TSTP Solution File: SYN557-1 by SPASS---3.9
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%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN557-1 : TPTP v8.1.0. Released v2.5.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n016.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:22:52 EDT 2022
% Result : Unsatisfiable 0.22s 0.50s
% Output : Refutation 0.22s
% Verified :
% SZS Type : Refutation
% Derivation depth : 7
% Number of leaves : 7
% Syntax : Number of clauses : 16 ( 11 unt; 0 nHn; 16 RR)
% Number of literals : 22 ( 0 equ; 7 neg)
% Maximal clause size : 3 ( 1 avg)
% Maximal term depth : 4 ( 2 avg)
% Number of predicates : 2 ( 1 usr; 1 prp; 0-2 aty)
% Number of functors : 10 ( 10 usr; 8 con; 0-2 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
p2(u,u),
file('SYN557-1.p',unknown),
[] ).
cnf(3,axiom,
~ p2(c6,f3(c8,f5(c9))),
file('SYN557-1.p',unknown),
[] ).
cnf(4,axiom,
p2(f3(u,v),f3(v,u)),
file('SYN557-1.p',unknown),
[] ).
cnf(6,axiom,
( ~ p2(u,v)
| ~ p2(u,w)
| p2(w,v) ),
file('SYN557-1.p',unknown),
[] ).
cnf(8,axiom,
( ~ p2(f3(u,v),f3(w,v))
| p2(u,w) ),
file('SYN557-1.p',unknown),
[] ).
cnf(10,axiom,
p2(f3(u,f3(v,w)),f3(v,f3(u,w))),
file('SYN557-1.p',unknown),
[] ).
cnf(12,axiom,
p2(f3(c6,f5(c7)),f3(c8,f3(f5(c7),f5(c9)))),
file('SYN557-1.p',unknown),
[] ).
cnf(20,plain,
( ~ p2(u,v)
| p2(v,u) ),
inference(res,[status(thm),theory(equality)],[1,6]),
[iquote('0:Res:1.0,6.0')] ).
cnf(21,plain,
( ~ p2(f3(u,v),w)
| p2(w,f3(v,u)) ),
inference(res,[status(thm),theory(equality)],[4,6]),
[iquote('0:Res:4.0,6.0')] ).
cnf(24,plain,
( ~ p2(f3(u,f3(v,w)),x)
| p2(x,f3(v,f3(u,w))) ),
inference(res,[status(thm),theory(equality)],[10,6]),
[iquote('0:Res:10.0,6.0')] ).
cnf(34,plain,
p2(f3(c8,f3(f5(c7),f5(c9))),f3(c6,f5(c7))),
inference(res,[status(thm),theory(equality)],[12,20]),
[iquote('0:Res:12.0,20.0')] ).
cnf(248,plain,
p2(f3(c6,f5(c7)),f3(f5(c7),f3(c8,f5(c9)))),
inference(res,[status(thm),theory(equality)],[34,24]),
[iquote('0:Res:34.0,24.0')] ).
cnf(294,plain,
p2(f3(f5(c7),f3(c8,f5(c9))),f3(c6,f5(c7))),
inference(res,[status(thm),theory(equality)],[248,20]),
[iquote('0:Res:248.0,20.0')] ).
cnf(329,plain,
p2(f3(c6,f5(c7)),f3(f3(c8,f5(c9)),f5(c7))),
inference(res,[status(thm),theory(equality)],[294,21]),
[iquote('0:Res:294.0,21.0')] ).
cnf(359,plain,
p2(c6,f3(c8,f5(c9))),
inference(res,[status(thm),theory(equality)],[329,8]),
[iquote('0:Res:329.0,8.0')] ).
cnf(363,plain,
$false,
inference(mrr,[status(thm)],[359,3]),
[iquote('0:MRR:359.0,3.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.04/0.14 % Problem : SYN557-1 : TPTP v8.1.0. Released v2.5.0.
% 0.04/0.15 % Command : run_spass %d %s
% 0.15/0.36 % Computer : n016.cluster.edu
% 0.15/0.36 % Model : x86_64 x86_64
% 0.15/0.36 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.15/0.36 % Memory : 8042.1875MB
% 0.15/0.36 % OS : Linux 3.10.0-693.el7.x86_64
% 0.15/0.36 % CPULimit : 300
% 0.15/0.36 % WCLimit : 600
% 0.15/0.36 % DateTime : Tue Jul 12 08:17:59 EDT 2022
% 0.15/0.36 % CPUTime :
% 0.22/0.50
% 0.22/0.50 SPASS V 3.9
% 0.22/0.50 SPASS beiseite: Proof found.
% 0.22/0.50 % SZS status Theorem
% 0.22/0.50 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.22/0.50 SPASS derived 349 clauses, backtracked 0 clauses, performed 0 splits and kept 250 clauses.
% 0.22/0.50 SPASS allocated 63409 KBytes.
% 0.22/0.50 SPASS spent 0:00:00.12 on the problem.
% 0.22/0.50 0:00:00.03 for the input.
% 0.22/0.50 0:00:00.00 for the FLOTTER CNF translation.
% 0.22/0.50 0:00:00.01 for inferences.
% 0.22/0.50 0:00:00.00 for the backtracking.
% 0.22/0.50 0:00:00.06 for the reduction.
% 0.22/0.50
% 0.22/0.50
% 0.22/0.50 Here is a proof with depth 6, length 16 :
% 0.22/0.50 % SZS output start Refutation
% See solution above
% 0.22/0.50 Formulae used in the proof : p2_1 not_p2_3 p2_4 p2_6 p2_8 p2_10 p2_12
% 0.22/0.50
%------------------------------------------------------------------------------