TSTP Solution File: SYN313-1.001.002 by SOS---2.0

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : SOS---2.0
% Problem  : SYN313-1.001.002 : TPTP v8.1.0. Released v1.2.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : sos-script %s

% Computer : n022.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 12:11:38 EDT 2022

% Result   : Unsatisfiable 0.20s 0.47s
% Output   : Refutation 0.20s
% Verified : 
% SZS Type : -

% Comments : 
%------------------------------------------------------------------------------
%----WARNING: Could not form TPTP format derivation
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.03/0.12  % Problem  : SYN313-1.001.002 : TPTP v8.1.0. Released v1.2.0.
% 0.03/0.13  % Command  : sos-script %s
% 0.14/0.34  % Computer : n022.cluster.edu
% 0.14/0.34  % Model    : x86_64 x86_64
% 0.14/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34  % Memory   : 8042.1875MB
% 0.14/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34  % CPULimit : 300
% 0.14/0.34  % WCLimit  : 600
% 0.14/0.34  % DateTime : Tue Jul 12 05:21:55 EDT 2022
% 0.14/0.34  % CPUTime  : 
% 0.14/0.36  ----- Otter 3.2, August 2001 -----
% 0.14/0.36  The process was started by sandbox2 on n022.cluster.edu,
% 0.14/0.36  Tue Jul 12 05:21:55 2022
% 0.14/0.36  The command was "./sos".  The process ID is 18320.
% 0.14/0.36  
% 0.14/0.36  set(prolog_style_variables).
% 0.14/0.36  set(auto).
% 0.14/0.36     dependent: set(auto1).
% 0.14/0.36     dependent: set(process_input).
% 0.14/0.36     dependent: clear(print_kept).
% 0.14/0.36     dependent: clear(print_new_demod).
% 0.14/0.36     dependent: clear(print_back_demod).
% 0.14/0.36     dependent: clear(print_back_sub).
% 0.14/0.36     dependent: set(control_memory).
% 0.14/0.36     dependent: assign(max_mem, 12000).
% 0.14/0.36     dependent: assign(pick_given_ratio, 4).
% 0.14/0.36     dependent: assign(stats_level, 1).
% 0.14/0.36     dependent: assign(pick_semantic_ratio, 3).
% 0.14/0.36     dependent: assign(sos_limit, 5000).
% 0.14/0.36     dependent: assign(max_weight, 60).
% 0.14/0.36  clear(print_given).
% 0.14/0.36  
% 0.14/0.36  list(usable).
% 0.14/0.36  
% 0.14/0.36  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=3.
% 0.14/0.36  
% 0.14/0.36  This is a non-Horn set without equality.  The strategy
% 0.14/0.36  will be ordered hyper_res, ur_res, unit deletion, and
% 0.14/0.36  factoring, with satellites in sos and nuclei in usable.
% 0.14/0.36  
% 0.14/0.36     dependent: set(hyper_res).
% 0.14/0.36     dependent: set(factor).
% 0.14/0.36     dependent: set(unit_deletion).
% 0.14/0.36  
% 0.14/0.36  ------------> process usable:
% 0.14/0.36  
% 0.14/0.36  ------------> process sos:
% 0.14/0.36  
% 0.14/0.36  ======= end of input processing =======
% 0.20/0.38  
% 0.20/0.38  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.38  
% 0.20/0.38  Stopped by limit on number of solutions
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  -------------- Softie stats --------------
% 0.20/0.38  
% 0.20/0.38  UPDATE_STOP: 300
% 0.20/0.38  SFINDER_TIME_LIMIT: 2
% 0.20/0.38  SHORT_CLAUSE_CUTOFF: 4
% 0.20/0.38  number of clauses in intial UL: 1
% 0.20/0.38  number of clauses initially in problem: 2
% 0.20/0.38  percentage of clauses intially in UL: 50
