TSTP Solution File: SWV179+1 by Twee---2.4.2

View Problem - Process Solution

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% File     : Twee---2.4.2
% Problem  : SWV179+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof

% Computer : n017.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 300s
% DateTime : Thu Aug 31 23:02:53 EDT 2023

% Result   : Theorem 0.20s 0.61s
% Output   : Proof 0.20s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.07/0.12  % Problem  : SWV179+1 : TPTP v8.1.2. Bugfixed v3.3.0.
% 0.07/0.13  % Command  : parallel-twee %s --tstp --conditional-encoding if --smaller --drop-non-horn --give-up-on-saturation --explain-encoding --formal-proof
% 0.13/0.35  % Computer : n017.cluster.edu
% 0.13/0.35  % Model    : x86_64 x86_64
% 0.13/0.35  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.35  % Memory   : 8042.1875MB
% 0.13/0.35  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.35  % CPULimit : 300
% 0.13/0.35  % WCLimit  : 300
% 0.13/0.35  % DateTime : Tue Aug 29 08:19:13 EDT 2023
% 0.13/0.35  % CPUTime  : 
% 0.20/0.61  Command-line arguments: --flip-ordering --lhs-weight 1 --depth-weight 60 --distributivity-heuristic
% 0.20/0.61  
% 0.20/0.61  % SZS status Theorem
% 0.20/0.61  
% 0.20/0.61  % SZS output start Proof
% 0.20/0.61  Take the following subset of the input axioms:
% 0.20/0.62    fof(cl5_nebula_init_0071, conjecture, (leq(n0, pv68) & (leq(pv68, n4) & (![A2]: ((leq(n0, A2) & leq(A2, n135299)) => ![B]: ((leq(n0, B) & leq(B, n4)) => a_select3(q_init, A2, B)=init)) & (![C]: ((leq(n0, C) & leq(C, n4)) => a_select3(center_init, C, n0)=init) & (![D]: ((leq(n0, D) & leq(D, n4)) => a_select2(muold_init, D)=init) & (![E]: ((leq(n0, E) & leq(E, pred(pv68))) => a_select2(rhoold_init, E)=init) & (![F]: ((leq(n0, F) & leq(F, n4)) => a_select2(mu_init, F)=init) & (![G]: ((leq(n0, G) & leq(G, n4)) => a_select2(rho_init, G)=init) & ![H]: ((leq(n0, H) & leq(H, n4)) => a_select2(sigma_init, H)=init))))))))) => a_select2(rho_init, pv68)=init).
% 0.20/0.62  
% 0.20/0.62  Now clausify the problem and encode Horn clauses using encoding 3 of
% 0.20/0.62  http://www.cse.chalmers.se/~nicsma/papers/horn.pdf.
% 0.20/0.62  We repeatedly replace C & s=t => u=v by the two clauses:
% 0.20/0.62    fresh(y, y, x1...xn) = u
% 0.20/0.62    C => fresh(s, t, x1...xn) = v
% 0.20/0.62  where fresh is a fresh function symbol and x1..xn are the free
% 0.20/0.62  variables of u and v.
% 0.20/0.62  A predicate p(X) is encoded as p(X)=true (this is sound, because the
% 0.20/0.62  input problem has no model of domain size 1).
% 0.20/0.62  
% 0.20/0.62  The encoding turns the above axioms into the following unit equations and goals:
% 0.20/0.62  
% 0.20/0.62  Axiom 1 (cl5_nebula_init_0071): leq(n0, pv68) = true3.
% 0.20/0.62  Axiom 2 (cl5_nebula_init_0071_1): leq(pv68, n4) = true3.
% 0.20/0.62  Axiom 3 (cl5_nebula_init_0071_8): fresh44(X, X, Y) = a_select2(rho_init, Y).
% 0.20/0.62  Axiom 4 (cl5_nebula_init_0071_8): fresh43(X, X, Y) = init.
% 0.20/0.62  Axiom 5 (cl5_nebula_init_0071_8): fresh44(leq(n0, X), true3, X) = fresh43(leq(X, n4), true3, X).
% 0.20/0.62  
% 0.20/0.62  Goal 1 (cl5_nebula_init_0071_2): a_select2(rho_init, pv68) = init.
% 0.20/0.62  Proof:
% 0.20/0.62    a_select2(rho_init, pv68)
% 0.20/0.62  = { by axiom 3 (cl5_nebula_init_0071_8) R->L }
% 0.20/0.62    fresh44(true3, true3, pv68)
% 0.20/0.62  = { by axiom 1 (cl5_nebula_init_0071) R->L }
% 0.20/0.62    fresh44(leq(n0, pv68), true3, pv68)
% 0.20/0.62  = { by axiom 5 (cl5_nebula_init_0071_8) }
% 0.20/0.62    fresh43(leq(pv68, n4), true3, pv68)
% 0.20/0.62  = { by axiom 2 (cl5_nebula_init_0071_1) }
% 0.20/0.62    fresh43(true3, true3, pv68)
% 0.20/0.62  = { by axiom 4 (cl5_nebula_init_0071_8) }
% 0.20/0.62    init
% 0.20/0.62  % SZS output end Proof
% 0.20/0.62  
% 0.20/0.62  RESULT: Theorem (the conjecture is true).
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