TSTP Solution File: SYN935+1 by Duper---1.0
View Problem
- Process Solution
%------------------------------------------------------------------------------
% File : Duper---1.0
% Problem : SYN935+1 : TPTP v8.1.2. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n009.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 02:13:20 EDT 2023
% Result : Theorem 3.56s 3.78s
% Output : Proof 3.56s
% Verified :
% SZS Type : -
% Comments :
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.06/0.12 % Problem : SYN935+1 : TPTP v8.1.2. Released v3.1.0.
% 0.06/0.13 % Command : duper %s
% 0.14/0.34 % Computer : n009.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Sat Aug 26 21:29:20 EDT 2023
% 0.14/0.34 % CPUTime :
% 3.56/3.78 SZS status Theorem for theBenchmark.p
% 3.56/3.78 SZS output start Proof for theBenchmark.p
% 3.56/3.78 Clause #0 (by assumption #[]): Eq (Not (Iff (Exists fun X => p X → c) ((∀ (X : Iota), p X) → c))) True
% 3.56/3.78 Clause #1 (by clausification #[0]): Eq (Iff (Exists fun X => p X → c) ((∀ (X : Iota), p X) → c)) False
% 3.56/3.78 Clause #2 (by clausification #[1]): Or (Eq (Exists fun X => p X → c) False) (Eq ((∀ (X : Iota), p X) → c) False)
% 3.56/3.78 Clause #3 (by clausification #[1]): Or (Eq (Exists fun X => p X → c) True) (Eq ((∀ (X : Iota), p X) → c) True)
% 3.56/3.78 Clause #4 (by clausification #[2]): ∀ (a : Iota), Or (Eq ((∀ (X : Iota), p X) → c) False) (Eq (p a → c) False)
% 3.56/3.78 Clause #5 (by clausification #[4]): ∀ (a : Iota), Or (Eq (p a → c) False) (Eq (∀ (X : Iota), p X) True)
% 3.56/3.78 Clause #6 (by clausification #[4]): ∀ (a : Iota), Or (Eq (p a → c) False) (Eq c False)
% 3.56/3.78 Clause #7 (by clausification #[5]): ∀ (a : Iota), Or (Eq (∀ (X : Iota), p X) True) (Eq (p a) True)
% 3.56/3.78 Clause #9 (by clausification #[7]): ∀ (a a_1 : Iota), Or (Eq (p a) True) (Eq (p a_1) True)
% 3.56/3.78 Clause #10 (by equality factoring #[9]): ∀ (a : Iota), Or (Ne True True) (Eq (p a) True)
% 3.56/3.78 Clause #11 (by clausification #[10]): ∀ (a : Iota), Or (Eq (p a) True) (Or (Eq True False) (Eq True False))
% 3.56/3.78 Clause #13 (by clausification #[11]): ∀ (a : Iota), Or (Eq (p a) True) (Eq True False)
% 3.56/3.78 Clause #14 (by clausification #[13]): ∀ (a : Iota), Eq (p a) True
% 3.56/3.78 Clause #16 (by clausification #[6]): Or (Eq c False) (Eq c False)
% 3.56/3.78 Clause #17 (by eliminate duplicate literals #[16]): Eq c False
% 3.56/3.78 Clause #18 (by clausification #[3]): ∀ (a : Iota), Or (Eq ((∀ (X : Iota), p X) → c) True) (Eq (p (skS.0 0 a) → c) True)
% 3.56/3.78 Clause #19 (by clausification #[18]): ∀ (a : Iota), Or (Eq (p (skS.0 0 a) → c) True) (Or (Eq (∀ (X : Iota), p X) False) (Eq c True))
% 3.56/3.78 Clause #20 (by clausification #[19]): ∀ (a : Iota), Or (Eq (∀ (X : Iota), p X) False) (Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Eq c True)))
% 3.56/3.78 Clause #21 (by clausification #[20]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Or (Eq c True) (Eq (Not (p (skS.0 1 a_1))) True)))
% 3.56/3.78 Clause #22 (by clausification #[21]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Or (Eq c True) (Eq (p (skS.0 1 a_1)) False)))
% 3.56/3.78 Clause #23 (by eliminate duplicate literals #[22]): ∀ (a a_1 : Iota), Or (Eq c True) (Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False))
% 3.56/3.78 Clause #24 (by forward demodulation #[23, 17]): ∀ (a a_1 : Iota), Or (Eq False True) (Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False))
% 3.56/3.78 Clause #25 (by clausification #[24]): ∀ (a a_1 : Iota), Or (Eq (p (skS.0 0 a)) False) (Eq (p (skS.0 1 a_1)) False)
% 3.56/3.78 Clause #26 (by superposition #[25, 14]): ∀ (a : Iota), Or (Eq (p (skS.0 1 a)) False) (Eq False True)
% 3.56/3.78 Clause #27 (by clausification #[26]): ∀ (a : Iota), Eq (p (skS.0 1 a)) False
% 3.56/3.78 Clause #28 (by superposition #[27, 14]): Eq False True
% 3.56/3.78 Clause #29 (by clausification #[28]): False
% 3.56/3.78 SZS output end Proof for theBenchmark.p
%------------------------------------------------------------------------------