TSTP Solution File: SYN945+1 by Duper---1.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Duper---1.0
% Problem  : SYN945+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : duper %s

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 02:13:22 EDT 2023

% Result   : Theorem 3.71s 3.91s
% Output   : Proof 3.71s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14  % Problem    : SYN945+1 : TPTP v8.1.2. Released v3.1.0.
% 0.00/0.16  % Command    : duper %s
% 0.17/0.36  % Computer : n029.cluster.edu
% 0.17/0.36  % Model    : x86_64 x86_64
% 0.17/0.36  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.17/0.36  % Memory   : 8042.1875MB
% 0.17/0.36  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.17/0.36  % CPULimit   : 300
% 0.17/0.36  % WCLimit    : 300
% 0.17/0.36  % DateTime   : Sat Aug 26 19:42:25 EDT 2023
% 0.17/0.36  % CPUTime    : 
% 3.71/3.91  SZS status Theorem for theBenchmark.p
% 3.71/3.91  SZS output start Proof for theBenchmark.p
% 3.71/3.91  Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), p X) → ∀ (A B : Iota), And (p A) (p B))) True
% 3.71/3.91  Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), p X) → ∀ (A B : Iota), And (p A) (p B)) False
% 3.71/3.91  Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), p X) True
% 3.71/3.91  Clause #3 (by clausification #[1]): Eq (∀ (A B : Iota), And (p A) (p B)) False
% 3.71/3.91  Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (p a) True
% 3.71/3.91  Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), And (p (skS.0 0 a)) (p B))) True
% 3.71/3.91  Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), And (p (skS.0 0 a)) (p B)) False
% 3.71/3.91  Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (Not (And (p (skS.0 0 a)) (p (skS.0 1 a a_1)))) True
% 3.71/3.91  Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (And (p (skS.0 0 a)) (p (skS.0 1 a a_1))) False
% 3.71/3.91  Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a a_1)) False)
% 3.71/3.91  Clause #10 (by forward demodulation #[9, 4]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (p (skS.0 1 a a_1)) False)
% 3.71/3.91  Clause #11 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (p (skS.0 1 a a_1)) False
% 3.71/3.91  Clause #12 (by superposition #[11, 4]): Eq False True
% 3.71/3.91  Clause #13 (by clausification #[12]): False
% 3.71/3.91  SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------