TSTP Solution File: SYO004^1 by cocATP---0.2.0
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- Process Solution
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% File : cocATP---0.2.0
% Problem : SYO004^1 : TPTP v7.5.0. Released v3.7.0.
% Transfm : none
% Format : tptp:raw
% Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% Computer : n022.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 0s
% DateTime : Tue Mar 29 00:50:22 EDT 2022
% Result : Theorem 0.54s 0.72s
% Output : Proof 0.54s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : SYO004^1 : TPTP v7.5.0. Released v3.7.0.
% 0.06/0.12 % Command : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.12/0.33 % Computer : n022.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPUModel : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % RAMPerCPU : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % DateTime : Thu Mar 10 23:20:43 EST 2022
% 0.12/0.33 % CPUTime :
% 0.12/0.34 ModuleCmd_Load.c(213):ERROR:105: Unable to locate a modulefile for 'python/python27'
% 0.12/0.35 Python 2.7.5
% 0.54/0.72 Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% 0.54/0.72 FOF formula (<kernel.Constant object at 0x1c99e60>, <kernel.DependentProduct object at 0x1c99ea8>) of role type named leibeq_decl
% 0.54/0.72 Using role type
% 0.54/0.72 Declaring leibeq:(fofType->(fofType->Prop))
% 0.54/0.72 FOF formula (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))) of role definition named leibeq
% 0.54/0.72 A new definition: (((eq (fofType->(fofType->Prop))) leibeq) (fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))))
% 0.54/0.72 Defined: leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y))))
% 0.54/0.72 FOF formula (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))) of role conjecture named conj
% 0.54/0.72 Conjecture to prove = (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y))):Prop
% 0.54/0.72 Parameter fofType_DUMMY:fofType.
% 0.54/0.72 We need to prove ['(forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y)))']
% 0.54/0.72 Parameter fofType:Type.
% 0.54/0.72 Definition leibeq:=(fun (X:fofType) (Y:fofType)=> (forall (P:(fofType->Prop)), ((P X)->(P Y)))):(fofType->(fofType->Prop)).
% 0.54/0.72 Trying to prove (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y)))
% 0.54/0.72 Found eq_substitution00000:=(eq_substitution0000 (fun (x2:fofType)=> x2)):((((eq fofType) X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found (eq_substitution0000 (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found ((eq_substitution000 Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found (((eq_substitution00 X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found ((((eq_substitution0 fofType) X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2)) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found (fun (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (((leibeq X) Y)->(((eq fofType) X) Y))
% 0.54/0.72 Found (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (forall (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y)))
% 0.54/0.72 Found (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2))) as proof of (forall (X:fofType) (Y:fofType), (((leibeq X) Y)->(((eq fofType) X) Y)))
% 0.54/0.72 Got proof (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2)))
% 0.54/0.72 Time elapsed = 0.111593s
% 0.54/0.72 node=12 cost=-458.000000 depth=7
% 0.54/0.72 ::::::::::::::::::::::
% 0.54/0.72 % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.54/0.72 % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.54/0.72 (fun (X:fofType) (Y:fofType)=> (((((eq_substitution fofType) fofType) X) Y) (fun (x2:fofType)=> x2)))
% 0.54/0.72 % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
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