TSTP Solution File: SYN934+1 by SnakeForV-SAT---1.0
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- Process Solution
%------------------------------------------------------------------------------
% File : SnakeForV-SAT---1.0
% Problem : SYN934+1 : TPTP v8.1.0. Released v3.1.0.
% Transfm : none
% Format : tptp:raw
% Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s
% Computer : n026.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Aug 31 19:46:08 EDT 2022
% Result : Theorem 0.20s 0.50s
% Output : Refutation 0.20s
% Verified :
% SZS Type : Refutation
% Derivation depth : 12
% Number of leaves : 6
% Syntax : Number of formulae : 29 ( 2 unt; 0 def)
% Number of atoms : 95 ( 0 equ)
% Maximal formula atoms : 8 ( 3 avg)
% Number of connectives : 106 ( 40 ~; 39 |; 12 &)
% ( 6 <=>; 8 =>; 0 <=; 1 <~>)
% Maximal formula depth : 7 ( 4 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 6 ( 5 usr; 5 prp; 0-1 aty)
% Number of functors : 2 ( 2 usr; 2 con; 0-0 aty)
% Number of variables : 28 ( 12 !; 16 ?)
% Comments :
%------------------------------------------------------------------------------
fof(f36,plain,
$false,
inference(avatar_sat_refutation,[],[f21,f31,f33,f35]) ).
fof(f35,plain,
( ~ spl2_1
| ~ spl2_2 ),
inference(avatar_contradiction_clause,[],[f34]) ).
fof(f34,plain,
( $false
| ~ spl2_1
| ~ spl2_2 ),
inference(subsumption_resolution,[],[f26,f20]) ).
fof(f20,plain,
( ! [X1] : ~ p(X1)
| ~ spl2_1 ),
inference(avatar_component_clause,[],[f19]) ).
fof(f19,plain,
( spl2_1
<=> ! [X1] : ~ p(X1) ),
introduced(avatar_definition,[new_symbols(naming,[spl2_1])]) ).
fof(f26,plain,
( p(sK0)
| ~ spl2_2 ),
inference(avatar_component_clause,[],[f24]) ).
fof(f24,plain,
( spl2_2
<=> p(sK0) ),
introduced(avatar_definition,[new_symbols(naming,[spl2_2])]) ).
fof(f33,plain,
( ~ spl2_1
| ~ spl2_3 ),
inference(avatar_contradiction_clause,[],[f32]) ).
fof(f32,plain,
( $false
| ~ spl2_1
| ~ spl2_3 ),
inference(subsumption_resolution,[],[f30,f20]) ).
fof(f30,plain,
( p(sK1)
| ~ spl2_3 ),
inference(avatar_component_clause,[],[f28]) ).
fof(f28,plain,
( spl2_3
<=> p(sK1) ),
introduced(avatar_definition,[new_symbols(naming,[spl2_3])]) ).
fof(f31,plain,
( spl2_2
| spl2_3 ),
inference(avatar_split_clause,[],[f22,f28,f24]) ).
fof(f22,plain,
( p(sK1)
| p(sK0) ),
inference(subsumption_resolution,[],[f16,f17]) ).
fof(f17,plain,
c,
inference(duplicate_literal_removal,[],[f13]) ).
fof(f13,plain,
( c
| c ),
inference(cnf_transformation,[],[f10]) ).
fof(f10,plain,
( ( ( ! [X0] : ~ p(X0)
& c )
| ! [X1] :
( c
& ~ p(X1) ) )
& ( p(sK0)
| ~ c
| ~ c
| p(sK1) ) ),
inference(skolemisation,[status(esa),new_symbols(skolem,[sK0,sK1])],[f7,f9,f8]) ).
fof(f8,plain,
( ? [X2] : p(X2)
=> p(sK0) ),
introduced(choice_axiom,[]) ).
fof(f9,plain,
( ? [X3] :
( ~ c
| p(X3) )
=> ( ~ c
| p(sK1) ) ),
introduced(choice_axiom,[]) ).
fof(f7,plain,
( ( ( ! [X0] : ~ p(X0)
& c )
| ! [X1] :
( c
& ~ p(X1) ) )
& ( ? [X2] : p(X2)
| ~ c
| ? [X3] :
( ~ c
| p(X3) ) ) ),
inference(rectify,[],[f6]) ).
