TSTP Solution File: SYN408+1 by Metis---2.4

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%------------------------------------------------------------------------------
% File     : Metis---2.4
% Problem  : SYN408+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : metis --show proof --show saturation %s

% Computer : n008.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 09:02:11 EDT 2022

% Result   : Theorem 0.19s 0.35s
% Output   : CNFRefutation 0.19s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    8
%            Number of leaves      :    1
% Syntax   : Number of formulae    :   13 (   7 unt;   0 def)
%            Number of atoms       :   23 (   0 equ)
%            Maximal formula atoms :    3 (   1 avg)
%            Number of connectives :   22 (  12   ~;   0   |;   4   &)
%                                         (   0 <=>;   6  =>;   0  <=;   0 <~>)
%            Maximal formula depth :    5 (   3 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    3 (   2 usr;   1 prp; 0-1 aty)
%            Number of functors    :    1 (   1 usr;   1 con; 0-0 aty)
%            Number of variables   :   12 (   1 sgn   6   !;   5   ?)

% Comments : 
%------------------------------------------------------------------------------
fof(kalish244,conjecture,
    ( ~ ? [X] : f(X)
   => ! [Y] :
        ( f(Y)
       => g(Y) ) ) ).

fof(subgoal_0,plain,
    ( ~ ? [X] : f(X)
   => ! [Y] :
        ( f(Y)
       => g(Y) ) ),
    inference(strip,[],[kalish244]) ).

fof(negate_0_0,plain,
    ~ ( ~ ? [X] : f(X)
     => ! [Y] :
          ( f(Y)
         => g(Y) ) ),
    inference(negate,[],[subgoal_0]) ).

fof(normalize_0_0,plain,
    ( ? [Y] :
        ( ~ g(Y)
        & f(Y) )
    & ! [X] : ~ f(X) ),
    inference(canonicalize,[],[negate_0_0]) ).

fof(normalize_0_1,plain,
    ? [Y] :
      ( ~ g(Y)
      & f(Y) ),
    inference(conjunct,[],[normalize_0_0]) ).

fof(normalize_0_2,plain,
    ( ~ g(skolemFOFtoCNF_Y)
    & f(skolemFOFtoCNF_Y) ),
    inference(skolemize,[],[normalize_0_1]) ).

fof(normalize_0_3,plain,
    f(skolemFOFtoCNF_Y),
    inference(conjunct,[],[normalize_0_2]) ).

fof(normalize_0_4,plain,
    ! [X] : ~ f(X),
    inference(conjunct,[],[normalize_0_0]) ).

fof(normalize_0_5,plain,
    ! [X] : ~ f(X),
    inference(specialize,[],[normalize_0_4]) ).

cnf(refute_0_0,plain,
    f(skolemFOFtoCNF_Y),
    inference(canonicalize,[],[normalize_0_3]) ).

cnf(refute_0_1,plain,
    ~ f(X),
    inference(canonicalize,[],[normalize_0_5]) ).

cnf(refute_0_2,plain,
    ~ f(skolemFOFtoCNF_Y),
    inference(subst,[],[refute_0_1:[bind(X,$fot(skolemFOFtoCNF_Y))]]) ).

cnf(refute_0_3,plain,
    $false,
    inference(resolve,[$cnf( f(skolemFOFtoCNF_Y) )],[refute_0_0,refute_0_2]) ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.01/0.12  % Problem  : SYN408+1 : TPTP v8.1.0. Released v2.0.0.
% 0.12/0.13  % Command  : metis --show proof --show saturation %s
% 0.12/0.34  % Computer : n008.cluster.edu
% 0.12/0.34  % Model    : x86_64 x86_64
% 0.12/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34  % Memory   : 8042.1875MB
% 0.12/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34  % CPULimit : 300
% 0.12/0.34  % WCLimit  : 600
% 0.12/0.34  % DateTime : Tue Jul 12 01:17:53 EDT 2022
% 0.12/0.35  % CPUTime  : 
% 0.19/0.35  %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% 0.19/0.35  % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.35  
% 0.19/0.35  % SZS output start CNFRefutation for /export/starexec/sandbox/benchmark/theBenchmark.p
% See solution above
% 0.19/0.35  
%------------------------------------------------------------------------------