TSTP Solution File: SYN970+1 by Bliksem---1.12

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Bliksem---1.12
% Problem  : SYN970+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : bliksem %s

% Computer : n025.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 0s
% DateTime : Thu Jul 21 02:58:27 EDT 2022

% Result   : Theorem 0.80s 1.19s
% Output   : Refutation 0.80s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem  : SYN970+1 : TPTP v8.1.0. Released v3.1.0.
% 0.04/0.13  % Command  : bliksem %s
% 0.13/0.34  % Computer : n025.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % DateTime : Mon Jul 11 12:59:17 EDT 2022
% 0.13/0.34  % CPUTime  : 
% 0.80/1.19  *** allocated 10000 integers for termspace/termends
% 0.80/1.19  *** allocated 10000 integers for clauses
% 0.80/1.19  *** allocated 10000 integers for justifications
% 0.80/1.19  Bliksem 1.12
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Automatic Strategy Selection
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Clauses:
% 0.80/1.19  
% 0.80/1.19  { ! p( X ), r( Y ) }.
% 0.80/1.19  { p( skol1 ) }.
% 0.80/1.19  { ! r( skol2 ) }.
% 0.80/1.19  
% 0.80/1.19  percentage equality = 0.000000, percentage horn = 1.000000
% 0.80/1.19  This is a near-Horn, non-equality  problem
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Options Used:
% 0.80/1.19  
% 0.80/1.19  useres =            1
% 0.80/1.19  useparamod =        0
% 0.80/1.19  useeqrefl =         0
% 0.80/1.19  useeqfact =         0
% 0.80/1.19  usefactor =         1
% 0.80/1.19  usesimpsplitting =  0
% 0.80/1.19  usesimpdemod =      0
% 0.80/1.19  usesimpres =        4
% 0.80/1.19  
% 0.80/1.19  resimpinuse      =  1000
% 0.80/1.19  resimpclauses =     20000
% 0.80/1.19  substype =          standard
% 0.80/1.19  backwardsubs =      1
% 0.80/1.19  selectoldest =      5
% 0.80/1.19  
% 0.80/1.19  litorderings [0] =  split
% 0.80/1.19  litorderings [1] =  liftord
% 0.80/1.19  
% 0.80/1.19  termordering =      none
% 0.80/1.19  
% 0.80/1.19  litapriori =        1
% 0.80/1.19  termapriori =       0
% 0.80/1.19  litaposteriori =    0
% 0.80/1.19  termaposteriori =   0
% 0.80/1.19  demodaposteriori =  0
% 0.80/1.19  ordereqreflfact =   0
% 0.80/1.19  
% 0.80/1.19  litselect =         negative
% 0.80/1.19  
% 0.80/1.19  maxweight =         30000
% 0.80/1.19  maxdepth =          30000
% 0.80/1.19  maxlength =         115
% 0.80/1.19  maxnrvars =         195
% 0.80/1.19  excuselevel =       0
% 0.80/1.19  increasemaxweight = 0
% 0.80/1.19  
% 0.80/1.19  maxselected =       10000000
% 0.80/1.19  maxnrclauses =      10000000
% 0.80/1.19  
% 0.80/1.19  showgenerated =    0
% 0.80/1.19  showkept =         0
% 0.80/1.19  showselected =     0
% 0.80/1.19  showdeleted =      0
% 0.80/1.19  showresimp =       1
% 0.80/1.19  showstatus =       2000
% 0.80/1.19  
% 0.80/1.19  prologoutput =     0
% 0.80/1.19  nrgoals =          5000000
% 0.80/1.19  totalproof =       1
% 0.80/1.19  
% 0.80/1.19  Symbols occurring in the translation:
% 0.80/1.19  
% 0.80/1.19  {}  [0, 0]      (w:1, o:2, a:1, s:1, b:0), 
% 0.80/1.19  .  [1, 2]      (w:1, o:19, a:1, s:1, b:0), 
% 0.80/1.19  !  [4, 1]      (w:1, o:12, a:1, s:1, b:0), 
% 0.80/1.19  =  [13, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.80/1.19  ==>  [14, 2]      (w:1, o:0, a:0, s:1, b:0), 
% 0.80/1.19  p  [39, 1]      (w:1, o:17, a:1, s:1, b:0), 
% 0.80/1.19  r  [40, 1]      (w:1, o:18, a:1, s:1, b:0), 
% 0.80/1.19  skol1  [41, 0]      (w:1, o:10, a:1, s:1, b:0), 
% 0.80/1.19  skol2  [42, 0]      (w:1, o:11, a:1, s:1, b:0).
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Starting Search:
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Bliksems!, er is een bewijs:
% 0.80/1.19  % SZS status Theorem
