TSTP Solution File: SWV818-1 by Otter---3.3
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%------------------------------------------------------------------------------
% File : Otter---3.3
% Problem : SWV818-1 : TPTP v8.1.0. Released v4.1.0.
% Transfm : none
% Format : tptp:raw
% Command : otter-tptp-script %s
% Computer : n008.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Wed Jul 27 13:21:37 EDT 2022
% Result : Unsatisfiable 1.75s 1.92s
% Output : Refutation 1.75s
% Verified :
% SZS Type : Refutation
% Derivation depth : 3
% Number of leaves : 2
% Syntax : Number of clauses : 6 ( 6 unt; 0 nHn; 4 RR)
% Number of literals : 6 ( 5 equ; 3 neg)
% Maximal clause size : 1 ( 1 avg)
% Maximal term depth : 1 ( 1 avg)
% Number of predicates : 2 ( 0 usr; 1 prp; 0-2 aty)
% Number of functors : 3 ( 3 usr; 3 con; 0-0 aty)
% Number of variables : 2 ( 2 sgn)
% Comments :
%------------------------------------------------------------------------------
cnf(1,axiom,
v_s != v_t,
file('SWV818-1.p',unknown),
[] ).
cnf(2,plain,
v_t != v_s,
inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[1])]),
[iquote('copy,1,flip.1')] ).
cnf(6,axiom,
A = v_ta,
file('SWV818-1.p',unknown),
[] ).
cnf(7,plain,
v_ta = A,
inference(flip,[status(thm),theory(equality)],[inference(copy,[status(thm)],[6])]),
[iquote('copy,6,flip.1')] ).
cnf(8,plain,
v_ta != v_s,
inference(para_from,[status(thm),theory(equality)],[6,2]),
[iquote('para_from,6.1.1,2.1.1')] ).
cnf(9,plain,
$false,
inference(binary,[status(thm)],[8,7]),
[iquote('binary,8.1,7.1')] ).
%------------------------------------------------------------------------------
%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12 % Problem : SWV818-1 : TPTP v8.1.0. Released v4.1.0.
% 0.07/0.13 % Command : otter-tptp-script %s
% 0.14/0.35 % Computer : n008.cluster.edu
% 0.14/0.35 % Model : x86_64 x86_64
% 0.14/0.35 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.35 % Memory : 8042.1875MB
% 0.14/0.35 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.35 % CPULimit : 300
% 0.14/0.35 % WCLimit : 300
% 0.14/0.35 % DateTime : Wed Jul 27 05:56:23 EDT 2022
% 0.14/0.35 % CPUTime :
% 1.75/1.92 ----- Otter 3.3f, August 2004 -----
% 1.75/1.92 The process was started by sandbox2 on n008.cluster.edu,
% 1.75/1.92 Wed Jul 27 05:56:23 2022
% 1.75/1.92 The command was "./otter". The process ID is 19922.
% 1.75/1.92
% 1.75/1.92 set(prolog_style_variables).
% 1.75/1.92 set(auto).
% 1.75/1.92 dependent: set(auto1).
% 1.75/1.92 dependent: set(process_input).
% 1.75/1.92 dependent: clear(print_kept).
% 1.75/1.92 dependent: clear(print_new_demod).
% 1.75/1.92 dependent: clear(print_back_demod).
% 1.75/1.92 dependent: clear(print_back_sub).
% 1.75/1.92 dependent: set(control_memory).
% 1.75/1.92 dependent: assign(max_mem, 12000).
% 1.75/1.92 dependent: assign(pick_given_ratio, 4).
% 1.75/1.92 dependent: assign(stats_level, 1).
% 1.75/1.92 dependent: assign(max_seconds, 10800).
% 1.75/1.92 clear(print_given).
% 1.75/1.92
% 1.75/1.92 list(usable).
% 1.75/1.92 0 [] A=A.
% 1.75/1.92 0 [] c_Code__Evaluation_Otracing(V_s,V_x,T_a)=V_x.
% 1.75/1.92 0 [] c_Code__Evaluation_Otracing(v_s,v_x,t_a)=v_x.
% 1.75/1.92 0 [] v_s!=v_t.
% 1.75/1.92 0 [] V_s=v_ta.
% 1.75/1.92 end_of_list.
% 1.75/1.92
% 1.75/1.92 SCAN INPUT: prop=0, horn=1, equality=1, symmetry=0, max_lits=1.
