TSTP Solution File: SYN070+1 by SPASS---3.9
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- Process Solution
%------------------------------------------------------------------------------
% File : SPASS---3.9
% Problem : SYN070+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm : none
% Format : tptp
% Command : run_spass %d %s
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 600s
% DateTime : Thu Jul 21 12:18:18 EDT 2022
% Result : Theorem 0.19s 0.42s
% Output : Refutation 0.19s
% Verified :
% SZS Type : Refutation
% Derivation depth : 6
% Number of leaves : 7
% Syntax : Number of clauses : 18 ( 8 unt; 6 nHn; 18 RR)
% Number of literals : 34 ( 0 equ; 15 neg)
% Maximal clause size : 4 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 5 ( 4 usr; 1 prp; 0-2 aty)
% Number of functors : 4 ( 4 usr; 4 con; 0-0 aty)
% Number of variables : 0 ( 0 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
big(skc2),
file('SYN070+1.p',unknown),
[] ).
cnf(3,axiom,
~ big_g(skc2),
file('SYN070+1.p',unknown),
[] ).
cnf(4,axiom,
( ~ big(u)
| big(v)
| big_g(u) ),
file('SYN070+1.p',unknown),
[] ).
cnf(5,axiom,
( ~ big(u)
| big_h(v,u)
| big_g(u) ),
file('SYN070+1.p',unknown),
[] ).
cnf(6,axiom,
( ~ big_g(u)
| ~ big(v)
| big_g(v) ),
file('SYN070+1.p',unknown),
[] ).
cnf(8,axiom,
( ~ big(u)
| big_g(u)
| big_j(skc3,u) ),
file('SYN070+1.p',unknown),
[] ).
cnf(9,axiom,
( ~ big(u)
| ~ big(v)
| ~ big_j(v,u)
| ~ big_h(u,v) ),
file('SYN070+1.p',unknown),
[] ).
cnf(14,plain,
( big(u)
| big_g(skc2) ),
inference(res,[status(thm),theory(equality)],[1,4]),
[iquote('0:Res:1.0,4.0')] ).
cnf(16,plain,
( ~ big_g(u)
| big_g(skc2) ),
inference(res,[status(thm),theory(equality)],[1,6]),
[iquote('0:Res:1.0,6.1')] ).
cnf(22,plain,
big(u),
inference(mrr,[status(thm)],[14,3]),
[iquote('0:MRR:14.1,3.0')] ).
cnf(23,plain,
( big_g(u)
| big_j(skc3,u) ),
inference(mrr,[status(thm)],[8,22]),
[iquote('0:MRR:8.0,22.0')] ).
cnf(25,plain,
( big_h(u,v)
| big_g(v) ),
inference(mrr,[status(thm)],[5,22]),
[iquote('0:MRR:5.0,22.0')] ).
cnf(26,plain,
( ~ big_j(u,v)
| ~ big_h(v,u) ),
inference(mrr,[status(thm)],[9,22]),
[iquote('0:MRR:9.1,9.0,22.0')] ).
cnf(31,plain,
~ big_g(u),
inference(mrr,[status(thm)],[16,3]),
[iquote('0:MRR:16.1,3.0')] ).
cnf(32,plain,
big_j(skc3,u),
inference(mrr,[status(thm)],[23,31]),
[iquote('0:MRR:23.0,31.0')] ).
cnf(33,plain,
big_h(u,v),
inference(mrr,[status(thm)],[25,31]),
[iquote('0:MRR:25.1,31.0')] ).
cnf(34,plain,
~ big_j(u,v),
inference(mrr,[status(thm)],[26,33]),
[iquote('0:MRR:26.1,33.0')] ).
cnf(35,plain,
$false,
inference(unc,[status(thm)],[34,32]),
[iquote('0:UnC:34.0,32.0')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SYN070+1 : TPTP v8.1.0. Released v2.0.0.
% 0.07/0.12 % Command : run_spass %d %s
% 0.12/0.33 % Computer : n028.cluster.edu
% 0.12/0.33 % Model : x86_64 x86_64
% 0.12/0.33 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33 % Memory : 8042.1875MB
% 0.12/0.33 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33 % CPULimit : 300
% 0.12/0.33 % WCLimit : 600
% 0.12/0.33 % DateTime : Mon Jul 11 20:51:44 EDT 2022
% 0.12/0.33 % CPUTime :
% 0.19/0.42
% 0.19/0.42 SPASS V 3.9
% 0.19/0.42 SPASS beiseite: Proof found.
% 0.19/0.42 % SZS status Theorem
% 0.19/0.42 Problem: /export/starexec/sandbox/benchmark/theBenchmark.p
% 0.19/0.42 SPASS derived 17 clauses, backtracked 0 clauses, performed 0 splits and kept 17 clauses.
% 0.19/0.42 SPASS allocated 97619 KBytes.
% 0.19/0.42 SPASS spent 0:00:00.08 on the problem.
% 0.19/0.42 0:00:00.03 for the input.
% 0.19/0.42 0:00:00.02 for the FLOTTER CNF translation.
% 0.19/0.42 0:00:00.00 for inferences.
% 0.19/0.42 0:00:00.00 for the backtracking.
% 0.19/0.42 0:00:00.00 for the reduction.
% 0.19/0.42
% 0.19/0.42
% 0.19/0.42 Here is a proof with depth 1, length 18 :
% 0.19/0.42 % SZS output start Refutation
% See solution above
% 0.19/0.42 Formulae used in the proof : pel46 pel46_1 pel46_2 pel46_3
% 0.19/0.42
%------------------------------------------------------------------------------