TSTP Solution File: SYN063+1 by Otter---3.3

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Otter---3.3
% Problem  : SYN063+1 : TPTP v8.1.0. Released v2.0.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : otter-tptp-script %s

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Wed Jul 27 13:23:27 EDT 2022

% Result   : Theorem 1.63s 1.86s
% Output   : Refutation 1.63s
% Verified : 
% SZS Type : Refutation
%            Derivation depth      :    3
%            Number of leaves      :    3
% Syntax   : Number of clauses     :    6 (   4 unt;   1 nHn;   5 RR)
%            Number of literals    :   10 (   0 equ;   3 neg)
%            Maximal clause size   :    4 (   1 avg)
%            Maximal term depth    :    1 (   1 avg)
%            Number of predicates  :    2 (   1 usr;   1 prp; 0-1 aty)
%            Number of functors    :    2 (   2 usr;   2 con; 0-0 aty)
%            Number of variables   :    2 (   2 sgn)

% Comments : 
%------------------------------------------------------------------------------
cnf(1,axiom,
    ( big_p(A)
    | ~ big_p(a)
    | big_p(B)
    | big_p(c) ),
    file('SYN063+1.p',unknown),
    [] ).

cnf(2,plain,
    ( big_p(c)
    | ~ big_p(a) ),
    inference(factor_simp,[status(thm)],[inference(factor_simp,[status(thm)],[inference(copy,[status(thm)],[1])])]),
    [iquote('copy,1,factor_simp,factor_simp')] ).

cnf(4,axiom,
    ~ big_p(c),
    file('SYN063+1.p',unknown),
    [] ).

cnf(5,axiom,
    big_p(a),
    file('SYN063+1.p',unknown),
    [] ).

cnf(6,plain,
    big_p(c),
    inference(hyper,[status(thm)],[5,2]),
    [iquote('hyper,5,2')] ).

cnf(7,plain,
    $false,
    inference(binary,[status(thm)],[6,4]),
    [iquote('binary,6.1,4.1')] ).

