TSTP Solution File: SYN945+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYN945+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n029.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:22 EDT 2023
% Result : Theorem 3.71s 3.91s
% Output : Proof 3.71s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.14 % Problem : SYN945+1 : TPTP v8.1.2. Released v3.1.0.
% 0.00/0.16 % Command : duper %s
% 0.17/0.36 % Computer : n029.cluster.edu
% 0.17/0.36 % Model : x86_64 x86_64
% 0.17/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.17/0.36 % Memory : 8042.1875MB
% 0.17/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.17/0.36 % CPULimit : 300
% 0.17/0.36 % WCLimit : 300
% 0.17/0.36 % DateTime : Sat Aug 26 19:42:25 EDT 2023
% 0.17/0.36 % CPUTime :
% 3.71/3.91 SZS status Theorem for theBenchmark.p
% 3.71/3.91 SZS output start Proof for theBenchmark.p
% 3.71/3.91 Clause #0 (by assumption #[]): Eq (Not ((∀ (X : Iota), p X) → ∀ (A B : Iota), And (p A) (p B))) True
% 3.71/3.91 Clause #1 (by clausification #[0]): Eq ((∀ (X : Iota), p X) → ∀ (A B : Iota), And (p A) (p B)) False
% 3.71/3.91 Clause #2 (by clausification #[1]): Eq (∀ (X : Iota), p X) True
% 3.71/3.91 Clause #3 (by clausification #[1]): Eq (∀ (A B : Iota), And (p A) (p B)) False
% 3.71/3.91 Clause #4 (by clausification #[2]): ∀ (a : Iota), Eq (p a) True
% 3.71/3.91 Clause #5 (by clausification #[3]): ∀ (a : Iota), Eq (Not (∀ (B : Iota), And (p (skS.0 0 a)) (p B))) True
% 3.71/3.91 Clause #6 (by clausification #[5]): ∀ (a : Iota), Eq (∀ (B : Iota), And (p (skS.0 0 a)) (p B)) False
% 3.71/3.91 Clause #7 (by clausification #[6]): ∀ (a a_1 : Iota), Eq (Not (And (p (skS.0 0 a)) (p (skS.0 1 a a_1)))) True
% 3.71/3.91 Clause #8 (by clausification #[7]): ∀ (a a_1 : Iota), Eq (And (p (skS.0 0 a)) (p (skS.0 1 a a_1))) False
% 3.71/3.91 Clause #9 (by clausification #[8]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a a_1)) False)
% 3.71/3.91 Clause #10 (by forward demodulation #[9, 4]): ∀ (a a_1 : Iota), Or (Eq True False) (Eq (p (skS.0 1 a a_1)) False)
% 3.71/3.91 Clause #11 (by clausification #[10]): ∀ (a a_1 : Iota), Eq (p (skS.0 1 a a_1)) False
% 3.71/3.91 Clause #12 (by superposition #[11, 4]): Eq False True
% 3.71/3.91 Clause #13 (by clausification #[12]): False
% 3.71/3.91 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------