TSTP Solution File: SYN727+1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : SYN727+1 : TPTP v8.1.2. Released v2.5.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n029.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Fri Sep  1 03:35:52 EDT 2023

% Result   : Theorem 0.13s 0.39s
% Output   : Proof 0.21s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.13  % Problem  : SYN727+1 : TPTP v8.1.2. Released v2.5.0.
% 0.00/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.35  % Computer : n029.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 300
% 0.13/0.35  % DateTime : Sat Aug 26 20:06:55 EDT 2023
% 0.13/0.36  % CPUTime  : 
% 0.13/0.39  Command-line arguments: --flip-ordering --lhs-weight 1 --depth-weight 60 --distributivity-heuristic
% 0.13/0.39  
% 0.13/0.39  % SZS status Theorem
% 0.13/0.39  
% 0.13/0.39  % SZS output start Proof
% 0.13/0.39  Take the following subset of the input axioms:
% 0.13/0.40    fof(thm68, conjecture, (![X]: likes(X, bruce) & ![Y]: (?[Z]: likes(Y, Z) => likes(lyle, Y))) => ?[U]: ![V]: likes(U, V)).
% 0.13/0.40  
% 0.13/0.40  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.13/0.40  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.13/0.40  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.13/0.40    fresh(y, y, x1...xn) = u
% 0.13/0.40    C => fresh(s, t, x1...xn) = v
% 0.13/0.40  where fresh is a fresh function symbol and x1..xn are the free
% 0.13/0.40  variables of u and v.
% 0.13/0.40  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.13/0.40  input problem has no model of domain size 1).
% 0.13/0.40  
% 0.13/0.40  The encoding turns the above axioms into the following unit equations and goals:
% 0.13/0.40  
% 0.21/0.40  Axiom 1 (thm68): likes(X, bruce) = true2.
% 0.21/0.40  Axiom 2 (thm68_1): fresh(X, X, Y) = true2.
% 0.21/0.40  Axiom 3 (thm68_1): fresh(likes(X, Y), true2, X) = likes(lyle, X).
% 0.21/0.40  
% 0.21/0.40  Goal 1 (thm68_2): likes(X, v(X)) = true2.
% 0.21/0.40  The goal is true when:
% 0.21/0.40    X = lyle
% 0.21/0.40  
% 0.21/0.40  Proof:
% 0.21/0.40    likes(lyle, v(lyle))
% 0.21/0.40  = { by axiom 3 (thm68_1) R->L }
% 0.21/0.40    fresh(likes(v(lyle), bruce), true2, v(lyle))
% 0.21/0.40  = { by axiom 1 (thm68) }
% 0.21/0.40    fresh(true2, true2, v(lyle))
% 0.21/0.40  = { by axiom 2 (thm68_1) }
% 0.21/0.40    true2
% 0.21/0.40  % SZS output end Proof
% 0.21/0.40  
% 0.21/0.40  RESULT: Theorem (the conjecture is true).
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