TSTP Solution File: SYN733+1 by Vampire-SAT---4.8

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Vampire-SAT---4.8
% Problem  : SYN733+1 : TPTP v8.1.2. Released v2.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s

% Computer : n003.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Sun May  5 12:12:06 EDT 2024

% Result   : Theorem 0.14s 0.38s
% Output   : Refutation 0.14s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    2
% Syntax   : Number of formulae    :   12 (   4 unt;   0 def)
%            Number of atoms       :   39 (   0 equ)
%            Maximal formula atoms :    6 (   3 avg)
%            Number of connectives :   37 (  10   ~;  12   |;  12   &)
%                                         (   0 <=>;   3  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    7 (   4 avg)
%            Maximal term depth    :    2 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   0 con; 1-1 aty)
%            Number of variables   :   21 (  14   !;   7   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(f12,plain,
    $false,
    inference(subsumption_resolution,[],[f11,f10]) ).

fof(f10,plain,
    ! [X0] : ~ q(X0),
    inference(subsumption_resolution,[],[f9,f7]) ).

fof(f7,plain,
    ! [X1] : p(X1),
    inference(cnf_transformation,[],[f6]) ).

fof(f6,plain,
    ( ! [X0] :
        ( ~ q(X0)
        | ~ p(X0) )
    & ! [X1] :
        ( ( q(X1)
          | q(sK0(X1)) )
        & p(X1) ) ),
    inference(skolemisation,[status(esa),new_symbols(skolem,[sK0])],[f4,f5]) ).

fof(f5,plain,
    ! [X1] :
      ( ? [X2] :
          ( ( q(X1)
            | q(X2) )
          & p(X1) )
     => ( ( q(X1)
          | q(sK0(X1)) )
        & p(X1) ) ),
    introduced(choice_axiom,[]) ).

fof(f4,plain,
    ( ! [X0] :
        ( ~ q(X0)
        | ~ p(X0) )
    & ! [X1] :
      ? [X2] :
        ( ( q(X1)
          | q(X2) )
        & p(X1) ) ),
    inference(rectify,[],[f3]) ).

fof(f3,plain,
    ( ! [X2] :
        ( ~ q(X2)
        | ~ p(X2) )
    & ! [X0] :
      ? [X1] :
        ( ( q(X0)
          | q(X1) )
        & p(X0) ) ),
    inference(ennf_transformation,[],[f2]) ).

fof(f2,negated_conjecture,
    ~ ( ! [X0] :
        ? [X1] :
          ( ( q(X0)
            | q(X1) )
          & p(X0) )
     => ? [X2] :
          ( q(X2)
          & p(X2) ) ),
    inference(negated_conjecture,[],[f1]) ).

fof(f1,conjecture,
    ( ! [X0] :
      ? [X1] :
        ( ( q(X0)
          | q(X1) )
        & p(X0) )
   => ? [X2] :
        ( q(X2)
        & p(X2) ) ),
    file('/export/starexec/sandbox/benchmark/theBenchmark.p',y2141) ).

fof(f9,plain,
    ! [X0] :
      ( ~ q(X0)
      | ~ p(X0) ),
    inference(cnf_transformation,[],[f6]) ).

fof(f11,plain,
    ! [X1] : q(sK0(X1)),
    inference(subsumption_resolution,[],[f8,f10]) ).

fof(f8,plain,
    ! [X1] :
      ( q(X1)
      | q(sK0(X1)) ),
    inference(cnf_transformation,[],[f6]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.12  % Problem    : SYN733+1 : TPTP v8.1.2. Released v2.5.0.
% 0.13/0.14  % Command    : vampire --mode casc_sat -m 16384 --cores 7 -t %d %s
% 0.14/0.35  % Computer : n003.cluster.edu
% 0.14/0.35  % Model    : x86_64 x86_64
% 0.14/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35  % Memory   : 8042.1875MB
% 0.14/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35  % CPULimit   : 300
% 0.14/0.35  % WCLimit    : 300
% 0.14/0.35  % DateTime   : Fri May  3 17:19:38 EDT 2024
% 0.14/0.36  % CPUTime    : 
% 0.14/0.36  % (26908)Running in auto input_syntax mode. Trying TPTP
% 0.14/0.38  % (26910)fmb+10_1_bce=on:fmbas=expand:fmbksg=on:fmbsr=1.3_569 on theBenchmark for (569ds/0Mi)
% 0.14/0.38  % (26913)dis+1_20_av=off:lcm=predicate:nm=2:nwc=2.0_396 on theBenchmark for (396ds/0Mi)
% 0.14/0.38  % (26909)fmb+10_1_fmbas=off:fmbsr=1.3:nm=2_1451 on theBenchmark for (1451ds/0Mi)
% 0.14/0.38  % (26912)fmb+10_1_bce=on:fmbas=expand:fmbksg=on:fmbsr=1.3:gsp=on:nm=4_470 on theBenchmark for (470ds/0Mi)
% 0.14/0.38  % (26914)dis+11_4:5_nm=4_216 on theBenchmark for (216ds/0Mi)
% 0.14/0.38  % (26911)dis-2_2:3_amm=sco:anc=none:bce=on:fsr=off:gsp=on:nm=16:nwc=1.2:nicw=on:sac=on:sp=weighted_frequency_476 on theBenchmark for (476ds/0Mi)
% 0.14/0.38  % (26915)fmb+10_1_fmbas=off:fmbsr=1.3:nm=2:si=on:rtra=on:rawr=on:rp=on:fmbksg=on_1451 on theBenchmark for (1451ds/0Mi)
% 0.14/0.38  TRYING [1]
% 0.14/0.38  TRYING [1]
% 0.14/0.38  TRYING [1]
% 0.14/0.38  TRYING [1]
% 0.14/0.38  TRYING [2]
% 0.14/0.38  TRYING [2]
% 0.14/0.38  TRYING [2]
% 0.14/0.38  TRYING [2]
% 0.14/0.38  % (26915)Also succeeded, but the first one will report.
% 0.14/0.38  % (26909)Also succeeded, but the first one will report.
% 0.14/0.38  % (26914)Also succeeded, but the first one will report.
% 0.14/0.38  % (26913)First to succeed.
% 0.14/0.38  % (26912)Also succeeded, but the first one will report.
% 0.14/0.38  % (26910)Also succeeded, but the first one will report.
% 0.14/0.38  % (26911)Also succeeded, but the first one will report.
% 0.14/0.38  % (26913)Solution written to "/export/starexec/sandbox/tmp/vampire-proof-26908"
% 0.14/0.38  % (26913)Refutation found. Thanks to Tanya!
% 0.14/0.38  % SZS status Theorem for theBenchmark
% 0.14/0.38  % SZS output start Proof for theBenchmark
% See solution above
% 0.14/0.38  % (26913)------------------------------
% 0.14/0.38  % (26913)Version: Vampire 4.8 (commit 3a798227e on 2024-05-03 07:42:47 +0200)
% 0.14/0.38  % (26913)Termination reason: Refutation
% 0.14/0.38  
% 0.14/0.38  % (26913)Memory used [KB]: 727
% 0.14/0.38  % (26913)Time elapsed: 0.003 s
% 0.14/0.38  % (26913)Instructions burned: 2 (million)
% 0.14/0.38  % (26908)Success in time 0.018 s
%------------------------------------------------------------------------------