3.76  Clause #4 (by identity loobHoist #[2]): Or (Eq (p True) True) (Eq (And a b) False)
% 3.58/3.76  Clause #5 (by identity boolHoist #[2]): Or (Eq (p False) True) (Eq (And a b) True)
% 3.58/3.76  Clause #6 (by clausification #[4]): Or (Eq (p True) True) (Or (Eq a False) (Eq b False))
% 3.58/3.76  Clause #7 (by identity loobHoist #[3]): Or (Eq (p True) False) (Eq (And b a) False)
% 3.58/3.76  Clause #8 (by identity boolHoist #[3]): Or (Eq (p False) False) (Eq (And b a) True)
% 3.58/3.76  Clause #9 (by clausification #[7]): Or (Eq (p True) False) (Or (Eq b False) (Eq a False))
% 3.58/3.76  Clause #10 (by clausification #[8]): Or (Eq (p False) False) (Eq a True)
% 3.58/3.76  Clause #11 (by clausification #[8]): Or (Eq (p False) False) (Eq b True)
% 3.58/3.76  Clause #12 (by clausification #[5]): Or (Eq (p False) True) (Eq b True)
% 3.58/3.76  Clause #13 (by clausification #[5]): Or (Eq (p False) True) (Eq a True)
% 3.58/3.76  Clause #15 (by superposition #[12, 11]): Or (Eq b True) (Or (Eq True False) (Eq b True))
% 3.58/3.76  Clause #16 (by superposition #[13, 10]): Or (Eq a True) (Or (Eq True False) (Eq a True))
% 3.58/3.76  Clause #18 (by clausification #[15]): Or (Eq b True) (Eq b True)
% 3.58/3.76  Clause #19 (by eliminate duplicate literals #[18]): Eq b True
% 3.58/3.76  Clause #20 (by backward demodulation #[19, 6]): Or (Eq (p True) True) (Or (Eq a False) (Eq True False))
% 3.58/3.76  Clause #21 (by backward demodulation #[19, 9]): Or (Eq (p True) False) (Or (Eq True False) (Eq a False))
% 3.58/3.76  Clause #28 (by clausification #[16]): Or (Eq a True) (Eq a True)
% 3.58/3.76  Clause #29 (by eliminate duplicate literals #[28]): Eq a True
% 3.58/3.76  Clause #30 (by clausification #[21]): Or (Eq (p True) False) (Eq a False)
% 3.58/3.76  Clause #31 (by forward demodulation #[30, 29]): Or (Eq (p True) False) (Eq True False)
% 3.58/3.76  Clause #32 (by clausification #[31]): Eq (p True) False
% 3.58/3.76  Clause #33 (by clausification #[20]): Or (Eq (p True) True) (Eq a False)
% 3.58/3.76  Clause #34 (by forward demodulation #[33, 29]): Or (Eq (p True) True) (Eq True False)
% 3.58/3.76  Clause #35 (by clausification #[34]): Eq (p True) True
% 3.58/3.76  Clause #36 (by superposition #[35, 32]): Eq True False
% 3.58/3.76  Clause #37 (by clausification #[36]): False
% 3.58/3.76  SZS output end Proof for theBenchmark.p
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