TSTP Solution File: SYN551+1 by SPASS---3.9

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SPASS---3.9
% Problem  : SYN551+1 : TPTP v8.1.0. Bugfixed v3.1.0.
% Transfm  : none
% Format   : tptp
% Command  : run_spass %d %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:22:49 EDT 2022

% Result   : Theorem 0.18s 0.45s
% Output   : Refutation 0.18s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.11  % Problem  : SYN551+1 : TPTP v8.1.0. Bugfixed v3.1.0.
% 0.07/0.12  % Command  : run_spass %d %s
% 0.13/0.33  % Computer : n017.cluster.edu
% 0.13/0.33  % Model    : x86_64 x86_64
% 0.13/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.33  % Memory   : 8042.1875MB
% 0.13/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.33  % CPULimit : 300
% 0.13/0.33  % WCLimit  : 600
% 0.13/0.33  % DateTime : Mon Jul 11 22:24:34 EDT 2022
% 0.13/0.33  % CPUTime  : 
% 0.18/0.45  
% 0.18/0.45  SPASS V 3.9 
% 0.18/0.45  SPASS beiseite: Proof found.
% 0.18/0.45  % SZS status Theorem
% 0.18/0.45  Problem: /export/starexec/sandbox/benchmark/theBenchmark.p 
% 0.18/0.45  SPASS derived 45 clauses, backtracked 17 clauses, performed 3 splits and kept 48 clauses.
% 0.18/0.45  SPASS allocated 85280 KBytes.
% 0.18/0.45  SPASS spent	0:00:00.10 on the problem.
% 0.18/0.45  		0:00:00.04 for the input.
% 0.18/0.45  		0:00:00.04 for the FLOTTER CNF translation.
% 0.18/0.45  		0:00:00.00 for inferences.
% 0.18/0.45  		0:00:00.00 for the backtracking.
% 0.18/0.45  		0:00:00.00 for the reduction.
% 0.18/0.45  
% 0.18/0.45  
% 0.18/0.45  Here is a proof with depth 5, length 59 :
% 0.18/0.45  % SZS output start Refutation
% 0.18/0.45  1[0:Inp] ||  -> SkC0 equal(g(f(skc6)),skc6)**.
% 0.18/0.45  2[0:Inp] || SkC0 -> equal(f(g(skc9)),skc9)**.
% 0.18/0.45  3[0:Inp] || equal(skc11,skc10) equal(f(g(u)),u)** -> SkC0.
% 0.18/0.45  4[0:Inp] || SkC0 equal(skc8,skc7) equal(g(f(u)),u)** -> .
% 0.18/0.45  5[0:Inp] || equal(f(g(u)),u)** -> SkC0 equal(f(g(skc11)),skc11)**.
% 0.18/0.45  6[0:Inp] || equal(f(g(u)),u)** -> SkC0 equal(f(g(skc10)),skc10)**.
% 0.18/0.45  7[0:Inp] || SkC0 equal(g(f(u)),u)** -> equal(g(f(skc8)),skc8)**.
% 0.18/0.45  8[0:Inp] || SkC0 equal(g(f(u)),u)** -> equal(g(f(skc7)),skc7)**.
% 0.18/0.45  9[0:Inp] || equal(g(f(u)),u)**+ equal(g(f(v)),v)** -> SkC0 equal(v,u)*.
% 0.18/0.45  10[0:Inp] || SkC0 equal(f(g(u)),u)** equal(f(g(v)),v)** -> equal(v,u)*.
% 0.18/0.45  11[1:Spt:9.2] ||  -> SkC0*.
% 0.18/0.45  12[1:MRR:2.0,11.0] ||  -> equal(f(g(skc9)),skc9)**.
% 0.18/0.45  13[1:MRR:4.0,11.0] || equal(skc8,skc7) equal(g(f(u)),u)** -> .
% 0.18/0.45  14[1:MRR:8.0,11.0] || equal(g(f(u)),u)**+ -> equal(g(f(skc7)),skc7)**.
% 0.18/0.45  15[1:MRR:7.0,11.0] || equal(g(f(u)),u)**+ -> equal(g(f(skc8)),skc8)**.
% 0.18/0.45  16[1:MRR:10.0,11.0] || equal(f(g(u)),u)**+ equal(f(g(v)),v)** -> equal(v,u)*.
% 0.18/0.45  18[2:Spt:13.1] || equal(g(f(u)),u)** -> .
% 0.18/0.45  19[2:SpL:12.0,18.0] || equal(g(skc9),g(skc9))* -> .
% 0.18/0.45  20[2:Obv:19.0] ||  -> .
% 0.18/0.45  21[2:Spt:20.0,13.0] || equal(skc8,skc7)** -> .
% 0.18/0.45  22[1:SpL:12.0,14.0] || equal(g(skc9),g(skc9)) -> equal(g(f(skc7)),skc7)**.
