TSTP Solution File: SWW469_1 by Twee---2.4.2
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%------------------------------------------------------------------------------
% File : Twee---2.4.2
% Problem : SWW469_1 : TPTP v8.1.2. Released v5.3.0.
% Transfm : none
% Format : tptp:raw
% Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% Computer : n002.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Fri Sep 1 00:55:01 EDT 2023
% Result : Theorem 0.13s 0.39s
% Output : Proof 0.13s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.13/0.13 % Problem : SWW469_1 : TPTP v8.1.2. Released v5.3.0.
% 0.13/0.14 % Command : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.35 % Computer : n002.cluster.edu
% 0.13/0.35 % Model : x86_64 x86_64
% 0.13/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35 % Memory : 8042.1875MB
% 0.13/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35 % CPULimit : 300
% 0.13/0.35 % WCLimit : 300
% 0.13/0.35 % DateTime : Sun Aug 27 21:43:19 EDT 2023
% 0.13/0.36 % CPUTime :
% 0.13/0.39 Command-line arguments: --no-flatten-goal
% 0.13/0.39
% 0.13/0.39 % SZS status Theorem
% 0.13/0.39
% 0.13/0.39 % SZS output start Proof
% 0.13/0.39 Take the following subset of the input axioms:
% 0.13/0.39 tff(type, type, state: $tType).
% 0.13/0.39 tff(type, type, hoare_1310879719gleton: $i).
% 0.13/0.39 tff(conj_1, conjecture, ![T: state]: ~![S: $i]: S=T).
% 0.13/0.40 tff(fact_0_state__not__singleton__def, axiom, hoare_1310879719gleton <=> ?[S2: state, T2: state]: S2!=T2).
% 0.13/0.40
% 0.13/0.40 Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.13/0.40 http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.13/0.40 We repeatedly replace C & s=t => u=v by the two clauses:
% 0.13/0.40 fresh(y, y, x1...xn) = u
% 0.13/0.40 C => fresh(s, t, x1...xn) = v
% 0.13/0.40 where fresh is a fresh function symbol and x1..xn are the free
% 0.13/0.40 variables of u and v.
% 0.13/0.40 A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.13/0.40 input problem has no model of domain size 1).
% 0.13/0.40
% 0.13/0.40 The encoding turns the above axioms into the following unit equations and goals:
% 0.13/0.40
% 0.13/0.40 Axiom 1 (conj_1): X = t.
% 0.13/0.40
% 0.13/0.40 Goal 1 (fact_0_state__not__singleton__def_1): tuple(s, hoare_1310879719gleton) = tuple(t2, true).
% 0.13/0.40 Proof:
% 0.13/0.40 tuple(s, hoare_1310879719gleton)
% 0.13/0.40 = { by axiom 1 (conj_1) }
% 0.13/0.40 tuple(t, hoare_1310879719gleton)
% 0.13/0.40 = { by axiom 1 (conj_1) R->L }
% 0.13/0.40 tuple(t2, hoare_1310879719gleton)
% 0.13/0.40 = { by axiom 1 (conj_1) }
% 0.13/0.40 tuple(t2, t)
% 0.13/0.40 = { by axiom 1 (conj_1) R->L }
% 0.13/0.40 tuple(t2, true)
% 0.13/0.40 % SZS output end Proof
% 0.13/0.40
% 0.13/0.40 RESULT: Theorem (the conjecture is true).
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