TSTP Solution File: SYN357^5 by cocATP---0.2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : cocATP---0.2.0
% Problem  : SYN357^5 : TPTP v6.1.0. Released v4.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p

% Computer : n096.star.cs.uiowa.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2609 0 2.40GHz
% Memory   : 32286.75MB
% OS       : Linux 2.6.32-431.20.3.el6.x86_64
% CPULimit : 300s
% DateTime : Thu Jul 17 13:38:15 EDT 2014

% Result   : Theorem 0.36s
% Output   : Proof 0.36s
% Verified : 
% SZS Type : None (Parsing solution fails)
% Syntax   : Number of formulae    : 0

% Comments : 
%------------------------------------------------------------------------------
%----ERROR: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% % Problem  : SYN357^5 : TPTP v6.1.0. Released v4.0.0.
% % Command  : python CASC.py /export/starexec/sandbox/benchmark/theBenchmark.p
% % Computer : n096.star.cs.uiowa.edu
% % Model    : x86_64 x86_64
% % CPU      : Intel(R) Xeon(R) CPU E5-2609 0 @ 2.40GHz
% % Memory   : 32286.75MB
% % OS       : Linux 2.6.32-431.20.3.el6.x86_64
% % CPULimit : 300
% % DateTime : Thu Jul 17 09:25:21 CDT 2014
% % CPUTime: 0.36 
% Python 2.7.5
% Using paths ['/home/cristobal/cocATP/CASC/TPTP/', '/export/starexec/sandbox/benchmark/', '/export/starexec/sandbox/benchmark/']
% FOF formula (<kernel.Constant object at 0x1c5d758>, <kernel.DependentProduct object at 0x1c3d050>) of role type named cP
% Using role type
% Declaring cP:(fofType->Prop)
% FOF formula (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))) of role conjecture named cLX2108
% Conjecture to prove = (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))):Prop
% Parameter fofType_DUMMY:fofType.
% We need to prove ['(forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))))']
% Parameter fofType:Type.
% Parameter cP:(fofType->Prop).
% Trying to prove (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))))
% Found x0:(cP X)
% Instantiate: x:=X:fofType
% Found (fun (x0:(cP X))=> x0) as proof of (cP x)
% Found (fun (x0:(cP X))=> x0) as proof of ((cP X)->(cP x))
% Found (ex_intro000 (fun (x0:(cP X))=> x0)) as proof of ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))
% Found ((ex_intro00 X) (fun (x0:(cP X))=> x0)) as proof of ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))
% Found (((ex_intro0 (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0)) as proof of ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))
% Found ((((ex_intro fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0)) as proof of ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))
% Found (fun (X:fofType)=> ((((ex_intro fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0))) as proof of ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y))))
% Found (fun (X:fofType)=> ((((ex_intro fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0))) as proof of (forall (X:fofType), ((ex fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))))
% Got proof (fun (X:fofType)=> ((((ex_intro fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0)))
% Time elapsed = 0.044033s
% node=7 cost=221.000000 depth=7
% ::::::::::::::::::::::
% % SZS status Theorem for /export/starexec/sandbox/benchmark/theBenchmark.p
% % SZS output start Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% (fun (X:fofType)=> ((((ex_intro fofType) (fun (Y:fofType)=> ((cP X)->(cP Y)))) X) (fun (x0:(cP X))=> x0)))
% % SZS output end Proof for /export/starexec/sandbox/benchmark/theBenchmark.p
% EOF
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