% 1.75/1.92
% 1.75/1.92 All clauses are units, and equality is present; the
% 1.75/1.92 strategy will be Knuth-Bendix with positive clauses in sos.
% 1.75/1.92
% 1.75/1.92 dependent: set(knuth_bendix).
% 1.75/1.92 dependent: set(anl_eq).
% 1.75/1.92 dependent: set(para_from).
% 1.75/1.92 dependent: set(para_into).
% 1.75/1.92 dependent: clear(para_from_right).
% 1.75/1.92 dependent: clear(para_into_right).
% 1.75/1.92 dependent: set(para_from_vars).
% 1.75/1.92 dependent: set(eq_units_both_ways).
% 1.75/1.92 dependent: set(dynamic_demod_all).
% 1.75/1.92 dependent: set(dynamic_demod).
% 1.75/1.92 dependent: set(order_eq).
% 1.75/1.92 dependent: set(back_demod).
% 1.75/1.92 dependent: set(lrpo).
% 1.75/1.92
% 1.75/1.92 ------------> process usable:
% 1.75/1.92 ** KEPT (pick-wt=3): 2 [copy,1,flip.1] v_t!=v_s.
% 1.75/1.92
% 1.75/1.92 ------------> process sos:
% 1.75/1.92 ** KEPT (pick-wt=3): 3 [] A=A.
% 1.75/1.92 ** KEPT (pick-wt=6): 4 [] c_Code__Evaluation_Otracing(A,B,C)=B.
% 1.75/1.92 ---> New Demodulator: 5 [new_demod,4] c_Code__Evaluation_Otracing(A,B,C)=B.
% 1.75/1.92 Following clause subsumed by 3 during input processing: 0 [demod,5] v_x=v_x.
% 1.75/1.92 ** KEPT (pick-wt=3): 6 [] A=v_ta.
% 1.75/1.92 Following clause subsumed by 3 during input processing: 0 [copy,3,flip.1] A=A.
% 1.75/1.92 >>>> Starting back demodulation with 5.
% 1.75/1.92 ** KEPT (pick-wt=3): 7 [copy,6,flip.1] v_ta=A.
% 1.75/1.92 Following clause subsumed by 6 during input processing: 0 [copy,7,flip.1] A=v_ta.
% 1.75/1.92
% 1.75/1.92 ======= end of input processing =======
% 1.75/1.92
% 1.75/1.92 =========== start of search ===========
% 1.75/1.92
% 1.75/1.92 -------- PROOF --------
% 1.75/1.92
% 1.75/1.92 ----> UNIT CONFLICT at 0.00 sec ----> 9 [binary,8.1,7.1] $F.
% 1.75/1.92
% 1.75/1.92 Length of proof is 3. Level of proof is 2.
% 1.75/1.92
% 1.75/1.92 ---------------- PROOF ----------------
% 1.75/1.92 % SZS status Unsatisfiable
% 1.75/1.92 % SZS output start Refutation
% See solution above
% 1.75/1.92 ------------ end of proof -------------
% 1.75/1.92
% 1.75/1.92
% 1.75/1.92 Search stopped by max_proofs option.
% 1.75/1.92
% 1.75/1.92
% 1.75/1.92 Search stopped by max_proofs option.
% 1.75/1.92
% 1.75/1.92 ============ end of search ============
% 1.75/1.92
% 1.75/1.92 -------------- statistics -------------
% 1.75/1.92 clauses given 2
% 1.75/1.92 clauses generated 1
% 1.75/1.92 clauses kept 6
% 1.75/1.92 clauses forward subsumed 3
% 1.75/1.92 clauses back subsumed 0
% 1.75/1.92 Kbytes malloced 976
% 1.75/1.92
% 1.75/1.92 ----------- times (seconds) -----------
% 1.75/1.92 user CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.75/1.92 system CPU time 0.00 (0 hr, 0 min, 0 sec)
% 1.75/1.92 wall-clock time 2 (0 hr, 0 min, 2 sec)
% 1.75/1.92
% 1.75/1.92 That finishes the proof of the theorem.
% 1.75/1.92
% 1.75/1.92 Process 19922 finished Wed Jul 27 05:56:25 2022
% 1.75/1.92 Otter interrupted
% 1.75/1.92 PROOF FOUND
%------------------------------------------------------------------------------