% 0.18/0.45  23[1:Obv:22.0] ||  -> equal(g(f(skc7)),skc7)**.
% 0.18/0.45  26[1:SpL:23.0,15.0] || equal(skc7,skc7) -> equal(g(f(skc8)),skc8)**.
% 0.18/0.45  27[1:Obv:26.0] ||  -> equal(g(f(skc8)),skc8)**.
% 0.18/0.45  32[1:SpL:12.0,16.0] || equal(skc9,skc9) equal(f(g(u)),u)** -> equal(u,skc9).
% 0.18/0.45  33[1:Obv:32.0] || equal(f(g(u)),u)** -> equal(u,skc9).
% 0.18/0.45  36[1:SpL:23.0,33.0] || equal(f(skc7),f(skc7))* -> equal(f(skc7),skc9).
% 0.18/0.45  37[1:SpL:27.0,33.0] || equal(f(skc8),f(skc8))* -> equal(f(skc8),skc9).
% 0.18/0.45  39[1:Obv:36.0] ||  -> equal(f(skc7),skc9)**.
% 0.18/0.45  40[1:Rew:39.0,23.0] ||  -> equal(g(skc9),skc7)**.
% 0.18/0.45  43[1:Obv:37.0] ||  -> equal(f(skc8),skc9)**.
% 0.18/0.45  44[1:Rew:43.0,27.0] ||  -> equal(g(skc9),skc8)**.
% 0.18/0.45  46[1:Rew:40.0,44.0] ||  -> equal(skc8,skc7)**.
% 0.18/0.45  47[2:MRR:46.0,21.0] ||  -> .
% 0.18/0.45  48[1:Spt:47.0,9.2,11.0] || SkC0* -> .
% 0.18/0.45  49[1:Spt:47.0,9.0,9.1,9.3] || equal(g(f(u)),u)**+ equal(g(f(v)),v)** -> equal(v,u)*.
% 0.18/0.45  50[1:MRR:1.0,48.0] ||  -> equal(g(f(skc6)),skc6)**.
% 0.18/0.45  51[1:MRR:3.2,48.0] || equal(skc11,skc10) equal(f(g(u)),u)** -> .
% 0.18/0.45  52[1:MRR:6.1,48.0] || equal(f(g(u)),u)**+ -> equal(f(g(skc10)),skc10)**.
% 0.18/0.45  53[1:MRR:5.1,48.0] || equal(f(g(u)),u)**+ -> equal(f(g(skc11)),skc11)**.
% 0.18/0.45  55[1:SpL:50.0,49.0] || equal(skc6,skc6) equal(g(f(u)),u)** -> equal(u,skc6).
% 0.18/0.45  56[1:Obv:55.0] || equal(g(f(u)),u)** -> equal(u,skc6).
% 0.18/0.45  58[2:Spt:51.1] || equal(f(g(u)),u)** -> .
% 0.18/0.45  59[2:SpL:50.0,58.0] || equal(f(skc6),f(skc6))* -> .
% 0.18/0.45  60[2:Obv:59.0] ||  -> .
% 0.18/0.45  61[2:Spt:60.0,51.0] || equal(skc11,skc10)** -> .
% 0.18/0.45  62[1:SpL:50.0,52.0] || equal(f(skc6),f(skc6)) -> equal(f(g(skc10)),skc10)**.
% 0.18/0.45  63[1:Obv:62.0] ||  -> equal(f(g(skc10)),skc10)**.
% 0.18/0.45  65[1:SpL:63.0,56.0] || equal(g(skc10),g(skc10))* -> equal(g(skc10),skc6).
% 0.18/0.45  67[1:Obv:65.0] ||  -> equal(g(skc10),skc6)**.
% 0.18/0.45  68[1:Rew:67.0,63.0] ||  -> equal(f(skc6),skc10)**.
% 0.18/0.45  73[1:SpL:67.0,53.0] || equal(f(skc6),skc10) -> equal(f(g(skc11)),skc11)**.
% 0.18/0.45  74[1:Rew:68.0,73.0] || equal(skc10,skc10) -> equal(f(g(skc11)),skc11)**.
% 0.18/0.45  75[1:Obv:74.0] ||  -> equal(f(g(skc11)),skc11)**.
% 0.18/0.45  80[1:SpL:75.0,56.0] || equal(g(skc11),g(skc11))* -> equal(g(skc11),skc6).
% 0.18/0.45  82[1:Obv:80.0] ||  -> equal(g(skc11),skc6)**.
% 0.18/0.45  83[1:Rew:82.0,75.0] ||  -> equal(f(skc6),skc11)**.
% 0.18/0.45  84[1:Rew:68.0,83.0] ||  -> equal(skc11,skc10)**.
% 0.18/0.45  85[2:MRR:84.0,61.0] ||  -> .
% 0.18/0.45  % SZS output end Refutation
% 0.18/0.45  Formulae used in the proof : prove_this_cute_thing
% 0.18/0.45  
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