% 0.80/1.19  % SZS output start Refutation
% 0.80/1.19  
% 0.80/1.19  (0) {G0,W5,D2,L2,V2,M1} I { r( Y ), ! p( X ) }.
% 0.80/1.19  (1) {G0,W2,D2,L1,V0,M1} I { p( skol1 ) }.
% 0.80/1.19  (2) {G0,W3,D2,L1,V0,M1} I { ! r( skol2 ) }.
% 0.80/1.19  (3) {G1,W2,D2,L1,V1,M1} R(0,1) { r( X ) }.
% 0.80/1.19  (4) {G2,W0,D0,L0,V0,M0} R(3,2) {  }.
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  % SZS output end Refutation
% 0.80/1.19  found a proof!
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Unprocessed initial clauses:
% 0.80/1.19  
% 0.80/1.19  (6) {G0,W5,D2,L2,V2,M2}  { ! p( X ), r( Y ) }.
% 0.80/1.19  (7) {G0,W2,D2,L1,V0,M1}  { p( skol1 ) }.
% 0.80/1.19  (8) {G0,W3,D2,L1,V0,M1}  { ! r( skol2 ) }.
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Total Proof:
% 0.80/1.19  
% 0.80/1.19  subsumption: (0) {G0,W5,D2,L2,V2,M1} I { r( Y ), ! p( X ) }.
% 0.80/1.19  parent0: (6) {G0,W5,D2,L2,V2,M2}  { ! p( X ), r( Y ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19     X := X
% 0.80/1.19     Y := Y
% 0.80/1.19  end
% 0.80/1.19  permutation0:
% 0.80/1.19     0 ==> 1
% 0.80/1.19     1 ==> 0
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  subsumption: (1) {G0,W2,D2,L1,V0,M1} I { p( skol1 ) }.
% 0.80/1.19  parent0: (7) {G0,W2,D2,L1,V0,M1}  { p( skol1 ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19  end
% 0.80/1.19  permutation0:
% 0.80/1.19     0 ==> 0
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  subsumption: (2) {G0,W3,D2,L1,V0,M1} I { ! r( skol2 ) }.
% 0.80/1.19  parent0: (8) {G0,W3,D2,L1,V0,M1}  { ! r( skol2 ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19  end
% 0.80/1.19  permutation0:
% 0.80/1.19     0 ==> 0
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  resolution: (9) {G1,W2,D2,L1,V1,M1}  { r( X ) }.
% 0.80/1.19  parent0[1]: (0) {G0,W5,D2,L2,V2,M1} I { r( Y ), ! p( X ) }.
% 0.80/1.19  parent1[0]: (1) {G0,W2,D2,L1,V0,M1} I { p( skol1 ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19     X := skol1
% 0.80/1.19     Y := X
% 0.80/1.19  end
% 0.80/1.19  substitution1:
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  subsumption: (3) {G1,W2,D2,L1,V1,M1} R(0,1) { r( X ) }.
% 0.80/1.19  parent0: (9) {G1,W2,D2,L1,V1,M1}  { r( X ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19     X := X
% 0.80/1.19  end
% 0.80/1.19  permutation0:
% 0.80/1.19     0 ==> 0
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  resolution: (10) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.80/1.19  parent0[0]: (2) {G0,W3,D2,L1,V0,M1} I { ! r( skol2 ) }.
% 0.80/1.19  parent1[0]: (3) {G1,W2,D2,L1,V1,M1} R(0,1) { r( X ) }.
% 0.80/1.19  substitution0:
% 0.80/1.19  end
% 0.80/1.19  substitution1:
% 0.80/1.19     X := skol2
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  subsumption: (4) {G2,W0,D0,L0,V0,M0} R(3,2) {  }.
% 0.80/1.19  parent0: (10) {G1,W0,D0,L0,V0,M0}  {  }.
% 0.80/1.19  substitution0:
% 0.80/1.19  end
% 0.80/1.19  permutation0:
% 0.80/1.19  end
% 0.80/1.19  
% 0.80/1.19  Proof check complete!
% 0.80/1.19  
% 0.80/1.19  Memory use:
% 0.80/1.19  
% 0.80/1.19  space for terms:        50
% 0.80/1.19  space for clauses:      207
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  clauses generated:      5
% 0.80/1.19  clauses kept:           5
% 0.80/1.19  clauses selected:       4
% 0.80/1.19  clauses deleted:        0
% 0.80/1.19  clauses inuse deleted:  0
% 0.80/1.19  
% 0.80/1.19  subsentry:          0
% 0.80/1.19  literals s-matched: 0
% 0.80/1.19  literals matched:   0
% 0.80/1.19  full subsumption:   0
% 0.80/1.19  
% 0.80/1.19  checksum:           -20978122
% 0.80/1.19  
% 0.80/1.19  
% 0.80/1.19  Bliksem ended
%------------------------------------------------------------------------------