%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SYN063+1 : TPTP v8.1.0. Released v2.0.0.
% 0.00/0.12  % Command  : otter-tptp-script %s
% 0.12/0.33  % Computer : n017.cluster.edu
% 0.12/0.33  % Model    : x86_64 x86_64
% 0.12/0.33  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.33  % Memory   : 8042.1875MB
% 0.12/0.33  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.12/0.33  % CPULimit : 300
% 0.12/0.33  % WCLimit  : 300
% 0.12/0.33  % DateTime : Wed Jul 27 10:42:18 EDT 2022
% 0.12/0.33  % CPUTime  : 
% 1.63/1.86  ----- Otter 3.3f, August 2004 -----
% 1.63/1.86  The process was started by sandbox on n017.cluster.edu,
% 1.63/1.86  Wed Jul 27 10:42:18 2022
% 1.63/1.86  The command was "./otter".  The process ID is 30610.
% 1.63/1.86  
% 1.63/1.86  set(prolog_style_variables).
% 1.63/1.86  set(auto).
% 1.63/1.86     dependent: set(auto1).
% 1.63/1.86     dependent: set(process_input).
% 1.63/1.86     dependent: clear(print_kept).
% 1.63/1.86     dependent: clear(print_new_demod).
% 1.63/1.86     dependent: clear(print_back_demod).
% 1.63/1.86     dependent: clear(print_back_sub).
% 1.63/1.86     dependent: set(control_memory).
% 1.63/1.86     dependent: assign(max_mem, 12000).
% 1.63/1.86     dependent: assign(pick_given_ratio, 4).
% 1.63/1.86     dependent: assign(stats_level, 1).
% 1.63/1.86     dependent: assign(max_seconds, 10800).
% 1.63/1.86  clear(print_given).
% 1.63/1.86  
% 1.63/1.86  formula_list(usable).
% 1.63/1.86  -((all X (big_p(a)& (big_p(X)->big_p(b))->big_p(c)))<-> (all X1 ((-big_p(a)|big_p(X1)|big_p(c))& (-big_p(a)| -big_p(b)|big_p(c))))).
% 1.63/1.86  end_of_list.
% 1.63/1.86  
% 1.63/1.86  -------> usable clausifies to:
% 1.63/1.86  
% 1.63/1.86  list(usable).
% 1.63/1.86  0 [] big_p(X)| -big_p(a)|big_p(X1)|big_p(c).
% 1.63/1.86  0 [] -big_p(b)| -big_p(a)|big_p(c).
% 1.63/1.86  0 [] big_p(a).
% 1.63/1.86  0 [] -big_p($c1)|big_p(b)| -big_p($c2).
% 1.63/1.86  0 [] -big_p(c).
% 1.63/1.86  end_of_list.
% 1.63/1.86  
% 1.63/1.86  SCAN INPUT: prop=0, horn=0, equality=0, symmetry=0, max_lits=4.
% 1.63/1.86  
% 1.63/1.86  This is a non-Horn set without equality.  The strategy will
% 1.63/1.86  be ordered hyper_res, unit deletion, and factoring, with
% 1.63/1.86  satellites in sos and with nuclei in usable.
% 1.63/1.86  
% 1.63/1.86     dependent: set(hyper_res).
% 1.63/1.86     dependent: set(factor).
% 1.63/1.86     dependent: set(unit_deletion).
% 1.63/1.86  
% 1.63/1.86  ------------> process usable:
% 1.63/1.86  ** KEPT (pick-wt=4): 2 [copy,1,factor_simp,factor_simp] big_p(c)| -big_p(a).
% 1.63/1.86    Following clause subsumed by 2 during input processing: 0 [] -big_p(b)| -big_p(a)|big_p(c).
% 1.63/1.86  ** KEPT (pick-wt=6): 3 [] -big_p($c1)|big_p(b)| -big_p($c2).
% 1.63/1.86  ** KEPT (pick-wt=2): 4 [] -big_p(c).
% 1.63/1.86  
% 1.63/1.86  ------------> process sos:
% 1.63/1.86  ** KEPT (pick-wt=2): 5 [] big_p(a).
% 1.63/1.86  
% 1.63/1.86  ======= end of input processing =======
% 1.63/1.86  
% 1.63/1.86  =========== start of search ===========
% 1.63/1.86  
% 1.63/1.86  -------- PROOF -------- 
% 1.63/1.86  
% 1.63/1.86  ----> UNIT CONFLICT at   0.00 sec ----> 7 [binary,6.1,4.1] $F.
% 1.63/1.86  
% 1.63/1.86  Length of proof is 2.  Level of proof is 2.
% 1.63/1.86  
% 1.63/1.86  ---------------- PROOF ----------------
% 1.63/1.86  % SZS status Theorem
% 1.63/1.86  % SZS output start Refutation
% See solution above
% 1.63/1.86  ------------ end of proof -------------
% 1.63/1.86  
% 1.63/1.86  
% 1.63/1.86  Search stopped by max_proofs option.
% 1.63/1.86  
% 1.63/1.86  
% 1.63/1.86  Search stopped by max_proofs option.
% 1.63/1.86  
% 1.63/1.86  ============ end of search ============
% 1.63/1.86  
% 1.63/1.86  -------------- statistics -------------
% 1.63/1.86  clauses given                  1
% 1.63/1.86  clauses generated              1
% 1.63/1.86  clauses kept                   5
% 1.63/1.86  clauses forward subsumed       1
% 1.63/1.86  clauses back subsumed          0
% 1.63/1.86  Kbytes malloced              976
% 1.63/1.86  
% 1.63/1.86  ----------- times (seconds) -----------
% 1.63/1.86  user CPU time          0.00          (0 hr, 0 min, 0 sec)
% 1.63/1.86  system CPU time        0.00          (0 hr, 0 min, 0 sec)
% 1.63/1.86  wall-clock time        1             (0 hr, 0 min, 1 sec)
% 1.63/1.86  
% 1.63/1.86  That finishes the proof of the theorem.
% 1.63/1.86  
% 1.63/1.86  Process 30610 finished Wed Jul 27 10:42:19 2022
% 1.63/1.86  Otter interrupted
% 1.63/1.86  PROOF FOUND
%------------------------------------------------------------------------------