%------------------------------------------------------------------------------
% File     : Crossbow---0.1
% Problem  : SYN348+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : do_Crossbow---0.1 %s

% Computer : n004.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 03:01:34 EDT 2022

% Result   : CounterSatisfiable 0.20s 0.50s
% Output   : FiniteModel 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem    : SYN348+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.13  % Command    : do_Crossbow---0.1 %s
% 0.13/0.34  % Computer : n004.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit   : 300
% 0.13/0.34  % WCLimit    : 600
% 0.13/0.34  % DateTime   : Tue Jul 12 07:45:37 EDT 2022
% 0.13/0.34  % CPUTime    : 
% 0.13/0.35  /export/starexec/sandbox/solver/bin
% 0.13/0.35  crossbow.opt
% 0.13/0.35  do_Crossbow---0.1
% 0.13/0.35  eprover
% 0.13/0.35  runsolver
% 0.13/0.35  starexec_run_Crossbow---0.1
% 0.20/0.50  % SZS status CounterSatisfiable for theBenchmark.p
% 0.20/0.50  % SZS output start FiniteModel for theBenchmark.p
% 0.20/0.50  % domain size: 2
% 0.20/0.50  fof(interp, fi_domain, ![X] : (X = 0 | X = 1)).
% 0.20/0.50  fof(interp, fi_predicates, big_f(0, 0) & ~big_f(0, 1) & big_f(1, 0) &
% 0.20/0.50    big_f(1, 1)).
% 0.20/0.50  fof(interp, fi_functors, esk1_1(0) = 1 & esk1_1(1) = 0).
% 0.20/0.50  fof(interp, fi_functors, esk2_2(0, 0) = 0 & esk2_2(0, 1) = 0 & esk2_2(1, 0) = 0 &
% 0.20/0.50    esk2_2(1, 1) = 0).
% 0.20/0.50  fof(interp, fi_functors, esk3_2(0, 0) = 0 & esk3_2(0, 1) = 0 & esk3_2(1, 0) = 1 &
% 0.20/0.50    esk3_2(1, 1) = 0).
% 0.20/0.50  % SZS output end FiniteModel for theBenchmark.p
% 0.20/0.50  % 0 lemma(s) from E
% 0.20/0.50  % 129 pred(s)
% 0.20/0.50  % 3 func(s)
% 0.20/0.50  % 1 sort(s)
% 0.20/0.50  % 192 clause(s)
% 0.20/0.50  % Instantiating 1 (113 ms)
% 0.20/0.50  % Solving (114 ms)
% 0.20/0.50  % Instantiating 2 (114 ms)
% 0.20/0.50  % Solving (118 ms)
% 0.20/0.50  % 
% 0.20/0.50  % 1 model found (119 ms)
%------------------------------------------------------------------------------