fof(f6,plain,
( ( ( ! [X0] : ~ p(X0)
& c )
| ! [X1] :
( c
& ~ p(X1) ) )
& ( ? [X0] : p(X0)
| ~ c
| ? [X1] :
( ~ c
| p(X1) ) ) ),
inference(flattening,[],[f5]) ).
fof(f5,plain,
( ( ( ! [X0] : ~ p(X0)
& c )
| ! [X1] :
( c
& ~ p(X1) ) )
& ( ? [X0] : p(X0)
| ~ c
| ? [X1] :
( ~ c
| p(X1) ) ) ),
inference(nnf_transformation,[],[f4]) ).
fof(f4,plain,
( ? [X1] :
( ~ c
| p(X1) )
<~> ( ? [X0] : p(X0)
| ~ c ) ),
inference(ennf_transformation,[],[f3]) ).
fof(f3,plain,
~ ( ? [X1] :
( c
=> p(X1) )
<=> ( c
=> ? [X0] : p(X0) ) ),
inference(rectify,[],[f2]) ).
fof(f2,negated_conjecture,
~ ( ( c
=> ? [X0] : p(X0) )
<=> ? [X0] :
( c
=> p(X0) ) ),
inference(negated_conjecture,[],[f1]) ).
fof(f1,conjecture,
( ( c
=> ? [X0] : p(X0) )
<=> ? [X0] :
( c
=> p(X0) ) ),
file('/export/starexec/sandbox2/benchmark/theBenchmark.p',prove_this) ).
fof(f16,plain,
( ~ c
| p(sK1)
| p(sK0) ),
inference(duplicate_literal_removal,[],[f11]) ).
fof(f11,plain,
( ~ c
| p(sK0)
| ~ c
| p(sK1) ),
inference(cnf_transformation,[],[f10]) ).
fof(f21,plain,
( spl2_1
| spl2_1 ),
inference(avatar_split_clause,[],[f14,f19,f19]) ).
fof(f14,plain,
! [X0,X1] :
( ~ p(X0)
| ~ p(X1) ),
inference(cnf_transformation,[],[f10]) ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.12/0.12 % Problem : SYN934+1 : TPTP v8.1.0. Released v3.1.0.
% 0.12/0.13 % Command : vampire --input_syntax tptp --proof tptp --output_axiom_names on --mode portfolio --schedule snake_tptp_sat --cores 0 -t %d %s
% 0.13/0.34 % Computer : n026.cluster.edu
% 0.13/0.34 % Model : x86_64 x86_64
% 0.13/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34 % Memory : 8042.1875MB
% 0.13/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34 % CPULimit : 300
% 0.13/0.34 % WCLimit : 300
% 0.13/0.34 % DateTime : Tue Aug 30 22:46:06 EDT 2022
% 0.13/0.34 % CPUTime :
% 0.20/0.49 % (3730)ott+11_2:3_av=off:fde=unused:nwc=5.0:tgt=ground:i=177:si=on:rawr=on:rtra=on_0 on theBenchmark for (3000ds/177Mi)
% 0.20/0.50 % (3716)ott+10_1:5_bd=off:tgt=full:i=99:si=on:rawr=on:rtra=on_0 on theBenchmark for (3000ds/99Mi)
% 0.20/0.50 % (3716)First to succeed.
% 0.20/0.50 % (3724)ott+3_1:1_gsp=on:lcm=predicate:i=138:si=on:rawr=on:rtra=on_0 on theBenchmark for (3000ds/138Mi)
% 0.20/0.50 % (3716)Refutation found. Thanks to Tanya!
% 0.20/0.50 % SZS status Theorem for theBenchmark
% 0.20/0.50 % SZS output start Proof for theBenchmark
% See solution above
% 0.20/0.50 % (3716)------------------------------
% 0.20/0.50 % (3716)Version: Vampire 4.7 (commit 807e37dd9 on 2022-08-23 09:55:27 +0200)
% 0.20/0.50 % (3716)Linked with Z3 4.8.13.0 f03d756e086f81f2596157241e0decfb1c982299 z3-4.8.4-5390-gf03d756e0
% 0.20/0.50 % (3716)Termination reason: Refutation
% 0.20/0.50
% 0.20/0.50 % (3716)Memory used [KB]: 5373
% 0.20/0.50 % (3716)Time elapsed: 0.003 s
% 0.20/0.50 % (3716)Instructions burned: 1 (million)
% 0.20/0.50 % (3716)------------------------------
% 0.20/0.50 % (3716)------------------------------
% 0.20/0.50 % (3701)Success in time 0.158 s
%------------------------------------------------------------------------------