TSTP Solution File: SYN968+1 by iProver---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : iProver---3.9
% Problem  : SYN968+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : run_iprover %s %d THM

% Computer : n011.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri May  3 03:33:44 EDT 2024

% Result   : Theorem 0.50s 1.18s
% Output   : CNFRefutation 0.50s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    6
%            Number of leaves      :    2
% Syntax   : Number of formulae    :   10 (   5 unt;   0 def)
%            Number of atoms       :   17 (   0 equ)
%            Maximal formula atoms :    4 (   1 avg)
%            Number of connectives :   14 (   7   ~;   0   |;   4   &)
%                                         (   0 <=>;   3  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    6 (   3 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   0 con; 1-1 aty)
%            Number of variables   :   13 (   2 sgn   7   !;   4   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f1,conjecture,
    ? [X0] :
    ! [X1] :
      ( p(X0)
     => p(X1) ),
    file('/export/starexec/sandbox2/benchmark/theBenchmark.p',prove_this) ).

fof(f2,negated_conjecture,
    ~ ? [X0] :
      ! [X1] :
        ( p(X0)
       => p(X1) ),
    inference(negated_conjecture,[],[f1]) ).

fof(f3,plain,
    ! [X0] :
    ? [X1] :
      ( ~ p(X1)
      & p(X0) ),
    inference(ennf_transformation,[],[f2]) ).

fof(f4,plain,
    ! [X0] :
      ( ? [X1] :
          ( ~ p(X1)
          & p(X0) )
     => ( ~ p(sK0(X0))
        & p(X0) ) ),
    introduced(choice_axiom,[]) ).

fof(f5,plain,
    ! [X0] :
      ( ~ p(sK0(X0))
      & p(X0) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0])],[f3,f4]) ).

fof(f6,plain,
    ! [X0] : p(X0),
    inference(cnf_transformation,[],[f5]) ).

fof(f7,plain,
    ! [X0] : ~ p(sK0(X0)),
    inference(cnf_transformation,[],[f5]) ).

cnf(c_49,negated_conjecture,
    ~ p(sK0(X0)),
    inference(cnf_transformation,[],[f7]) ).

cnf(c_50,negated_conjecture,
    p(X0),
    inference(cnf_transformation,[],[f6]) ).

cnf(c_55,plain,
    $false,
    inference(backward_subsumption_resolution,[status(thm)],[c_49,c_50]) ).


%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12  % Problem  : SYN968+1 : TPTP v8.1.2. Released v3.1.0.
% 0.06/0.13  % Command  : run_iprover %s %d THM
% 0.14/0.34  % Computer : n011.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 300
% 0.14/0.34  % DateTime : Thu May  2 21:02:18 EDT 2024
% 0.14/0.34  % CPUTime  : 
% 0.21/0.47  Running first-order theorem proving
% 0.21/0.47  Running: /export/starexec/sandbox2/solver/bin/run_problem --schedule fof_schedule --heuristic_context casc_unsat --no_cores 8 /export/starexec/sandbox2/benchmark/theBenchmark.p 300
% 0.50/1.18  % SZS status Started for theBenchmark.p
% 0.50/1.18  % SZS status Theorem for theBenchmark.p
% 0.50/1.18  
% 0.50/1.18  %---------------- iProver v3.9 (pre CASC 2024/SMT-COMP 2024) ----------------%
% 0.50/1.18  
% 0.50/1.18  ------  iProver source info
% 0.50/1.18  
% 0.50/1.18  git: date: 2024-05-02 19:28:25 +0000
% 0.50/1.18  git: sha1: a33b5eb135c74074ba803943bb12f2ebd971352f
% 0.50/1.18  git: non_committed_changes: false
% 0.50/1.18  
% 0.50/1.18  ------ Parsing...
% 0.50/1.18  ------ Clausification by vclausify_rel  & Parsing by iProver...
% 0.50/1.18  
% 0.50/1.18  ------ Preprocessing...
% 0.50/1.18  
% 0.50/1.18  % SZS status Theorem for theBenchmark.p
% 0.50/1.18  
% 0.50/1.18  % SZS output start CNFRefutation for theBenchmark.p
% See solution above
% 0.50/1.18  
% 0.50/1.18  
%------------------------------------------------------------------------------