% 0.20/0.38  percentage of distinct symbols occuring in initial UL: 33
% 0.20/0.38  percent of all initial clauses that are short: 50
% 0.20/0.38  absolute distinct symbol count: 9
% 0.20/0.38     distinct predicate count: 1
% 0.20/0.38     distinct function count: 7
% 0.20/0.38     distinct constant count: 1
% 0.20/0.38  
% 0.20/0.38  ---------- no more Softie stats ----------
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  
% 0.20/0.38  =========== start of search ===========
% 0.20/0.47  
% 0.20/0.47  -------- PROOF -------- 
% 0.20/0.47  % SZS status Unsatisfiable
% 0.20/0.47  % SZS output start Refutation
% 0.20/0.47  
% 0.20/0.47  -----> EMPTY CLAUSE at   0.09 sec ----> 283 [hyper,277,1,277] {-} $F.
% 0.20/0.47  
% 0.20/0.47  Length of proof is 6.  Level of proof is 6.
% 0.20/0.47  
% 0.20/0.47  ---------------- PROOF ----------------
% 0.20/0.47  % SZS status Unsatisfiable
% 0.20/0.47  % SZS output start Refutation
% 0.20/0.47  
% 0.20/0.47  1 [] {+} -p(A,f0(A),B)| -p(A,f1(B),C).
% 0.20/0.47  2 [] {-} p(h0,A,j0(B))|p(h1(A),C,j1(B))|p(h2(C),B,j2(B)).
% 0.20/0.47  3 [hyper,2,1,2] {-} p(h1(f1(j0(A))),B,j1(C))|p(h2(B),C,j2(C))|p(h1(f0(h0)),D,j1(A))|p(h2(D),A,j2(A)).
% 0.20/0.47  62 [hyper,3,1,3,factor_simp,factor_simp] {-} p(h2(f1(j1(A))),B,j2(B))|p(h1(f0(h0)),C,j1(D))|p(h2(C),D,j2(D))|p(h2(f0(h1(f1(j0(D))))),A,j2(A)).
% 0.20/0.47  166 [hyper,62,1,62,factor_simp,factor_simp,factor_simp] {-} p(h1(f0(h0)),A,j1(B))|p(h2(A),B,j2(B))|p(h2(f0(h1(f1(j0(B))))),C,j2(C)).
% 0.20/0.47  252 [hyper,166,1,166,factor_simp,factor_simp] {-} p(h1(f0(h0)),A,j1(B))|p(h2(A),B,j2(B)).
% 0.20/0.47  260 [hyper,252,1,252] {-} p(h2(f1(j1(A))),B,j2(B))|p(h2(f0(h1(f0(h0)))),A,j2(A)).
% 0.20/0.47  277 [hyper,260,1,260,factor_simp] {-} p(h2(f0(h1(f0(h0)))),A,j2(A)).
% 0.20/0.47  283 [hyper,277,1,277] {-} $F.
% 0.20/0.47  
% 0.20/0.47  % SZS output end Refutation
% 0.20/0.47  ------------ end of proof -------------
% 0.20/0.47  
% 0.20/0.47  
% 0.20/0.47  Search stopped by max_proofs option.
% 0.20/0.47  
% 0.20/0.47  
% 0.20/0.47  Search stopped by max_proofs option.
% 0.20/0.47  
% 0.20/0.47  ============ end of search ============
% 0.20/0.47  
% 0.20/0.47  ----------- soft-scott stats ----------
% 0.20/0.47  
% 0.20/0.47  true clauses given           2      (10.0%)
% 0.20/0.47  false clauses given         18
% 0.20/0.47  
% 0.20/0.47        FALSE     TRUE
% 0.20/0.47    20  1         0
% 0.20/0.47    26  1         0
% 0.20/0.47    28  2         0
% 0.20/0.47    30  2         0
% 0.20/0.47    33  1         0
% 0.20/0.47    37  0         2
% 0.20/0.47    39  1         0
% 0.20/0.47    41  2         0
% 0.20/0.47    43  1         0
% 0.20/0.47    44  1         0
% 0.20/0.47    45  0         1
% 0.20/0.47    46  1         0
% 0.20/0.47    47  0         1
% 0.20/0.47    50  1         0
% 0.20/0.47    51  3         0
% 0.20/0.47    54  2         0
% 0.20/0.47    56  1         0
% 0.20/0.47    58  2         0
% 0.20/0.47    59  2         0
% 0.20/0.47  tot:  24        4      (14.3% true)
% 0.20/0.47  
% 0.20/0.47  
% 0.20/0.47  Model 1 (0.00 seconds, 0 Inserts)
% 0.20/0.47  
% 0.20/0.47  That finishes the proof of the theorem.
% 0.20/0.47  
% 0.20/0.47  Process 18320 finished Tue Jul 12 05:21:55 2022
%------------------------------------------------------------------------------